### Contents of ESIC Upper Division Clerk (UDC) & Stenographer Phase-1

This book contains chapter-wise solutions, topic-wise solutions, exercise-wise solutions, and videos.

#### 51 Chapters

- 1. Analogy or Similarity
- 2. Classification or Differences
- 3. Series
- 4. Word Formation
- 5. Logical Sequence of Words
- 6. Coding and Decoding
- 7. Ranking Test
- 8. Spatial Orientation
- 9. Relationship Concept
- 10. Sitting Arrangement
- 11. Inserting the Missing Character
- 12. Clock and Calendar
- 13. Mathematical Operations
- 14. Mathematical Reasoning
- 15. Venn Diagram
- 16. Spatial Visualisation
- 17. Analytical Reasoning
- 18. Non-Verbal Intelligence
- 19. History of India and Freedom Struggle
- 20. Geography:World and India
- 21. Indian Polity and Constitution
- 22. Indian Economy
- 23. India and World
- 24. General Science
- 25. Number System
- 26. Fractions
- 27. HCF and LCM
- 28. Square Root, Cube Root and Surds
- 29. Fundamental Arithmetical Operations
- 30. Ratio and Proportion
- 31. Average
- 32. Percentage
- 33. Profit, Loss and Discount
- 34. Simple and Compound Interest
- 35. Time and Work
- 36. Time, Speed and Distance
- 37. Mensuration
- 38. Data Interpretation
- 39. Spotting Errors
- 40. Sentence Completion (Fillers)
- 41. Sentence Improvement
- 42. Rearrangement of Sentences
- 43. Idioms and Phrases
- 44. One Word Substitution
- 45. Synonyms & Antonyms
- 46. Spellings
- 47. Direct and Indirect Speech
- 48. Active and Passive Voice
- 49. Cloze Test
- 50. Comprehension
- 51. Practice Set

#### 4 Topics

Word Analogy

Letter Analogy

Number Analogy

Mixed Analogy

#### 3 Topics

Word Classification

Letters Classification

Numbers Classification

#### 2 Topics

Number Series

Alphabet Series

#### 2 Topics

Type 1: Word Formation using Letters from a Given Word

Type 2: Word Formation by Unscrambling Letters

#### 1 Topics

Logical Sequence off Words

#### 4 Topics

Letter Coding

Number/Symbol Coding

Substitution Coding

Message Coding

#### 2 Topics

Based on Comparison

Based on Position(Top/Left or Right/ Bottom)

#### 3 Topics

To Find the Direction

To Find the Distance

To Find both Distance and Direction

#### 2 Topics

Conversation Based

Relation Puzzle Based

#### 2 Topics

Arrangement in Linear Pattern

Circular Arrangement

#### 1 Topics

Inserting the Missing Character

#### 2 Topics

Clock

Calendar

#### 4 Topics

Symbol Problem Solving by Substitution

Balancing the Expression

Interchange of Signs

Trick Based

#### 1 Topics

Mathematical Reasoning

#### 2 Topics

Relation Based Venn Diagram

Analysis Based Venn Diagram

#### 2 Topics

Cube

Dice

#### 3 Topics

Syllogism

Statement and Conclusions

Statement and Assumptions

#### 11 Topics

Analogy

Classification

Series

Mirror Image

Water Image

Paper Folding

Paper Cutting

Figure Completion

Formation of Figures

Embedded Figures

Counting of Figures

#### 4 Topics

Ancient India

Medieval History

Modern India

Art and Culture

#### 16 Topics

Universe

Earth

Rocks

Earthquakes

Volcanism

Landforms

Plateaus

Atmosphere

Important Canals of the World

Deepest Point of Oceans

Industrial Cities

India: Size and Location

Physical Features of India (Physiography)

Drainage System of India

Climate, Natural Vegetation and Wildlife

Environmental Issues

#### 5 Topics

Framing of the Indian Constitution

Preamble

Fundamental Rights

Directive Principles of State Policy

Union

#### 11 Topics

Sectors of Indian Economy

Demand and Elasticity

Market and its Types

National Income

Human Development Report

Planning in India

NITI Aayog

Poverty and Unemployment

Agriculture in India

Industries in Indian Economy

Money and Banking

#### 18 Topics

First in World (Men)

First in World (Women)

First in World (Miscellaneous)

Superlatives of the World

Legislatures of the World

World Famous National Monuments of Major Countries

Official Books of Major Countries

First in India (Female)

First in India (Miscellaneous)

Superlatives in India

Books and Authors

National and International Awards/Honours

Sports

List of Important Cups and Trophies

Indian National Symbols

Defence Forces of India

Science and Technology

United Nations and other International Organisations

#### 3 Topics

Physics

Chemistry

Biology

#### 6 Topics

Face Value and Place Value of a Digit

Categories of Numbers

Different Types of Numbers

Divisibility Tests

To Find The Unit'S Place Digit of a Given Exponential

Most Important Formulae

#### 4 Topics

Types of Fraction

Decimal Fractions

Recurring Decimals

Comparison of Fraction

#### 2 Topics

HCF (Highest Common Factor)

LCM (Least Common Multiple)

#### 3 Topics

Square Root

Cube

Cube Root

#### 1 Topics

VBODMAS Rule

#### 2 Topics

Ratio

Proportion

#### 5 Topics

Cost Price (CP)

Selling Price (SP)

Profit or Gain

Loss

Discount

#### 2 Topics

Simple Interest(SI)

Compound Interest(CI)

#### 2 Topics

Important Points Related to Time and Work

Pipes and Cisterns

#### 5 Topics

Speed

Time

Distance

Average Speed

Boats and Streams

#### 4 Topics

Features of 2D-Figure

Triangle

Quadrilaterals

Features of 3D-Mensuration

#### 4 Topics

Data Table

Pie Chart

Bar Chart

Line Graph

#### 9 Topics

Article

Noun

Adjectives

Verb

Adverb

Prepositions

Conjunction

Tense

Miscellaneous Practice

#### 1 Topics

Sentence Completion (Fillers)

#### 1 Topics

Sentence Improvement

#### 1 Topics

Rearrangement of Sentences

#### 1 Topics

Idioms and Idiomatic Phrases

#### 1 Topics

One Word Substitution

#### 1 Topics

Commonly used Synonyms and Antonyms

#### 1 Topics

Direct and Indirect Speech

#### 1 Topics

Active and Passive Voice

#### 4 Topics

Practice Set-1

Practice Set-2

Practice Set-3

Practice Set-4

## Experience Tests Tailored to Match the Real Exam

## Practise Questions with Solutions from the ESIC Upper Division Clerk (UDC) & Stenographer Phase-1

- (a)Bright
- (b)Foolish
- (c)Insane
- (d)Idiot

**Hint**

Words are synonyms of each other.

**Solution:**

According to the question,

Intelligent and clever both are synonyms of each other. Similarly, dull is synonymous to foolish.

But, bright, insane, and idiot are not synonyms of dull.

- (a)Exams
- (b)Library
- (c)Reading
- (d)Chapters

**Hint**

First word is the part of the second word.

**Solution:**

A group of players constitutes a team.

Similarly, a group of books is found in a library. A collection of chapters constitutes a book. We read books and give exams.

Therefore, “Library” is the correct answer.

- (a)Music
- (b)Ears
- (c)Hear
- (d)Sound

**Hint**

Words are synonyms of each other.

**Solution:**

According to the question,

Talk and speak both are synonyms of each other. Similarly, listen is synonymous to hear.

But, music, ears, and sound are not synonyms of listen.

Therefore, this is the correct answer.

- (a)Doctor
- (b)Hospital
- (c)Chemist
- (d)Matron

**Hint**

First word is the profession of the second word.

**Solution:**

As, the education is given by the teacher.

Similarly, the treatment is done by the doctor.

But, treatment is done in hospitals. Medicine is given by chemist. Matron is the job title of a chief nurse.

- (a)$52$
- (b)$68$
- (c)$28$
- (d)$49$

**Hint**

Second Number $=$ (First Number)${}^{2}+3$.

**Solution:**

In the first pair of the given analogy, the second term is the square of first term with addition of ‘$3$’. As,

$4:19\to {4}^{2}+3=16+3=19$

Similarly, in the second pair, the second term will be square of the first term with addition of $3$’. As follows,

${7}^{2}+3=49+3=52$

Therefore, $52$ is the correct answer.

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- (a)Wood
- (b)Stone
- (c)Tree
- (d)Engine

**Hint**

Classify based on natural and artifical things.

