Find the product of the following: 5 a 2 - 4 b 2 1 5 a - 1 4 b

We have 5 a 2 - 4 b 2 1 5 a - 1 4 b = 5 a 2 1 5 a - 1 4 b - 4 b 2 1 5 a - 1 4 b = 5 a 3 5 - 5 a 2 b 4 - 4 a b 2 5 + 4 b 3 4 = a 3 - 5 a 2 b 4 - 4 a b 2 5 + b 3 Therefore, the product of the given binomials is a 3 - 5 a 2 b 4 - 4 a b 2 5 + b 3

Find the product of the following: 4 a + 3 b 5 3 a - 4 b 5

We have 4 a + 3 b 5 3 a - 4 b 5 = 4 a 3 a - 4 b 5 + 3 b 5 3 a - 4 b 5 = 12 a 2 - 16 a b 5 + 9 a b 5 - 12 b 2 25 = 12 a 2 - 7 a b 5 - 12 b 2 25 Therefore, the product of the given binomials is 12 a 2 - 7 a b 5 - 12 b 2 25

Find the product of the following: x 2 - x 2 3 y 2 9 - y 7

We have x 2 - x 2 3 y 2 9 - y 7 = x 2 y 2 9 - y 7 - x 2 3 y 2 9 - y 7 = x y 2 18 - x y 14 - x 2 y 2 27 + x 2 y 21 = - 1 14 x y + 1 21 x 2 y + 1 18 x y 2 - 1 27 x 2 y 2 Therefore, the product of the given binomials is - 1 14 x y + 1 21 x 2 y + 1 18 x y 2 - 1 27 x 2 y 2

E M B I B E

Number Magic a textbook of Mathematics 8>Chapter 16 - Algebraic Expressions and Identities>EXERCISE

Monica Capoor Solutions for Chapter: Algebraic Expressions and Identities, Exercise 7: EXERCISE

Author:Monica Capoor

Monica Capoor Mathematics Solutions for Exercise - Monica Capoor Solutions for Chapter: Algebraic Expressions and Identities, Exercise 7: EXERCISE

Attempt the practice questions on Chapter 16: Algebraic Expressions and Identities, Exercise 7: EXERCISE with hints and solutions to strengthen your understanding. Number Magic a textbook of Mathematics 8 solutions are prepared by Experienced Embibe Experts.