### Contents of Mental Ability Tests

This book contains chapter-wise solutions, topic-wise solutions, exercise-wise solutions, and videos.

#### 16 Chapters

- 1. Alphabetical Test
- 2. Coding-Decoding Test
- 3. Spotting Out the Dissimilar
- 4. Analogy Test
- 5. Series Completion Test
- 6. Arranging in Order
- 7. Direction Sense Test
- 8. Number Test and Time Sequence Test
- 9. Deductive Logic
- 10. Blood-Relation Test
- 11. Assigning Artificial Values to Arithmetic Signs
- 12. Assumption Type Test
- 13. Most Essential Component and Venn Diagram
- 14. Statement and Arguments
- 15. Ordering, Ranking and Puzzle Test
- 16. Model Paper

#### 1 Topics

Coding-Decoding

#### 1 Topics

Odd One Out

#### 3 Topics

Number-Series

Alphabet-Series

Letter-Series

#### 1 Topics

Order and Ranking

#### 1 Topics

Direction Test

#### 2 Topics

Number Test

Time Sequence Test

#### 1 Topics

Blood-Relation

#### 1 Topics

BODMAS

#### 1 Topics

Statement & Assumption

#### 1 Topics

Venn Diagram

#### 1 Topics

Statement & Arguments

#### 6 Topics

Position Series Test

Height Series Test

Age Series Test

Circular Test Series

Line Series Test

Square Series Test

## Experience Tests Tailored to Match the Real Exam

## Practise Questions with Solutions from the Mental Ability Tests

- (a)3
- (b)4
- (c)1
- (d)5
- (e)None of these

**Hint**

Between M and N in the given word, one letter is there, but if you check in alphabets, there is no gap between M and N.

**Solution:**

According to the given word “MONKEY” in the question, we found that:

From the above figure we can clearly see that there is only one pair of letters: N—O which has the same no. of letters left between them i.e., 0 for both alphabetical series and in the given word.

- (a)2
- (b)3
- (c)4
- (d)1
- (e)None of these

**Hint**

One of such pairs is G and E, in which we have one letter gap in the given word as well as in the alphabet series.

**Solution:**

According to the given word “SMUGGLER” in the question, we found that:

From the above figure we can clearly see that, T is between S & U and F is between G & E which have the same no. of letters left between them in the word as they have in the series.

- (a)$2$
- (b)$3$
- (c)$4$
- (d)$1$
- (e)None of these

**Hint**

One of such pairs is A and E, in which we have three letters gap in the given word as well as in the alphabet series.

**Solution:**

According to the given word “BONAFIDE” in the question, we found that:

From the above figure we can clearly see that Six letter-pairs of the word are : N—O, B—F, A—D, D-F, D-E and A-E which have the same no. of letters left between them in the word as they have in the series.

- (a)$2$
- (b)$4$
- (c)$1$
- (d)$3$
- (e)None of these

**Hint**

Between O and N, no letter/s in the given word, as well as in the alphabet series.

**Solution:**

According to the given word “FRONTIER” in the question, we found that:

From above figure we can clearly see that O & N are adjacent and O, P, Q are between N & R which have the same number of letters left between them in the word as they have in the series.

Hence, $2$ is the correct answer.

- (a)3
- (b)1
- (c)4
- (d)2
- (e)None of these

**Hint**

Between T and S, no letter/s in the given word as well as in the alphabet's series.

**Solution:**

According to the given word “MINISTER” in the question, we found that:

From above figure we can clearly see that, T & S are adjacent and S is between T and R which have same no. of letters left between them in the word as they have in the series.

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- (a)ILHTG
- (b)ILGHT
- (c)ILGTH
- (d)THGIL
- (e)None of these

**Hint**

The letter in the middle remains same.

**Solution:**

According to the question,

As the first two and the last two letters are reversing while the letters in the middle remain as they are in code.

Hence, the correct answer is ILGTH.

- (a)TDBO
- (b)TZBK
- (c)PZXK
- (d)TVXK
- (e)None of these

**Hint**

Observe the letter gap pattern between the corresponding letters.