**Solution:**

According to the question,

Wood, Stone, and Tree are the natural things. While ‘Engine’ is the artificial thing, means, it is made by man.

Therefore, engine does not belong to the group from which other options belong.

- (a)Temple
- (b)Monastery
- (c)Mosque
- (d)Church

**Hint**

Church, Mosque, Temple are places of worship.

**Solution:**

A temple is a place of worship for Hindus. A mosque is a place of worship for Muslims. A church is a place of worship for Christian.

While, monastery is a place where monks live.

Therefore, monastery does not belong to the group from which other options belong.

- (a)Tomato
- (b)Potato
- (c)Carrot
- (d)Onion

**Hint**

Identify the underground vegetable in the options.

**Solution:**

Tomatoes are grown above the ground. Whereas, Potato, Carrot, and Onion are grown underground.

Therefore, tomato does not belong to the group from which other options belong.

- (a)Email
- (b)Money Order
- (c)Speed Post
- (d)Letter

**Hint**

Three of the things here are posted from a post office.

**Solution:**

Email is the online process. While all others (Money order, Speed post, Letter) are posted in post office.

Therefore, email does not belong to the group from which other options belong.

- (a)Paper
- (b)Pencil
- (c)Pen
- (d)Stationery

**Hint**

Pen and Pencil are stationery used for writing purposes.

**Solution:**

Paper, Pen, and Pencil all are stationery items. Means here, stationery is the odd word.

Therefore, stationery does not belong to the group from which other options belong.

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- (a)$R,U$
- (b)$P,S$
- (c)$Q,T$
- (d)$U,X$

**Hint**

Letters are increasing in this series.

**Solution:**

After observing the given series,

$B,E,H,K,N,?,?$

We find that the letters increasing by 3

$B\stackrel{+3}{\to}E\stackrel{+3}{\to}H\stackrel{+3}{\to}K\stackrel{+3}{\to}N\stackrel{+3}{\to}Q\stackrel{+3}{\to}T$

Hence, option (C) is correct.

- (a)$MJK$
- (b)$LRS$
- (c)$BYZ$
- (d)$TQR$

**Hint**

Each alphabet has a difference of $3$.

**Solution:**

After observing the given series,

$DAB,GDE,JGH,?$

Comparing the letters of one combination with the others, we found that it increases by $3$.

$D\stackrel{+3}{\to}G\stackrel{+3}{\to}J\stackrel{+3}{\to}M$

$A\stackrel{+3}{\to}D\stackrel{+3}{\to}G\stackrel{+3}{\to}J$

$B\stackrel{+3}{\to}E\stackrel{+3}{\to}H\stackrel{+3}{\to}K$

Hence, option (a) is correct.

- (a)$TUD$
- (b)$DTU$
- (c)$ENO$
- (d)$FNQ$

**Hint**

Letters of each combination have a constant difference of $2$ and $1$.

**Solution:**

After observing the given series,

$NOA,PQB,RSC,?$

Comparing the letters of one combination with the others, we found that it increases by $2$ and last letter increased by $1$.

$N\stackrel{+2}{\to}P\stackrel{+2}{\to}R\stackrel{+2}{\to}T$

$O\stackrel{+2}{\to}Q\stackrel{+2}{\to}S\stackrel{+2}{\to}U$

$A\stackrel{+1}{\to}B\stackrel{+1}{\to}C\stackrel{+1}{\to}D$

Hence, option (a) is correct. i.e. $TUD$.

- (a)$M0$
- (b)$N1$
- (c)$N0$
- (d)$Q1$

**Hint**

Difference between the letters and numbers are constant.

**Solution:**

After observing the given series,

$V8,T6,R4,P2,?$

We find out that, letters are decreased by $2$and numbers are decreased by $2$

$V\stackrel{-2}{\to}T\stackrel{-2}{\to}R\stackrel{-2}{\to}P\stackrel{-2}{\to}N$

$8\stackrel{-2}{\to}6\stackrel{-2}{\to}4\stackrel{-2}{\to}2\stackrel{-2}{\to}0$

Hence, option (c) is correct.

- (a)$\mathrm{N}-12$
- (b)$\mathrm{K}-12$
- (c)$\mathrm{M}-13$
- (d)$\mathrm{L}-12$

**Hint**

Difference between the letter and number is constant.

**Solution:**

In the given series, the alphabets and the numbers are increasing by two.

Hence, according to the pattern of the series,

the correct answer is $\mathrm{L}-12$.

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- (a)S
- (b)H
- (c)C
- (d)B

**Hint**

One of the words denotes time duration.

**Solution:**

The prefix to the following word is H.

H + EAT = HEAT

H + OUR = HOUR

H + IS = HIS

H + AS = HAS

H + AT = HAT

Hence, H is the correct prefix.

- (a)A
- (b)E
- (c)B
- (d)D

**Hint**

One of the words formed means to shower.

**Solution:**

Following word formed using suffix 'E'.

HAT + E = HATE(dislike someone)

BAR + E = BARE(naked)

BAT + E = BATE(an angry mood)

PIN + E = PINE(a tree)

BATH + E = BATHE(shower)

Hence, E is the correct suffix.

- (a)Two
- (b)One
- (c)Three
- (d)More than four

**Hint**

The word that can be formed is a synonym of an animal hunt and kill for food.

**Solution:**

Using the letters E, P, R, and Y, only one word can be formed i.e. PREY.

Thus, only one word can be formed using the given letters.

- (a)None
- (b)One
- (c)Two
- (d)Three

**Hint**

Synonym of the word is impolite or bad-mannered.

**Solution:**

Using the letters E, R, D and U, only one word can be formed i.e. RUDE.

Thus, only one word can be formed using the given letters.

- (a)E
- (b)K
- (c)P
- (d)C

**Hint**

Female name of this bird is peahen.

**Solution:**

By rearranging the given letters, the word formed is “PEACOCK”.

The last letter is of the word PEACOCK is “K”.

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- (a)3, 2, 4, 1
- (b)3, 1, 2, 4
- (c)3, 1, 4, 2
- (d)3, 2, 1, 4

**Hint**

Flower is the part of the plant.

**Solution:**

The given four words in the above question are Plant, Fruit, Seed and Flower. So, we can arrange as the growing stages of a seed.

First, it is a seed which becomes a plant, then flowers come in it and in last it gives fruits.

So, the correct sequence is:

Hence, '3, 1, 4, 2' is a correct answer.

- (a)4, 3, 1, 2
- (b)4, 3, 2, 1
- (c)4, 1, 3, 2
- (d)1, 3, 2, 4

**Hint**

Butter is a milk product.

**Solution:**

We know that Cow gives milk. Then, from the milk, the curd is made and then from curd, butter is made.

So, the correct sequence is:

Hence, '4,3, 1, 2' is the correct answer.

- (a)1, 3, 4, 2
- (b)2, 1, 4, 3
- (c)2, 3, 1, 4
- (d)4, 3, 2, 1

**Hint**

The logical order represents the process of wax production.

**Solution:**

By observing the given words, we can say that these words form the sequence of producing wax. Firstly, the flowers produce nectar, which is then consumed by bees. The bees then produce honey from this nectar. Lastly, the wax is obtained from honey.

So, the correct sequence is:

Hence, '2, 3, 1, 4' is the correct answer.

- (a)1, 2, 4, 3
- (b)2, 1, 3, 4
- (c)4, 2, 3, 1
- (d)3, 1, 4, 2

**Hint**

The logical order represents the process of food production.

**Solution:**

Firstly, farmers sow seeds in the field. They water the fields by irrigation. After some time, the cultivation of crops begins, followed by the production of food such as wheat, maize, rice, etc.

So, the correct sequence is:

Hence, '1, 2, 4, 3' is the correct answer.

- (a)3, 2, 4, 1
- (b)2, 4, 1, 3
- (c)2, 3, 4, 1
- (d)2, 1, 4, 3

**Hint**

Blocks come under districts.

**Solution:**

A village is the smallest among all the given words. And the Block contains a lot of villages while a District contains lots of Blocks. The state contains lots of Districts.

So, the correct sequence is:

Hence, '2, 4, 1, 3' is the correct answer.

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- (a)TSIOM
- (b)SMIOT
- (c)SIOTM
- (d)TOIMS

**Hint**

Last letter remains same.

**Solution:**

By observing the above question, we find out that the given code is formed by replacing the position of the letters in a given word.

For eg. CRUDE is written as DCURE.

Similarly, we can write MOIST as –

Hence, SMIOT is the correct answer.

- (a)NGIFRE
- (b)GERFIN
- (c)REGNIF
- (d)NGFREI

**Hint**

Letters arranged in a specific position.

