Neha Tyagi and Amit Rastogi Solutions for Chapter: Statistics and Probability, Exercise 2: Exercise

Apoorv throws two dice once and computes the product of the numbers appearing on the dice. Peehu throws one die and squares the number that appears on it. Who has the better chance of getting the number 36? Why?

When we toss a coin, there are two possible outcomes-head or tail. Therefore, the probability of each outcome is $\frac{1}{2}.$ Justify your answer.

A student says that, if you throw a die, it will show up 1 or not 1. Therefore, the probability of getting 1 and the probability of getting not 1 each is equal to $\frac{1}{2}.$ Is this correct? Give reasons.

I toss three coins together. The possible outcomes are no heads, 1 head, 2 head and 3 heads, So, I say that probability of no heads is $\frac{1}{4}.$ What is wrong with this conclusion?

If you toss a coin $6$ times and it comes down heads on each occasion, can you say that the probability of getting a head is $1$? Given reason. 

Sushma tosses a coin$3$ times and gets tail each time. Do you think that the outcome of next toss will be a tail? Give reasons.

If I toss a coin 3 times and get head each time, should I expect a tail to have a higher chance in the 4th toss? Give reason in support of your answer.

A bag contains slips numbered from 1 to 100. If Fatima chooses a slip at random from the bag, it will either be an odd number or an even number. Since, this situation has only two possible outcomes, so the probability of each is $\frac{1}{2}.$ Justify.