Name: Drawing a Bar Graph
Uploaded: 2019-07-19
Duration: 5 min 41 s
Description: Do you know how to draw a bar graph? Draw the vertical and horizontal axes. Label both the axes. Watch this video for complete information on drawing a bar g...

Question

The number of persons in various age groups in a town is given in the following table:

Age group	$1 - 14$	$15 - 29$	$30 - 44$	$45 - 59$	$60 - 74$	$75 - 89$
Number of persons	$1400$	$1200$	$1100$	$1000$	$950$	$300$

Draw a bar graph to represent the above information and answer the following question:

What is the percentage of the youngest age groups over those in the oldest age groups?

Accepted Answer

We can draw the bar graph by following the given steps:

Draw a horizontal line $O X$ as $x -$ axis and vertical line $O Y$ as $y -$ axis.

We mark the horizontal axis as "Age group" and the vertical axis as "Number of persons".

Along $x -$ axis we choose the bar of uniform(equal) width, with a uniform gap between them.

Along $y -$ axis we choose $1$ big division $75 - 89$ persons.

All the bars should be of same width and same space should be left between the consecutive bars.

The graph is as follows:

Here the youngest age is $1 - 14$ years.

Number of persons in the youngest age group $= 1400$

Also, $75 - 89$ years is the oldest age groups.

Number of persons in the oldest age groups $= 300$

Hence, the youngest group has $1100$ more people than the oldest group.

Percentage of the youngest group over the oldest group

$= (\frac{1400}{300}) \times 100 = \frac{1400}{3} = 466 \frac{2}{3} %$ .

Marks	$9$	$19$	$58$	$61$	$75$
Number of students	$25$	$12$	$40$	$13$	$10$

Marks	$9$	$19$	$58$	$61$	$75$
Number of students	$25$	$12$	$40$	$13$	$10$

S K Khanuja Solutions for Chapter: Bar Graphs, Exercise 3: Exercise 66

S K Khanuja Mathematics Solutions for Exercise - S K Khanuja Solutions for Chapter: Bar Graphs, Exercise 3: Exercise 66

Questions from S K Khanuja Solutions for Chapter: Bar Graphs, Exercise 3: Exercise 66 with Hints & Solutions

Learn and Prepare for any exam you want !