**Solution:**

According to the question,

One is added to first and third letter and three is subtracted to second and fourth letter.

Hence, the correct answer is TZBK.

- (a)HTORW
- (b)HTWOR
- (c)HTWRO
- (d)HTRWO
- (e)None of these

**Hint**

First two pair of letters are reversed.

**Solution:**

According to the question,

Take the first two pairs of letters and reverse their order and the last letter will be same.

SP changed into PS, AN changed into NA and last letter K will remain same.

In the same way,

TH coded as HT, RO coded as OR and W will remain same.

Hence, THROW has been coded as HTORW.

Hence, the correct answer is HTORW.

- (a)USLBESAE
- (b)USLBAEES
- (c)USBAELES
- (d)USLBEAES
- (e)None of these

**Hint**

Take letters in pairs and reverse them.

**Solution:**

According to the question,

Set of two letters are reversed in the code.

Similarly.

Hence, the correct answer is USLBAEES.

- (a)EPRIDOIC
- (b)PEIRDOCI
- (c)EPIRDOCI
- (d)EPIRODCI
- (e)None of these

**Hint**

Letters are reversed in the code in a particular pattern.

**Solution:**

According to the question,

Set of two letters are reversed to form the code. In the word 'PURSER', 'PU' is coded as 'UP', 'RS' is coded as 'SR' and 'ER' is coded as 'RE'. So, the code for 'PURSER' is 'UPSRRE'.

Hence, the correct answer is EPIRDOCI.

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- (a)BFD
- (b)NRP
- (c)HLG
- (d)QUS
- (e)UYW

**Hint**

The second letter is two letter ahead of of the third letter.

**Solution:**

According to the question,

In all the options except third, the third letter is two letters ahead of the first letter and second letter is two letters ahead of the third letter.

In HLG, the first letter is one letter ahead of the third letter and second letter is five letter ahead of the third letter.

Hence, the correct option is C.

- (a)GTSH
- (b)BYXC
- (c)ETUF
- (d)LONM
- (e)KPIR

**Hint**

Observe the position of first and second letter in alphabet series.

**Solution:**

According to the question,

In all the options except in third, the position of the first letter from the left is the same as the position of the second letter from the right in the alphabet series.

For example, in option A, G is the seventh letter from the left and T is also the seventh letter but from the right.

Hence, the correct answer is ETUF which does not follow this pattern.

- (a)PQ
- (b)CD
- (c)MN
- (d)DF
- (e)RS

**Hint**

Check the letter gap in each as per alphabetical series.

**Solution:**

According to the question,

In all the options except fourth, the second letter is immediate right of the first letter in the alphabet series.

Hence, the correct answer is DF.

- (a)HB
- (b)ZU
- (c)NI
- (d)TO
- (e)PK

**Hint**

Observe the letter gap in each option according to English alphabet.

**Solution:**

According to the question,

In all the options except first, the first letter stands 5 places ahead of the second letter.

Hence, the correct answer is HB.

- (a)CEl
- (b)QSX
- (c)JLP
- (d)QSW
- (e)MOS

**Hint**

There is a constant difference between first and second letter in all the options.

**Solution:**

According to the question,

In all the options except second, the third letter stands 4 places ahead of the second letter.

Hence, the correct answer is QSX.

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- (a)Needle
- (b)Nail
- (c)Stick
- (d)Pin
- (e)None of these

**Hint**

The first word is part of the second word.

**Solution:**

According to the given information in the question, we can conclude that 'Vehicle' requires 'Wheel' for the movement in the same way 'Clock' requires 'Needle' to run.

- (a)Plants
- (b)Field
- (c)Forest
- (d)Trees
- (e)Stem

**Hint**

Small things combined and make a big one.

**Solution:**

According to the given information in the question, we concluded that small things combined and make a big one like a group of 'Plateaus' makes a 'Mountain', in the same way, group of 'Bush' makes a 'Forest'.

- (a)Satellites
- (b)Disease
- (c)Animals
- (d)Coins
- (e)None of these

**Hint**

First word is the study of the second word.