**Solution:**

By observing the above question, we find out that the given code is formed by replacing the position of the letters in a given word.

For e.g. KIDNEY is written as DNIKEY.

Similarly, FINGER can be written as –

Hence, Option 1 is the correct answer.

- (a)REOQ
- (b)MOLE
- (c)GOOE
- (d)EQOG

**Hint**

Arranged letters some places ahead in the English alphabets.

**Solution:**

The code language shown in the question is formed by shifting all the letters two places ahead in the English alphabets.

For e.g. FROM is written as HTQO.

Similarly, COME can be written as –

Hence, EQOG is the correct answer.

- (a)TYKB
- (b)SZMA
- (c)YKZB
- (d)None of the above

**Hint**

Use one-to-one coding.

**Solution:**

The above code is formed by adding 2 at the letters which are at odd place and by subtraction 2 at the letters which are at the even place.

For e.g. JUNE is written as LSPC.

Similarly, RAID can be written as –

Hence, Option 1 is the correct answer.

- (a)TSFRJ
- (b)RPFTJ
- (c)NJFTP
- (d)TSFGJ

**Hint**

Code for 'L' is 'P' and 'A' is 'F'.

**Solution:**

In the above code, a specific letter is denoted by some specific letter. For e.g. STARK is written as LBFMG and MOBILE is written as TNRSPJ.

It means we can denote these letters by –

Similarly, we can write BLAME as –

Hence, RPFTJ is the correct answer.

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- (a)Milon
- (b)Sameer
- (c)Priya
- (d)Arjun

**Hint**

Priya is older than Sam but younger than Milon that means Milon > Priya > Sam.

**Solution:**

It is given in a question that Sameer is older than Milon, but not as old as Arjun which means Sameer is younger than Arjun i.e.,

We arrange the row in ascending order.

Arjun > Sameer > Milon

It is also given in the question that Priya is older than Sam but younger than Milon i.e.

Milon > Priya > Sam

By arranging them in a meaningful order, we get

Arjun > Sameer > MIlon > Priya > Sam

So, we can say clearly that Arjun is the oldest.

Hence Option (d) is the correct answer.

- (a)Sonam
- (b)Pooja
- (c)Neha
- (d)Shivani

**Hint**

Shivani finished before Anju but after Neha that means Neha >Shivani>Anju.

**Solution:**

According to the question Sonam finished before Neha but after Pooja. So we can write,

We arrange the row in ascending order.

Pooja > Sonam > Neha

It is also given in question that Shivani finished before Anju but after Neha.

Neha > Shivani >Anju

By combining these two orders, we get

Pooja > Sonam > Neha > Shivani > Anju

So, we can say that Pooja won the race.

Hence, Pooja is the correct answer.

- (a)Akabarpur
- (b)Fatehpur
- (c)Palamu
- (d)Dhanbad

**Hint**

Dhanbad is bigger than Palamu that means Dhanbad >Palamu.

**Solution:**

We arrange the row in descending order.

It is given in the question that Akbarpur is smaller than Fatehpur and Barbanki is bigger than Fatehpur but smaller than Palamu. So, we can write it as,

Palamu > Barbanki > Fatehpur > Akbarpur

It is also given in the question that Dhanbad is bigger than Palamu. So, we can write this as –

Dhanbad > Palamu > Barbanki > Fatehpur> Akbarpur

So, we can clearly say that Dhanbad is the biggest.

Hence, Option (d) is the correct answer.

- (a)C
- (b)A
- (c)E
- (d)B

**Hint**

D is the heaviest.

**Solution:**

We arrange the row in descending order.

It is given that A is heavier than only C means A is at 4th position and C is at 5th position. And B is heavier than both E and A.

B > E >A > C.

And D is heavier than B. So, we can write –

D > B > E > A >C

So, we can say that E is sitting in the middle.

Hence, E is the correct answer.

- (a)$37$
- (b)$43$
- (c)$35$
- (d)$36$

**Hint**

$\left(\begin{array}{l}\text{Totalnumber}\\ \text{ofgirls}\end{array}\right)\text{=}\left(\begin{array}{l}\text{Rankofgirl}\\ \text{fromstart}\end{array}\right)\text{+}\left(\begin{array}{l}\text{Rankofgirl}\\ \text{fromend}\end{array}\right)-1$

**Solution:**

We can solve this easily by using the formula below –

$\left(\begin{array}{l}\text{Totalnumber}\\ \text{ofgirls}\end{array}\right)\text{=}\left(\begin{array}{l}\text{Rankofgirl}\\ \text{fromstart}\end{array}\right)\text{+}\left(\begin{array}{l}\text{Rankofgirl}\\ \text{fromend}\end{array}\right)-1$

So, total number of girls in a queue $=11+27\u20131=37$

Hence, (a) is the correct answer.

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- (a)
South

- (b)
West

- (c)East
- (d)North

**Hint**

After taking first left turn, he is facing opposite to west direction.

**Solution:**

According to the question, the boy is facing South direction. Then first left turns, he is facing East direction. After that second right turns, he is facing South direction and at last left turns, he is facing East direction.

Hence, the boy is facing East Direction.

- (a)
West

- (b)
East

- (c)South
- (d)North

**Hint**

Initially, when he turned left, he will be facing North.

**Solution:**

I was facing East from where I turned to my left and walked 12 ft, that means I was facing North direction. Then I turned towards right and walked 6 ft, that means I was facing East direction, After that I walked 6 ft in South direction and at last I walked 6 ft in the West.

The diagram of the figure can be drawn as per the question:

Clearly, I am towards north from my initial position.

- (a)
South

- (b)
North-East

- (c)
South-West

- (d)North

**Hint**

Rani is to the east of Ram.

**Solution:**

Ram is to the South of Aishwarya and to the West of Rani and Priyanka is to the South of Ram.

Drawing the figure as per the directions given:

Priyanka is towards South-West of Rani.

- (a)
North

- (b)
East

- (c)South
- (d)West

**Hint**

The college is in the north while the coffee house is in the east.

**Solution:**

According to the question.

On the four roads I have come from the South and want to go the temple. The road to the right leads me towards the coffee house while straight road leads to the college.

Here, we can see temple is towards West.

- (a)
North-East

- (b)
West

- (c)South-East
- (d)North-West

**Hint**

After ${135}^{o}$ movement, I am facing in South-East direction.

**Solution:**

Difference in degree $=$$180\xb0$ $-$ $135\xb0$ $=$ $45\xb0$

^{ }Anticlockwise.Now, following the directions as per the question. I am facing North. I turn $135\xb0$ in clockwise direction, then $180\xb0$ in anti-clockwise direction.

Now, I am facing in North-West Direction.

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- (a)Aunt
- (b)Niece
- (c)Daughter
- (d)Mother

**Hint**

Solve in reverse direction of given sentence.

**Solution:**

According to the given information in question:

Monika's father's only daughter $\to $ Monika

So, Reena is Monika’s daughter or Monika is Reena’s mother.

Hence, the correct answer is mother.

- (a)
Brother

- (b)
Cousin

- (c)Father
- (d)Son

**Hint**

Solve in reverse direction of given sentence.

**Solution:**

According to the question,

Mother's husband = Father

Father's Brother = Uncle

Uncle's son = CousinHence, the man is woman's cousin.

therefore, option 2 is correct.

- (a)
Sister

- (b)
Mother

- (c)Cousin
- (d)Either (a) or (c)

**Hint**

Lady's mother's husband is the father of the lady.

**Solution:**

According to the given information,

Lady's mother's husband = Lady's father

Lady's father's sister = Lady's auntSo, Lady's aunt is the man’s aunt.

Therefore, lady is either man’s sister or cousin.therefore, option 4 is correct.

- (a)
Mother

- (b)
Sister

- (c)Cousin
- (d)Daughter

**Hint**

Only son of woman's grandfather is the father of woman.

**Solution:**

According to the given information,

Only son of woman's grandfather = Woman's father

Man's brother's father = Man's father

So, woman's father is man's father.

Therefore, woman is man’s sister.

- (a)
Daughter

- (b)
Sister

- (c)Mother
- (d)Cousin

**Hint**

Solve in reverse direction of given sentence.

**Solution:**

Girl's father's only son = girl's brother

Grand mother of girl's brother = girl's grand mother

Only daughter-in-law of girl's grand mother = Girl's mother.

Hence, the lady is girl’s mother.

therefore, option 3 is correct.

