There is a pentagonal shaped park as shown in Fig. Jyoti and Kavita divided it in two different ways. Find the area of this park using both ways. Can you suggest some another way of finding its areas?

A pentagonal park is given below: Jyoti and Kavita divided it in two different ways. (i) Jyoti divided is into two trapeziums as shown below: It is clear that the park is divided in two equal trapeziums whose parallel sides are 30 m and 15 m . And, the distance between the two parallel lines: 15 2 = 7 . 5 m Area of the park = 2 × ( Area of a trapazium ) = 2 × 1 2 × ( 30 + 15 ) × ( 7 . 5 ) = 337 . 5 m 2 Kavita divided the park into a rectangle and a triangle, as shown in the figure. Here, the height of the triangle = 30 - 15 = 15 m In Kavita diagram, Area of Trapezium = Area of square + Area of triangle. = ( 15 × 15 ) + 1 2 × 15 × 15 = 225 + 112 . 5 = 337 . 5 m 2 One more way to find the area of the figure: Diagram make into following as Produce D F to G such that A G D C is rectangle and A G F is Right angled triangle. Now Area of the figure = 2 × (Area of rectangle A G D C - Area of triangle A G F )

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Mathematics for Class 8>Chapter 20 - Mensuration-I (Area of a Trapezium and a Polygon)>EXERCISE

R. D. Sharma Solutions for Chapter: Mensuration-I (Area of a Trapezium and a Polygon), Exercise 3: EXERCISE

Author:R. D. Sharma

R. D. Sharma Mathematics Solutions for Exercise - R. D. Sharma Solutions for Chapter: Mensuration-I (Area of a Trapezium and a Polygon), Exercise 3: EXERCISE

Attempt the practice questions on Chapter 20: Mensuration-I (Area of a Trapezium and a Polygon), Exercise 3: EXERCISE with hints and solutions to strengthen your understanding. Mathematics for Class 8 solutions are prepared by Experienced Embibe Experts.