**Solution:**

According to the given information in the question, we can know about the 'Planets' with the help of 'Astronomy', in the same way with the help of 'Astrology' we can know about 'Past, Present and Future' which is not an alternative.

- (a)Earth
- (b)Sea
- (c)Fair
- (d)Sky
- (e)None of these

**Hint**

First one occurs in the second one.

**Solution:**

According to the given information in the question, we can conclude that 'Earthquake' occurs on the 'Earth' in the same way 'Thundering' occurs in the 'Sky'.

- (a)Tonight
- (b)To feel
- (c)To steal
- (d)To wander
- (e)None of these

**Hint**

The second word is the job of the first one.

**Solution:**

According to the given information in the question, 'Author' is related to 'Writing.

Here, we have to find out the word to which thief is related.

Here, we can conclude that the main work of an 'Author' is 'Writing', in the same way, the main work of a 'Thief' is 'Stealing'.

Hence, the correct answer is to steal.

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- (a)28
- (b)24
- (c)27
- (d)29
- (e)none of these

**Hint**

Total no. of students in the class = (position from one end + position from another end) - 1

**Solution:**

First Method

According to the question, Rajan's position from one end is 15th, and from the other end is 13th .

So, total no. of students in the class = ( position from one end + position from another end) - 1

Total no. of students = (15 + 13) - 1

Total no. of students = 27

Second Method

Rajan's position from one end is 15th, which means that 14 students are before him, and from other end is 13th i.e. 12 students are after him.

Total no. of students = 14 + 1(Rajan) + 12

Total no. of students = 27

- (a)8
^{th} - (b)9
^{th} - (c)
7

^{th} - (d)10
^{th} - (e)None of these

**Hint**

Position from the other end = (Total - position from one end) + 1

**Solution:**

Total number of students in class = 21

The position of Shyamal from the last in his class = 13

^{th}The position of Shyamal from the beginning = (Total students in the class - Shyamal's position from the last) + 1

= (21 - 13) + 1 = 9

^{th}

- (a)9
^{th} - (b)12
^{th} - (c)10
^{th} - (d)11
^{th} - (e)None of these

**Hint**

Position from the other end = (Total number of students - position from the one end ) + 1

**Solution:**

Total number of students in Sanju's class = 40

Sanju's position from one end = 30

^{th}Sanju's position from the other end = (Total number of students in the class - his position from the one end ) + 1

= (40 - 30) + 1

= 11

^{th }

- (a)25
^{th} - (b)24
^{th} - (c)26
^{th} - (d)20
^{th} - (e)None of these

**Hint**

Position of Vimla from the right = (Total number of girls – Position of Vimla from the left) + 1

**Solution:**

Now Nivedita becomes 18

^{th}from the left and 23^{rd}from right in a row.Total number of girls in row = (Position of Nivedita from the left side + Position of Nivedita from right in row) - 1

= (18 + 23) - 1

= 40

Position of Vimla from the right = (Total numbers of girls – Position of Vimla from the left) + 1

= (40 - 15) + 1

= 26

^{th}

- (a)$35$
- (b)$34$
- (c)$44$
- (d)$24$
- (e)None of these

**Hint**

Total number of ladies in row $=$(Position of Manorama from the left side $+$ Position of Manorama from right side in row)$-1$

**Solution:**

According to the question:

Now, Manorama becomes ${25}^{\text{th}}$ from the right and ${10}^{\text{th}}$ from left in the row.

Then,

Total number of ladies in row $=$ (Position of Manorama from the left side $+$ Position of Manorama from right side in row) $-1$

$=\left(10+25\right)\u20131$

$=34$

Hence, $34$ is the correct answer.

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- (a)5 metres
- (b)10 metres
- (c)20 metres
- (d)15 metres
- (e)Can not be determined

**Hint**

The distance between point A and E is 5 m.

**Solution:**

Ramesh started from a fixed point O and goes 15 m towards North at point A, and then after turning to his right, he goes 15 m at point B. Then he goes 10 m at point C, 15 m at point D, and 15 m at point E after turning to his left each time.