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- (a)A and D are in front of each other
- (b)A is not between B and C
- (c)D is to the left of C
- (d)A is to the left of C

**Hint**

A can be placed towards right or left of B.

**Solution:**

According to the question,

B and C are in front of each other.

There will be two possible arrangements of these four girls around the circle. As follows,

And in both arrangements, A and D are in front of each other.

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- (a)$3$
- (b)$6$
- (c)$5$
- (d)$10$

**Hint**

$Colum{n}_{n=1,2,3}\left(\left(Cel{l}_{1}\times Cel{l}_{2}\right)+Cel{l}_{3}\right)=Cel{l}_{4}$

**Solution:**

By observing the given question it is found out that the number given in the last cell of each column vertically is being calculated as the following pattern of

$Colum{n}_{n=1,2,3}\left(\left(Cel{l}_{1}\times Cel{l}_{2}\right)+Cel{l}_{3}\right)=Cel{l}_{4}$

$5\times 6+4=34$

$4\times 7+2=30$

Therefore, the last column is

$3\times 8+?=30$

$?=30-24$

$?=6$

- (a)$7$
- (b)$10$
- (c)$8$
- (d)$13$

**Hint**

The sum of numbers in each column is constant.

**Solution:**

By observing the pattern of given question we have find out that sum of numbers of each column individually is equal to $20$. Hence for column$1$ and column$2$ we have:

$13+6+1=20$

$6+8+6=20$

Therefore, equating the value of $20$ to the sum of the values in the last column we get:

$4+6+?=20$

$?=10$

- (a)$54$
- (b)$50$
- (c)$49$
- (d)$45$

**Hint**

For each row, the middle element is the product of the first and last elements.

**Solution:**

By observing the pattern, we find that the number given in a given row, the second cell is the product of the first and third cells.

$Ro{w}_{cell2}=Ro{w}_{cell1}\times Ro{w}_{cell3}$

$15=3\times 5$

$35=5\times 7$

$?=9\times 5$

$?=45$

- (a)$54$
- (b)$18$
- (c)$36$
- (d)$24$

**Hint**

The sum of the numbers outside the circle is equal to the number inside the circle.

**Solution:**

According to the diagram given, we can observe that the sum of the numbers outside the circle is equal to the number inside the circle:

$Circl{e}_{1}=4+3+2+1=10$

$Circl{e}_{2}=5+4+3+2=14$

Thus, we can say that the value of the question mark in the third pattern is:

$Circl{e}_{3}=4+5+6+3=18$

- (a)$9$
- (b)$6$
- (c)$15$
- (d)$14$

**Hint**

The sum of the elements of each row is constant.

**Solution:**

According to the pattern given, we find relationship between the numbers by various mathematical operations. In this case we add the numbers:

$Ro{w}_{1}=4+9+2=15$

$Ro{w}_{2}=3+5+7=15$

As we can see that the sum of each row results in $15$.

Hence, the value of the question mark is

$Ro{w}_{3}=8+1+?$

$15=\left(8+1+?\right)$

$\left(9+?\right)=15$

$?=6$

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- (a)$8:30\mathrm{am}$
- (b)$8:55\mathrm{am}$
- (c)$8:45\mathrm{am}$
- (d)Data inadequate

**Hint**

The required time will be $15$ minutes more than the time taken by Manoj.

**Solution:**

According to the given information, Manoj reached the bus stop at $8:40\mathrm{am}$.

He takes $10\mathrm{min}$ to reach the stop, which means he left home at

$8:40\u201310\mathrm{min}=8:30\mathrm{am}$.

Now, he left his home $15\mathrm{min}$ earlier than usual time.So, his actual time of leaving the home is,

$8:30+15\mathrm{min}=8:45\mathrm{am}$.

Hence, the correct answer is $8:45\mathrm{am}.$

- (a)${90}^{\mathrm{o}}$
- (b)${75}^{\mathrm{o}}$
- (c)${60}^{\mathrm{o}}$
- (d)${85}^{\mathrm{o}}$

**Hint**

Angle traced by hour hand per minute $={\left(\frac{1}{2}\right)}^{\mathrm{o}}$

**Solution:**

In a clock, the distance between $8$ and $6=10$ min space.

Now, since $1$ min $=\frac{{360}^{\mathrm{o}}}{60}=60.$

Hence, Angle between $10$min space $=10\times {6}^{\mathrm{o}}={60}^{\mathrm{o}}$

Since, Angle traced by hour hand per minute $={\left(12\right)}^{\mathrm{o}}.$

Hence, Angle traced by hour hand in $30$min $=12\times 30={15}^{\mathrm{o}}.$

So, total angle $={60}^{\mathrm{o}}+{15}^{\mathrm{o}}={75}^{\mathrm{o}}.$

- (a)$12$
- (b)$24$
- (c)$22$
- (d)$44$

**Hint**

The hands overlap about every$1$ hour and $5$minute.

**Solution:**

As, we know that, the hands of clock coincide once every hour but between $11$O’clock and $1$ O’clock they coincide only once at $12$O’clock.

The hands overlap about every $65$minute, not every $60$minute. Hence, the hands of a clock coincide $11$ times in every $12$ hours.

Hence, they will coincide $22$ times in $24$ hours.

- (a)${20}^{th}$
- (b)${21}^{st}$
- (c)${20}^{th}$or ${21}^{st}$
- (d)Cannot be determined

**Hint**

Find the common date in both the statements.

**Solution:**

Here, as per the question, Pratap and his sister remembers correctly their mother’s birthday.

Hence, their mother’s birthday is either on 20th or ${21}^{st}$of April.

According to

Their mother’s birthday

Pratap

${20}^{t{h}^{}},{21}^{st},{22}^{nd}$

His sister

Before ${22}^{n{d}^{}}$

- (a)${17}^{th}$
- (b)${19}^{th}$
- (c)${18}^{th}$
- (d)${17}^{th}$or${18}^{th}$

**Hint**

The required date is common to both the ranges of dates correctly remembered by Rajat and his sister.

**Solution:**

According to the question,

Rajat and his sister correctly remember their mother’s birthday as follows:

According to

Their mother’s birthday

Rajat

On or before ${18}^{th}$

His sister

${18}^{th}$ or ${19}^{th}$

Hence, their mother’s birthday is on ${18}^{th}$ of June.

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- (a)$26$
- (b)$15$
- (c)$13$
- (d)$22$

**Hint**

Upon converting the expression, we get $(3\times 5+11)-11$.

**Solution:**

According to the question, the given expression is $(3-5\xf711)+11$.

After converting all the signs, the expression is $(3\times 5+11)-11$.$(3\times 5+11)-11$

$=(15+11)-11$

$=26-11$

$=15$

Hence, $15$ is the correct answer.

- (a)$100$
- (b)$10$
- (c)$91$
- (d)$0$

**Hint**

$100\xf7100+100-10$ is the expression obtained by replacing the symbols.

**Solution:**

Changing the symbols according to the question and solving the expression, we get:

$100\xf7100+100-10$$=1+100-10$

$=101-10$

$=91$

Hence option (c) is correct.

- (a)$24$
- (b)$26$
- (c)$48$
- (d)$32$

**Hint**

Convert the equation by interchanging the sign and follow BODMAS rule.

**Solution:**

According to the question, by changing the symbols and solving the equation:-

$20+8\xf74\times 2$

$=20+2\times 2$

$=20+4$

$=24$

Hence option (a) is correct.

- (a)$11$
- (b)$15$
- (c)$25$
- (d)$19$

**Hint**

Convert the alphabet into mathematical notation according to the question and solve the equation using the BODMAS rule.

**Solution:**

According to the question, by changing the symbols and solving the equation:-

$=16\xf74\times 5\u201315+6$$=4\times 5\u201315+6$

$=26\u201315$

$=11$

Hence option (a) is correct.

- (a)$45$
- (b)$35$
- (c)$25$
- (d)$15$

**Hint**

The expression obtained by decoding is $9\times 36\xf712+13\u201325$.

**Solution:**

According to the question, by changing the symbols and solving the expression, we get:

$9\times 36\xf712+13\u201325$$=9\times 3+13\u201325$

$=40\u201325$

$=15$

Hence option (d) is correct.

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- (a)$7020$
- (b)$6660$
- (c)$6652$
- (d)$3510$

**Hint**

There are $180$ candles in each box.

**Solution:**

The number of dozens of candles in a box is $15$.

Hence, the number of candles in a box is $15\times 12$.

The number of boxes are $39$.

Therefore, the total number of candles are

$15\times 12\times 39=7020$.

