Data Interpretation & Data Sufficiency For SBI, IBPS, RBI, SSC, LIC and Other Competitive Exams

Total number of candidate appeared $=600$

Number of candidate failed in at least two subjects $= 9+11+8+5 = 33$

Percentage of candidates failed in at least two subjects $= \frac{33}{600}\times 100\% = 5.5\%$

Total number of person $=1000$

Number of person who do not know any language

$=1000-(170+200+180+5+78+105+175)$

$=1000-993=7$

Required ratio $=\frac{7}{175}=\frac{1}{25}$

Hence, The correct answer is option B.

No. of surveying person $50$.

No. of person who read at least newspaper

$=8+5+12+2=27$

So, if no. of person $=$ $10000$

Then no. of person to read at least two newspaper

$=\frac{27}{50}\times 10000=5400$

A no. which is divisible by $2$ is called an even number, so this statements ($x$ is divisible by $2$) is alone sufficient to answer that is $x$ an even number and when and odd number is added in to an even number $2$, the result is always is odd no, so this statement also is alone sufficient to answer that is $x$ and even number.

Given ratio of Tanish & Shivay's age $=6:5$

 So let Tanish age $6x$ & Shivay’s age $5x$

In statement I, Tanish age$=3x$ & Danish Ages$=2x$ from this statement alone, we cannot conclude the age of Shivay.

From statement II, after $6$ years the ration of Danish age and Shivay age will be $6:7$ .

From this statement alone, we cannot conclude the age of shivay.

Now try to work on these statements we get

$$\begin{gathered} \left(5x+6\right) : (4x+6)=7:6 \\ =\frac{5x+6}{4x+6}=\frac{7}{6} \\ \mathrm{on} \mathrm{crossmultiplication} \\ 30x+36=28x+42 \\ x=3 \end{gathered}$$

So Shivay age $3\times 5=15$

So both statement I & II are needed.

From statement I, we can not conclude the answer because there is no data given with reference to men.

From statement II, it is given that $9$ men can complete the same work in $27$ days & we can find in how many days $15$ men can complete the work i.e $\frac{27\times 9}{15}\mathrm{days}=\frac{81}{5}\mathrm{days}$

Average salary of A, B, C, D, E, F = 60600

From statement I, A + E = 64500

From statement II, B + F = 52600

We have six persons in all and from the given two statements, the salary of four person(total) is given, so we can not conclude the salary of C from both the statements.

From statement I, we can write

$$\begin{gathered} \frac{1}{3}\left(x\right)+27=\frac{1}{2}x \\ \Rightarrow \frac{1}{6}x=27\Rightarrow x=162 \end{gathered}$$

(where $x$ is the three-digit no.)

So this statement is sufficient to answer the question.

From statement II, we can write

$\frac{1}{5}x=20\% of x\Rightarrow \frac{1}{5}x=\frac{1}{5}x$

This is always true.

So we can not conclude the no. from this data.

Hence, the statement I alone is sufficient to answer the question, but statement II alone is not sufficient.

For statement, I

The diameter is the diagonal of the square, so we can find the diagonal of the square by using its area. And then we can find the area of the circular field.

For statement II

Here the line joining the middle points of the opposite sides of the square is the diagonal of the circle. We can find the diagonal by using the area of the square and then can find the area of the circle. 

Hence, if the data either in statement I alone or in statement II alone are sufficient to answer the question.is correct. 

For Statement I

The Ratio of Juice : Water$=6:1$ initially

For Statement II

The new ratio becomes $8:3$ after drawing $7$ litres of mixture and adding $5$ litres of water.

Combining these statements,

$7x-7$ is the quantity of mixture after drawing $7$ litres of mixture.

Hence the ratio of Juice & Water is still $6:1$

Now

$$\begin{gathered} \frac{{\displaystyle \frac{6}{7}(7x-7)}}{{\displaystyle \frac{1}{7}(7x-7)+5}}=\frac{8}{3} \\ \Rightarrow \frac{42x-42}{7x-7+35}=\frac{8}{3} \\ \Rightarrow 126x-126=56x+28\times 8 \\ \Rightarrow 70x=224+126 \\ \Rightarrow x=\frac{350}{70}=5 \end{gathered}$$

Hence, Initial quantity of Juice$=6\times 5=30$ litres

Initial quantity of Water$=1\times 5=5$ litres

 

 

For statement I

Area of base of the cylinder$=616 {\mathrm{cm}}^2$

$\Rightarrow {\mathrm{\pi r}}^2=616$

For Statement II

Volume of cylinder$=9240 {\mathrm{cm}}^3$

$\Rightarrow {\mathrm{\pi r}}^2\mathrm{h}=9240$

Solving these two we can find the value of $r \& h$

And then we can find the curved surface area of the right circular cylinder.

For statement I

A, B, C can complete the work in $4\frac{32}{37}$ days.

For statement II 

A & B can complete in $6\frac{2}{3}$days

B & C can complete in $8\frac{2}{11}$ days

A & C can complete in $7\frac{1}{3}$ days

$2$(A+B+C)$=$$\frac{20}{3}+\frac{90}{11}+\frac{22}{3}$

Hence, on solving these two statements we can find the number of days taken by A, B, & C alone to do the work.

For statement I

Let Ms. Shalini receive Rs. $x$ as retirement funds. She gave $\left(25+10\%\right)$ to her husband & daughter, so remaining amount with Shalini $=65\%$of $x$

Now, $10\%$ of $65\%$ of $x$ $=260000$

$80x= \frac{260000\times 100\times 100}{10\times 65}=\frac{2\times 1000\times 10000}{5}=4000000$

For statement II

In this statement, all the data is in terms of percentage so the value of the fund can not be calculated.