The distance between final point E and initial point O is given by

OE = OD - DE

OE = OA + AD - DE

OE = OA + BC - DE

OE = 15 + 10 - 15 = 10 m

So, the distance between the initial and final position of Ramesh is 10 m.

- (a)$7km$ East
- (b)$5km$West
- (c)$7km$ West
- (d)$5km$ North-East
- (e)None of these

**Hint**

We use pythagoras theorem to find the value.

${H}^{2}={P}^{2}+{B}^{2}$

**Solution:**

Sonalika started from the fixed point $O$, then she goes $12km$towards North at point $B$, then she goes $8km$ towards South at point $A$ and in the end, she goes $3km$ towards East at point $C$.

The shortest distance between the initial point $O$ and final point $C$ is given by

$OC=\sqrt{O{A}^{2}+A{C}^{2}}$

$OC=\sqrt{{\left(OB-AB\right)}^{2}+A{C}^{2}}$

$OC=\sqrt{{\left(12-8\right)}^{2}+{\left(3\right)}^{2}}$

$OC=\sqrt{16+9}$

$OC=5km$

So, the shortest distance between initial and final position of Sonalika is $5km$ and clearly the final point $C$ is in North-East direction of initial point $O$ .

- (a)45 km, East
- (b)15 km, East
- (c)45 km, West
- (d)45 km, North
- (e)None of these

**Hint**

She has to travel west to reach her original position.

**Solution:**

Sunita started from the fixed point O, then she goes 30 km towards North at point A, then she goes 15 km towards right at point B and finally she goes 30 km towards right at point C.

The shortest distance between the initial point O and final point C is given by

OC = AB = 15 km

Also, C is in the East direction of O.

So, Sunita is finally at 15 km in East direction of initial point O.

- (a)40 m
- (b)5 m
- (c)10 m
- (d)15 m
- (e)None of these

**Hint**

Here MQ = OP and Kanchan has to travel towards east to reach original direction.

**Solution:**

Kanchan started from a fixed point N, then she goes 5 m towards East at point M, then she goes 35 m after turning to her left at point O. Again she goes 10 metres after turning to her right at point P. After this she goes 35 m after turning to her right at point Q.

The shortest distance between the initial point N and final point Q is given by

NQ = NM + MQ

NQ = NM + OP

NQ = 5 + 10 = 15 m

So, the shortest distance between the initial point N and the final point Q is 15 m.

- (a)40 m, North
- (b)50 m, West
- (c)10 m, East
- (d)10 m, West
- (e)None of these

**Hint**

Shri Prakash has to turn left to reach original position.

**Solution:**

Shri Prakash started from point O, then he walked 40 metres facing towards North at point A. From there he walked 50 metres after turning to his left at point B. After this he walked 40 metres after turning to his left at point C.

The shortest distance between the initial point O and final point C is given by

OC = AB = 50 m

C is in west direction of O.

So, the final position of Shri Prakash is 50 m, west from the initial point O.

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- (a)One
- (b)Two
- (c)Three
- (d)Four
- (e)More than four

**Hint**

Firstly figure out places where 7 is present.

**Solution:**

According to given question

437523721367542[7]427122[7]6572

274, 276 are the seven's which are preceded by an even number and also not followed by an odd number.

Thus, there are two 7’s, shown in brackets.

- (a)One
- (b)Two
- (c)Three
- (d)Four
- (e)More than four

**Hint**

Two of such trios repeat themselves.

**Solution:**

According to given question

5243[5]4678532573[5]6423[5]47523[5]83[5]6

354, 356, 354, 358, 356 are the five's which are preceded by 3 but not followed by 2.

Thus, there are five 5’s, shown in brackets.

- (a)One
- (b)Two
- (c)Three
- (d)Four
- (e)More than four

**Hint**

Find the position of all 3 and then look for the number which satisfies the condition.

**Solution:**

According to given question

3425[3]1521367[3]182785[3]91345235435

531, 731, 539 are the 3's which are preceded by an odd number but not followed by an even number.

Thus, there are three 3’s, shown in brackets.

- (a)60
- (b)28
- (c)20
- (d)32
- (e)None of these

**Hint**

68 is 5th element in new order.