- (a)$120$
- (b)$150$
- (c)$180$
- (d)$300$

**Hint**

$\mathrm{Average}=\frac{\mathrm{Sum}\mathrm{of}\text{'}\mathrm{n}\text{'}\mathrm{quantities}}{\mathrm{n}}$

**Solution:**

Let us assume the third number as $x$.

And, the second number will be $3x$.

Therefore, the first number which is twice the second will be $6x$.

Now, using the average formula i.e.

$\mathrm{Average}=\frac{\mathrm{Sum}\mathrm{of}\text{'}\mathrm{n}\text{'}\mathrm{quantities}}{\mathrm{n}}$

Substituting the values in the formula, we get:

$100=\frac{x+3x+6x}{3}$

$300=10x$

$30=x$

Hence, the largest number will be

$6x=6\times 30=180.$

- (a)
$\u20b93200$

- (b)
$\u20b93000$

- (c)
$\u20b92900$

- (d)
$\u20b93700$

**Hint**

To find the value of the marked price, use the formula:

$\left(1-\frac{\mathrm{d}\%}{100}\right)$ of $M.\mathrm{P}.=\mathrm{S}.\mathrm{P}.$

**Solution:**

The marked price $\left(\mathrm{M}.\mathrm{P}.\right)$ is denoted as $Rs.$$x$.

The discount $\left(\mathrm{d}\%\right)$ given is $15\%$.

The selling price $\left(\mathrm{S}.\mathrm{P}.\right)$ of the article is $\mathrm{Rs}.2550$.

Hence, using the formula between selling price and marked price we get:

$\left(1-\frac{\mathrm{d}\%}{100}\right)\mathrm{of}\mathrm{M}.\mathrm{P}.=\mathrm{S}.\mathrm{P}.$

Substituting the values in the formula, we get:

$\left(1-\frac{\mathrm{d}\%}{100}\right)$ of $M.\mathrm{P}.=\mathrm{S}.\mathrm{P}.$

$\frac{85}{100}\times x=2550$

$x=\mathrm{Rs}.3000$

- (a)$25\%$
- (b)$20\%$
- (c)$10\%$
- (d)$5\%$

**Hint**

Use Venn diagram and the formula to find the people who owned neither is $\mathrm{Total}\%-\left({\mathrm{TV}}_{\mathrm{only}}\%+{\mathrm{Car}}_{\mathrm{only}}\%+\mathrm{Both}\%\right)$.

**Solution:**

According to the question given, we draw a Venn diagram as follows:

Percentage of persons who only owned car is:

$70\%-55\%=15\%$

Percentage of persons who owned TV only is:

$75\%-55\%=20\%$

Percentage of persons who did not own either car or TV is given as:$100\%-\left(55\%+15\%+20\%\right)$

$=100\%-90\%=10\%$

- (a)$5\%$
- (b)$10\%$
- (c)$20\%$
- (d)$15\%$

**Hint**

Use Venn diagram and the formula to find the people who use neither medium to obtain news.$\mathrm{Total}\%-\left({\mathrm{Newspaper}}_{\mathrm{only}}\%+{\mathrm{TV}}_{\mathrm{only}}\%+\mathrm{Both}\%\right)$.

**Solution:**

According to the question given, we draw a Venn diagram showing the position of those who read newspaper, watch the news on tv, and both.

Percentage of people that watch news only on TV $=$ $65\%-25\%=40\%$

Percentage of people that read news only in newspaper $=$$40\%-25\%=15\%$

Percentage of people who don't watch news $=$$100\%-(25\%+40\%+15\%)=20\%$

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- (a)
- (b)
- (c)
- (d)

**Hint**

Red and Pink are subsets of Colour.

**Solution:**

Red and Pink are different from each other, but belong to the same category i.e. Colour.

Hence option (c) is correct.

- (a)
- (b)
- (c)
- (d)

**Hint**

Books are made up of wood. Pens are made up of plastic. Pencils are made up of graphite.

**Solution:**

All the three items belong to the Stationeries, but Book, Pen, and Pencil are all different from each other.

Hence option (c) is correct.

- (a)
- (b)
- (c)
- (d)

**Hint**

Theoretically, a male doctor can also be an actor.

**Solution:**

A Man can be a Doctor as well as an Actor.

A Doctor can be a Man as well as an Actor.

An Actor can be a Man as well as a Doctor.

Hence, option C is correct.

- (a)
- (b)
- (c)
- (d)

**Hint**

The set of Blackboards is a subset of Classrooms.

**Solution:**

Schools consist of Classrooms, and Classrooms consist of Blackboards.

Hence, option 1 is correct.

- (a)
- (b)
- (c)
- (d)

**Hint**

Hens do not produce milk. They lay eggs instead.

**Solution:**

In the given question we can find the relation between Milk,Goat, and Cow.

As both Goat and Cow yield Milk so both Goat and Cow will be a subset of Milk.

And there is no connection between Hen with Milk, Goat, and Cow.

Hence, Hen will be a distinct set.

As, shown in the below diagram.

Hence, option 3 is correct.

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- (a)7
- (b)11
- (c)13
- (d)15

**Hint**

There are three vertical blocks.

**Solution:**

The total number of blocks in the upper space is 3.

The total number of blocks in the lower space is 4.

Hence, the total number of blocks are 3 + 4 = 7.

- (a)$6$
- (b)$12$
- (c)$18$
- (d)$24$

**Hint**

The formula to find the total number of middle cubes is $12\left(n-2\right)$.

**Solution:**

A middle cube is a cube that exists at the middle of each edge.

The total number of middle cubes can be formulated as $12\left(n-2\right)$, where:

$n=\frac{3cm}{1cm}=3$.

Substituting the value of $n$, we obtain the total number of middle cubes as:

$12\left(n-2\right)=12\left(3-2\right)=12$.

- (a)$18$
- (b)$9$
- (c)$8$
- (d)$81$

**Hint**

The total number of inner central cubes is ${\left(n-2\right)}^{3}$.

**Solution:**

Inner central cubes refer to the cubes that are not visible. The total number of inner central cubes is given by ${\left(n-2\right)}^{3}$.

$n=\frac{{\mathrm{Sides}}_{\mathrm{big}}}{{\mathrm{Sides}}_{\mathrm{small}}}=\frac{12}{3}=4$

${\left(n-2\right)}^{3}={\left(\frac{12}{3}-2\right)}^{3}={2}^{3}=8$,

which is the total number of inner central cubes.

- (a)$5\mathrm{cm}$
- (b)$6\mathrm{cm}$
- (c)$3\mathrm{cm}$
- (d)$4\mathrm{cm}$

**Hint**

Use the following formula to find the smaller cube edge.

${\mathrm{Cubes}}_{\mathrm{Numbers}}={\left(\frac{\mathrm{Edge}\mathrm{of}\mathrm{bigger}\mathrm{cube}}{\mathrm{Edge}\mathrm{of}\mathrm{smaller}\mathrm{cube}}\right)}^{3}$

**Solution:**

Let edge of the smaller cube be $x\mathrm{cm}$.

Using the formula for the total number of smaller cube is

${\mathrm{Cubes}}_{\mathrm{Numbers}}={\left(\frac{\mathrm{Edge}\mathrm{of}\mathrm{bigger}\mathrm{cube}}{\mathrm{Edge}\mathrm{of}\mathrm{smaller}\mathrm{cube}}\right)}^{3}$.

Substituting the values in the formula we get:

$64={\left(\frac{24}{x}\right)}^{3}$

$\sqrt[3]{64}=\left(\frac{24}{x}\right)$

$x=\frac{24}{4}=6\mathrm{cm}$

- (a)$2$
- (b)$\frac{6}{2}$
- (c)$5$
- (d)$3$

**Hint**

First, check out that given dice is standard or not as standard dices are those whose opposite sides adds up to $7.$

**Solution:**

Let us check whether the dice is standard or not the sum of adjacent sides are

$5+4=9\ne 7$

$5+1=6\ne 7$

$4+1=5\ne 7$

As the sum of sides is not equal to seven it's a standard dice.

In standard dices, the sum of the opposites sides is equal to $7$.

Hence, the face behind the face $4$ is $7-4=3$.

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- (a)Only conclusion II follows
- (b)Both conclusions I and II follows
- (c)Neither conclusion I nor II follows
- (d)Only conclusion I follows

**Hint**

No data is provided regarding the relationship of cricketers with the other sets in the given statements.

**Solution:**

According to the given Venn diagram, there is no relationship between cricketer and student, so conclusion I do not follow.

But all children are players because children are a subset of players. So, conclusion II follows.

- (a)Only conclusion I follows
- (b)Only conclusion II follows
- (c)Neither conclusion I nor II follows
- (d)Both conclusions I and II follows

**Hint**

Read the given statement and establish a connection between the actions of the foreigners and the government, and determine whether the actions are a direct outcome of the statement given.

**Solution:**

The second conclusion is not verifiable with certainty as to why the government is doing what it is doing in the statement, since there can be other reasons as well. Hence, conclusion II is false. Whereas due to attractive packages, foreigners might flock to India making conclusion I true.

- (a)Only conclusion I follows
- (b)Only conclusion II follows
- (c)Both conclusions I or II follows
- (d)Neither conclusion I nor II follows

**Hint**

If all X are Y, and all Y are Z, then all X are Z. But all Z are not X.

**Solution:**

According to the given Venn diagram, all animals are birds as animals are a subset of birds, so the conclusion I follow.

But the reverse is not true. Hence, all birds are not animals. So, conclusion II does not follow.

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- (a)
- (b)
- (c)
- (d)

**Hint**

In the case of vertical mirrors, the right side of the real image becomes the left side of the mirror image and vice-versa.

**Solution:**

According to the image given in the question, the double dots on the left side of the real image will be situated on the right side of mirror in the mirror image. Similarly, the lines on the right side of the real image will be on the left side of the mirror image. All these criteria are followed by option (2). Thereby the right answer is option (2).

- (a)
- (b)
- (c)
- (d)

**Hint**

In the case of vertical mirrors, the right side of the real image becomes the left side of the mirror image and vice-versa.

**Solution:**

According to the given figure, the right side of the real image has six dots across three levels, with three dots at the top, two at the middle, and one at the bottom. Now when the mirror image is considered, the dot-filled side will move to the left side of the mirror image, with the same arrangement of dots as in the real one. All these criteria are followed by option (1). Therefore, option (1) is the correct answer.

- (a)
- (b)
- (c)
- (d)

**Hint**

In the mirror image the letters B and C would appear to be written from right-to-left instead of left-to-right. A is symmetric about the vertical axis.

**Solution:**

According to the figure given in the question, the mirror image would have the 'B' in opposite direction horizontally on the right side of the mirror image and a similar technique will be used for 'C' as it will be located on the left side of the image but no change will come to 'A'. Now all these criteria are followed by option (1) therefore, the correct answer is (1).

- (a)
- (b)
- (c)
- (d)

**Hint**

In the case of vertical mirrors, the right side of the real image becomes the left side of the mirror image and vice-versa. The top and bottom sides remain unchanged.

**Solution:**

According to the given question, the mirror image will have the hook on the circle in the lower-right corner of the figure. Similarly, for the line elements, the line segments will travel from the upper-right corner to the lower-left corner. Therefore, the correct option with all these criteria is (1).

- (a)5
- (b)79
- (c)9
- (d)8

**Hint**

Number of horizontal lines is equal to 29.

**Solution:**

Analyzing and naming the points in the figure with alphabets as shown below:

The lines in the given figure are- AB, AC, BC, LN, LO, LP, LD, NO, NP, ND, OP, OD, PD, KM, KE, ME, JQ, JR, JS, JF, QR, QS, QF, RS, RF, SF, IG, IH, HG, AN, AM, AS, AG, NM, NS, NG, MS, MG, SG, CP, CM, CQ, CI, PM, PQ, PI, MQ, MI, QI, AL, AK, AJ, AI, LK, LJ, LI, KJ, KI, JI, BO, BM, BR, BH, OM, OR, OH, MR, MH, RH, CD, CE, CF, CG, DE, DF, DG, EF, EG, and FG.

Hence, there are a total of 79 lines.

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- (a)Paleolithic age
- (b)Mesolithic age
- (c)Classic age
- (d)Neolithic age

**Hint**

It is the final division of the Stone Age.

**Solution:**

Neolithic age is not considered as the age of Ancient History. The Neolithic, the final division of the Stone Age, began about 12,000 years ago, when the first development of farming appeared in Epipalaeolithic Near East, and later in other parts of the world.

- (a)Lower Paleolithic Age
- (b)Middle Paleolithic Age
- (c)Upper Paleolithic Age
- (d)Iron Age

**Hint**

It is also known as the Early Stone Age.

**Solution:**

Handaxe and cleavers were characteristic tools of Lower Paleolithic age. This period is also known as the Early Stone Age, which is currently believed to have lasted from between about 2.7 million years ago to 200,000 years ago.

- (a)Lower Paleolithic site
- (b)Mesolithic site
- (c)Middle Paleolithic site
- (d)Neolithic site

**Hint**

This Age, means New Stone Age which was the last and 3rd part of the Stone Age.

**Solution:**

Chirand in Bihar is a Neolithic site. This Age, means New Stone Age which was the last and 3rd part of the Stone Age. In India, its span is from around 7,000 B.C. to 1,000 B.C. the development of settled agriculture mainly characterizes this Age, the use of tools and weapons made of polished stones. The major crop grown during this period was ragi, horse gram, cotton, rice, wheat, and barley. Pottery 1st appeared in this Age.

- (a)Copper
- (b)Iron
- (c)Gold
- (d)Silver

**Hint**

The first evidence of this metal was found about 1000 BC from Atranjikhera in Etah district.

**Solution:**

Metals like gold, silver, copper and bronze were known to the Indus Civilization. However, iron was not known to the Indus people. The first evidence of iron was found from Atranjikhera in the Etah district in around 1000 B.C.

Therefore, this is the correct answer.

- (a)Ravi
- (b)Jhelum
- (c)Chenab
- (d)Indus

**Hint**

This River is one of the longest river in Asia.

**Solution:**

Mohenjodaro is situated on the bank of the Indus River. This River is one of the longest River in Asia, originating from the Tibetan Plateau in the vicinity of Lake Manasarovar, the Indus River run a course through Ladakh toward the Gilgit-Baltistan region.

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- (a)Cosmology
- (b)Astrology
- (c)Geology
- (d)Geomorphology

**Hint**

Big Bang theory study is example of it.

**Solution:**

Cosmology is the study of the origin and development of the universe. It is about evolution and eventual fate of universe.

- (a)Andromeda galaxy
- (b)Proxima Centauri
- (c)Milky Way Galaxy
- (d)Ursa major

**Hint**

It is also known as "Ganges of the sky" in Sanskrit.

**Solution:**

Galaxy is a collection of billions of stars and planets that are held together by the power of gravity. Our Solar system is a part of the Milky Way Galaxy, which is spiral in shape.

- (a)Proxima Centauri
- (b)Phobos
- (c)Ganymede
- (d)Sirius

**Hint**

It was discovered by Robert Innes in 1915.

**Solution:**

Proxima Centauri is the star, closest to our Solar system. It is about 4.22 light-years from Earth. Its Latin name Centaurus means nearest, located in the southern constellation away from the Sun.

- (a)7 minutes
- (b)8 minutes
- (c)8.7 minutes
- (d)8.3 minutes

**Hint**

It takes 498 seconds to reach earth.

**Solution:**

The Sunlight takes on an average of 8 minutes and 20 seconds to travel from the Sun to the Earth. The Earth follows an elliptical orbit around the Sun, ranging from 147 million to 152 million km. At its closest point, sunlight only takes 490 seconds to reach Earth. And then at the most distant point, it takes 507 seconds for sunlight to make the journey.

- (a)Jupiter, Mars, Saturn and Earth
- (b)Jupiter, Saturn, Neptune and Uranus
- (c)Mercury, Venus, Earth and Mars
- (d)Neptune. Pluto, Saturn and Mars

**Hint**

Inner planets are also known as terrestrial planets.

**Solution:**

Planets which lie between the Sun and asteroid belt are called inner planets. The inner planets are Mercury, Venus, Earth and Mars whereas the outer planets are Jupiter, Saturn, Uranus and Neptune. Inner planets have no moon or, they have one or two moons only.

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- (a)Bombay, Madras, Calcutta
- (b)Delhi and Calcutta
- (c)Bomaby, Delhi, Madras
- (d)Madras and Bombay

**Hint**

These are present day metropolitan cities of India.

**Solution:**

Bombay, Calcutta and Madras High Courts were established by the Indian High Court Act, 1861. The Calcutta High Court has been considered to be the first High Court established in India. The Indian High Court Act of 1861 was passed in Parliament of Britain to create High Courts in India. It was Passed during the tenure of Lord Canning.

The correct answer is Bombay, Madras, Calcutta.

- (a)The Chief Minister
- (b)The Governor
- (c)The Cabinet
- (d)The Legislature Assembly

**Hint**

He/she appoints the chief minister.

**Solution:**

Part IV of the Constitution of India deals with the States. The State Executive comprises of Governor, Chief Minister, Council of Ministers, and Advocate General. The Governor is the executive head of the state. Article 153 to 167 relates to the power and functions of the Governor.

The correct answer is The Governor.

- (a)Chief Minister of the State
- (b)Governor of the State
- (c)Prime Minister
- (d)President of India

**Hint**

He is the Constitutional head of the state.

**Solution:**

The Governor of the State holds the power to appoint and remove the Chairman of the State Public Commission. Article 315 to 323 in Part XIV of the Constitution deals with the appointment and functioning of the Public Service Commission.

- (a)Six months
- (b)No time limit
- (c)One year
- (d)Three months

**Hint**

Part VI of the Constitution deals with the State government.

**Solution:**

Article 163-164 of the Constitution deals with the Council of Ministers. Six months is considered the maximum period a person can continue to be a minister of the State Government without being a member of the state legislature.

The correct answer is six months.

- (a)
Government

- (b)
President

- (c)
Political Party

- (d)
All of the above

**Hint**

It is the system or group of people governing an organized community, often a state.

**Solution:**

The government is the group or system through which the state is governed. The government enforces the policies and measures for the development of the state. State Government is a subdivision in the federal form of government. It has an autonomy of its own and enforces laws and policies.

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- (a)Adam Smith
- (b)Amartya Sen
- (c)Prof Marshall
- (d)Karl Marx

**Hint**

'The Wealth of Nations' was his famous book.

**Solution:**

Adam Smith is known as the Father of Economics. He was of Scottish descent and a well-known philosopher, economist and author, he laid the foundations of classical free-market economic theory. He was also known as the 'Father of Capitalism'.

- (a)Teaching
- (b)Construction
- (c)Hotels and Restaurants
- (d)Insurance

**Hint**

The service sector provides services. Service sector include retail, banks, hotels, etc.

**Solution:**

Service Sector in India includes services instead of goods and material. Service Sector includes trade, hotels, banking, teaching, business, social service, and personal service. This sector contributes the highest in the nation’s gross domestic product. Construction is not part of the service sector in India.

- (a)Service Sector
- (b)Manufacturing Sector
- (c)Agriculture Sector
- (d)Small Scale Industries

**Hint**

It is also known as the tertiary sector.

**Solution:**

Service sector contributes the most to India’s Economy. It includes trade, hotels, banking, teaching, business, social service, and personal service. This sector provides the highest in the nation’s gross domestic product.

- (a)Income and price of commodity
- (b)Income and quantity demand
- (c)Price and quantity of a commodity
- (d)Quantity demanded and quantity supplied

**Hint**

In this concept, when the price of a product increases, the demand for the same product will fall.

**Solution:**

The Law of demand is a fundamental concept. This concept talks about the price of commodities going higher in the market, and demand for such commodities getting lowered. It reflects general human behaviour. It occurs because of the diminishing marginal utility. The Law of demand presents an inverse relationship also between quantity and price of a commodity.

- (a)Changes in income
- (b)Changes in price
- (c)Changes in fashion
- (d)Changes in price of substitutes

**Hint**

It is related to the law of demand.

**Solution:**

Due to a change in price, the demand curve either moves upward or downward. As per the law of demand, the other factors remaining constant, the price of a commodity is inversely related to the quantity demanded. Price increases, demand decreases; thus, we move upward on the curve and vice versa.

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- (a)George Washington
- (b)Robert Peary
- (c)Trygve Lie
- (d)None of the above

**Hint**

He was a Norwegian Politician.

**Solution:**

Trygve Lie was the first Secretary-General of the United Nations. He served from $1946$ to $1952$. He was a Norwegian politician and foreign minister. Lie was a pragmatic and determined politician.

- (a)Dennis Tito
- (b)Alexi Leonov
- (c)Yuri Gagarin
- (d)Rakesh Sharma

**Hint**

He was a Russian citizen.

**Solution:**

Alexi Leonov was a Soviet and Russian cosmonaut. In 1965, he become the first person to conduct a spacewalk during the Voskhod 2 mission for 12 minutes and 9 seconds. He edited the cosmonaut newsletter, Neptune.

- (a)Aspheosis
- (b)Sully Prudhomme
- (c)A E Von Behring
- (d)Anaximander

**Hint**

He was known as the father of Astronomy.

**Solution:**

Anaximander was the first man to draw a map of the Earth. He was a Greek philosopher. He belonged to the Milesian school. His master was Thales. He has been known as the father of astronomy. He explained the origin of the universe with the theory of ‘Apeiron’.

- (a)Vijayalakshmi Pandit
- (b)Annie Besant
- (c)Sarojini Naidu
- (d)Sucheta Kriplani

**Hint**

She was sister of Jawaharlal Nehru.

**Solution:**

Vijayalakshmi Pandit was an Indian diplomat. She was elected as the first woman President of the United Nations General Assembly. She served as President of the UN General Assembly from 1953 to 1954.

- (a)Ann Bancroft
- (b)Anousheh Ansari
- (c)Sunita Williams
- (d)None of the above

**Hint**

First self –funded woman to fly to the International Space Station.

**Solution:**

Anousheh Ansari is an Iranian American engineer. She is also the co-founder and chairwoman of Prodea Systems. In September 2006, she becomes the first Iranian and first female Muslim in space. She was also the first self-funded space tourist.

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- (a)Speed
- (b)Velocity
- (c)Torque
- (d)Displacement

**Hint**

Scalar quantity does not have direction.

**Solution:**

A vector is a quantity that has both a magnitude and a direction. Some example is velocity, displacement, acceleration, torque, etc. Speed is the rate at which an object covers a particular distance. Formula of speed is distance per time ratio. Speed is a scalar quantity, it does not consider direction.

- (a)Energy
- (b)Power
- (c)Force
- (d)Momentum

**Hint**

Joule is the SI Unit of it.

**Solution:**

Kilowatt per hour is the unit of energy that is equivalent to 3600 kilojoules. Its symbol is kWh. It is commonly used in the billing unit for energy consumption by consumers.

- (a)Conservation of momentum
- (b)Conservation of mass
- (c)Conservation of energy
- (d)Conservation of angular momentum

**Hint**

Air filled balloon is the example of this principle.

**Solution:**

Law of conservation of momentum states that, if objects collide, the total momentum before the collision is the same as the total momentum after the collision. This applies only to an isolated object and no external force is applied.

- (a)Newton
- (b)Archimedes
- (c)Galileo
- (d)Faraday

**Hint**

He also discovered law of motion.

**Solution:**

Sir Isaac Newton was an English mathematician, physicist, astronomer, theologian, and author. He is widely recognized as a key figure in the scientific revolution. Newton defined the law of gravitation. He states that every particle attracts every other particle in the universe with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

- (a)Viscosity
- (b)Surface tension
- (c)Elasticity
- (d)Gravitation

**Hint**

Its SI unit is Newton/meter.

**Solution:**

Surface tension is the tendency of liquid surfaces to shrink into the minimum surface area possible. The shape of a raindrop is spherical due to surface tension. It is the effects of intermolecular forces at the interface.

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- (a)$200$
- (b)$2$
- (c)$2000$
- (d)$20000$

**Hint**

Place value of a digit is the digit multiplied by ${10}^{n-1}$, where $n$ is the position of digit from the right.

**Solution:**

Place value of a digit is the digit multiplied by ${10}^{n-1}$, where $n$ is the position of digit from the right.

So, the place value of $2$ in $832567$ will be $2\times 1000=2000$.

- (a)$\sqrt{4}$
- (b)$\sqrt{3}$
- (c)$2+\sqrt{3}$
- (d)$5\sqrt{3}$

**Hint**

A rational number is a number that can be expressed as the quotient or fraction $\frac{p}{q}$ of two integer numbers provided $q$ is never zero.

**Solution:**

A rational number is a number that can be expressed as the quotient or fraction $\frac{p}{q}$ of two integers, a numerator $p$ and a non-zero denominator $q$. Since $q$ may be equal to $1$, every integer is a rational number.

As $\sqrt{4}$ can be solved as $\pm 2$

So, it is a rational number.

- (a)$\frac{22}{7}$
- (b)$\mathrm{\pi}$
- (c)$1.333$
- (d)$3.14$

**Hint**

The numbers which can be expressed as a fraction like $\frac{22}{7}$ cannot be irrational.

**Solution:**

An irrational number is a real number that cannot be written as a simple fraction.

A rational number is a number that can be expressed as the quotient or fraction $\frac{p}{q}$ of two integers, a numerator $p$ and a non-zero denominator $q$. Since q may be equal to $1$, every integer is a rational number.

Here, $\mathrm{\pi}$ is an irrational number.

- (a)$0$
- (b)$1$
- (c)$2$
- (d)$3$
- (e)$4$

**Hint**

A prime number has factors as $1$ and the number itself only.

**Solution:**

A prime number is a natural number that does not have any number other than $1$ and the number itself as its factor. A natural number greater than $1$ that is not prime number is called a composite number. For example, $5$ is prime because it has factors as $1$ and $5$ only.

The smallest Odd prime number is $3$.

- (a)$137$
- (b)$122$
- (c)$144$
- (d)$125$

**Hint**

A prime number is a number which has only two factors, $1$ and itself.

**Solution:**

Prime number is a number that is divisible only by $1$ and itself (e.g., $2,3,5,7,11$)

So, among the given options, $137$ is a prime number.

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- (a)$\frac{10}{13},\frac{12}{17},\frac{5}{6},\frac{11}{21}$
- (b)$\frac{11}{21},\frac{12}{17},\frac{10}{13},\frac{5}{6}$
- (c)$\frac{5}{6},\frac{10}{13},\frac{11}{21},\frac{12}{17}$
- (d)$\frac{5}{6},\frac{10}{13},\frac{12}{17},\frac{11}{21}$

**Hint**

The decimal forms of the fractions are easier to compare.

**Solution:**

Converting all the fractions into decimals, we get the following:

$\frac{11}{21}=0.523$

$\frac{12}{17}=0.705$

$\frac{10}{13}=0.769$

$\frac{5}{6}=0.833$

Therefore, Ascending order is as follows; $0.523<0.705<0.769<0.833$.

Which is equals to $\frac{11}{21}<\frac{12}{17}<\frac{10}{13}<\frac{5}{6}$.

- (a)$\frac{1}{2}$
- (b)$\frac{2}{3}$
- (c)$\frac{4}{5}$
- (d)$\frac{9}{10}$

**Hint**

The decimal value of one of the option should lie between the decimal values of $\frac{3}{4}$ and $\frac{5}{6}$, i.e. $0.75$ and $0.833$.

**Solution:**

First of all calculating the decimal values of fractions given in the question:

$\frac{3}{4}=0.75$

$\frac{5}{6}=0.833$

Now, calculating the decimal values of fractions given in the options:

$\frac{1}{2}=0.5$

$\frac{2}{3}=0.666$

$\frac{4}{5}=0.8$

$\frac{9}{10}=0.9$

Therefore, According to the options $0.8$ comes in between as,

$0.75<0.8<0.833$.

That is, $\frac{3}{4}<\frac{4}{5}<\frac{5}{6}$.

- (a)$\frac{4}{7}$
- (b)$\frac{4}{5}$
- (c)$\frac{7}{8}$
- (d)$\frac{7}{9}$

**Hint**

Let, the fractions be $a,b,c:$

$a+b+c=2\frac{11}{24}=\frac{59}{24}$

**Solution:**

Let, the fractions be $a,b,c$ in decreasing order.

So, according to the question,

$a+b+c=2\frac{11}{24}=\frac{59}{24}$

As said in the question, the greatest fraction is divided by smallest fraction, so $\frac{a}{c}=\frac{7}{6}$

Therefore, $a=\frac{7}{6}c$

and now,

$b+\frac{1}{3}=\frac{7}{6}$

$b=\frac{7}{6}-\frac{1}{3}$

$b=\frac{5}{6}$

So, now as $a+b+c=\frac{59}{24}$$\frac{7}{6}c+\frac{5}{6}+c=\frac{59}{24}$

$\frac{13}{6}c=\frac{59}{24}-\frac{5}{6}$

$\frac{13}{6}c=\frac{39}{24}$

$c=\frac{39}{24}\times \frac{6}{13}$

$c=\frac{3}{4}$

So, $a=\frac{7}{6}c$

$a=\frac{7}{6}\times \frac{3}{4}$

$a=\frac{7}{8}$

- (a)$\frac{8}{27}$
- (b)$1\frac{1}{3}$
- (c)$2\frac{2}{3}$
- (d)$3\frac{2}{3}$

**Hint**

Let, the fraction be $a$, not $\frac{a}{b}$, ifor simpler evaluation.

**Solution:**

Let, the fraction be $a$.

So, according to the question :

$\frac{a\times a}{\frac{1}{a}}=18\frac{26}{27}$

${a}^{3}=\frac{512}{27}$

$a=\sqrt[3]{\frac{512}{27}}$

$a=\frac{8}{3}$

$a=2\frac{2}{3}$

Hence, The correct answer is $2\frac{2}{3}$

- (a)$\frac{75}{56}$
- (b)$\frac{73}{56}$
- (c)$\frac{71}{34}$
- (d)$\frac{75}{48}$

**Hint**

Converting all the fraction into its decimal form for comparision to get the smallest and largest fraction for taking their sum.

**Solution:**

First of all we will find out which fraction is largest and which fraction is smallest. For that we will figure out the decimal values first.

$\frac{3}{7}=0.428$

$\frac{11}{13}=0.846$

$\frac{{\displaystyle 6}}{{\displaystyle 11}}=0.545$

$\frac{{\displaystyle 7}}{{\displaystyle 8}}=0.875$

$\frac{{\displaystyle 5}}{{\displaystyle 9}}=0.555$

Now, we can clearly see that $0.875$ value is the largest value and $0.428$ is the smallest value.

So, now according to the question :

$\frac{7}{8}+\frac{3}{7}=\frac{73}{56}$

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- (a)One
- (b)Two
- (c)Three
- (d)None of these

**Hint**

Find out the LCM to get the numbers divisible by $12,15$ and $20$, and find the LCM's multiples lying in the given range.

**Solution:**

To find out the numbers divisible by $12,15$ and $20,$ we need to take the LCM of all these.

So, LCM of $12,15,20$ is $60$

Therefore, every multiple of $60$ is divisible by all $12,15$ and $20.$

So the multiples of $60$ are:

$60,120,180,240,300,360,420,480,540,600$ and so on ....

Therefore, we can see that only $420$ and $480$ are lying in between $400$ and $500$.

So, there are only two numbers between $400$ and $500$ which are divisible by all $12,15$ and $20$.

- (a)$216,288$
- (b)$224,296$
- (c)$210,240$
- (d)$224,288$

**Hint**

Find the LCM and add the remainder

**Solution:**

First lets find the LCM of $6,8,9$

LCM of $6,8,9=72$

Required number which when divided by $6,8,9$ leaves remainder $8$ is always multiple of $72$ plus $8$

Required Number $=$ Multiple of $72+8$) which lies between $200$ and $300$

By checking the multiples we can figure out that $3\mathrm{rd}$ and $4\mathrm{th}$ multiple satisfies between $200$ and $300$.

i.e. $(72\times 3+8,72\times 4+8)=(224,296)$

- (a)$273,357$
- (b)$210,340$
- (c)$215,314$
- (d)$210,252$

**Hint**

Product of two numbers $=$ HCF $\times $ LCM.

**Solution:**

Since, the HCF of two numbers is $21$

Hence, let the numbers be $21x$ and $21y$ respectively.

We know that, product of two numbers $=$ HCF $\times $ LCM

$\Rightarrow 21x\times 21y=21\times 4641$

$\Rightarrow xy=221=13\times 17$

$\left(13\times 17\right)$ because $x$ and $y$ are co-prime.

Therefore, the numbers are

$(21\times 1321\times 17)=\left(273357\right)$

Hence, The correct answer is option A.

- (a)$23$
- (b)$46$
- (c)$25$
- (d)$29$

**Hint**

HCF of the numbers after deducting the common reminder.

**Solution:**

The greatest number can be found out by taking the difference between the numbers and remainder then taking the HCF of whole.

Required number $=$ HCF of $(284-8),(698-8)$ and $(1618-8)$

$=$ HCF of $276,690$ and $1610=46$

Hence, The correct answer is option B.

- (a)$21$
- (b)$30$
- (c)$35$
- (d)$40$

**Hint**

HCF means highest common factor. It means the greatest number which can divide the given numbers.

**Solution:**

Largest number which leaves the same remainder is find out by taking the difference between those numbers and then taking the HCF as whole.

Therefore, Required number $=$ HCF of $(132-62),(237-132)$ and $(237-62)$

$=$ HCF of $70,105$ and $175$

$=35$