**Solution:**

According to given question

The numbers from 4 to 84 and divisible by 4 are : 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48, 52, 56, [60], 64, 68, 72, 76, 80 and 84

In reverse direction:

84, 80, 76, 72, 68, 64, [60], 56, 52, 48, 44, 40, 36, 32, 28, 24, 20,16, 12, 8, 4

After writing in reverse order then the number at the 7th place will be 60.

- (a)10
- (b)8
- (c)6
- (d)Less than 6
- (e)Noné of these

**Hint**

Write all multiples of 3 and check for the given condition.

**Solution:**

According to given question

The numbers from 5 to 100 and divisible by 3 are :

6, 9, 12, 15, 18, 21, 24, 27, [30], [33], [36], [39], 42, 45, 48, 51, 54, 57, 60, [63], 66, 69, 72, 75, 78, 81, 84, 87, 90, [93], 96, 99

There are 6 such numbers which include 3 at atleast one place.

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- (a)Only I follows
- (b)All follow
- (c)Only II and III follow
- (d)Only III and IV follow
- (e)None of these

**Hint**

If the relation all A are B is given then the conclusion some B are A will be true.

**Solution:**

Given Statements:

All kings are beggars.

All beggars are monks.

After analysing the given statements, the following Venn diagram can be formed.From the above diagram, let's check each conclusion:

Conclusion I. All beggars are kings will be false as beggars in the superset.

Conclusion II. All kings are monks will be true as kings is the subset of the set monks.

Conclusion III. Some monks are beggars will be true as the monk is the superset of the set of beggars.

Conclusion IV. No monk is a beggar will be false as all the given statements are positive.

Hence, the correct answer is only II and III follow.

- (a)All follow
- (b)Only I and III
- (c)Only II and IV
- (d)Only III and IV
- (e)None of these

**Hint**

If the relation all A are B is given, then the conclusions some B are A always follows.

**Solution:**

According to the given statement, the following Venn diagram can be drawn,

Now, let's check each conclusion,

Conclusion I. All benches are chairs will be false as the set of chairs is the subset of benches.

Conclusion II. All benches are boxes will be false as the set of boxes is the subset of benches.Conclusion III. Some benches are chairs will be true as the set of benches is the superset of chairs.

Conclusion IV. Some chairs are boxes will be true as the set of chairs is the superset of boxes.

Hence, the correct answer is only III and IV.

- (a)All
- (b)Only I and IV
- (c)Only IV
- (d)Only II and III
- (e)None of these

**Hint**

In this, labourers and grocers sets are a subset of wrestlers set.

**Solution:**

After brainstorming with given data we can find that,

Clearly,

All grocers are wrestlers follows.

Some wrestlers are grocers follows.

Some wrestlers are labourers follows.

Some labourers are grocers follows.

- (a)Only III and IV
- (b)All
- (c)Only II and III
- (d)Only IV
- (e)None of these

**Hint**

There is no information given about the relationship between artists and sages in the statements.

**Solution:**

After analysing the given statements, the Venn diagram formed is,

Clearly,

Some kind are sages follows.

Some kind are artists follows.

- (a)Only I and III
- (b)Only II, III and IV
- (c)All
- (d)Only III and IV
- (e)None of these

**Hint**

There is no direct relation given between the sets 'foolish' and 'clever'.

**Solution:**

We can draw the following Venn diagram based on the statements:

Clearly, there are two possibilities, and even though all foolish (persons) being clever is a possibility, it is not a definite case. Therefore, it is not logically valid.

The foolish (persons) who are kings will definitely be clever as all kings are clever. Therefore, both II and III are logically valid.

Since some foolish (persons) are kings, we can definitely say that some kings are foolish (persons) and therefore, IV is also logically valid.

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- (a)Mother
- (b)Sister
- (c)Daughter
- (d)Aunt
- (e)None of these

**Hint**

Only daughter of Saroj's mother is Saroj herself.

**Solution:**

According to the question, Priyanka's mother is the only daughter of Saroj's mother. Assuming that Saroj is female, we can use the following family tree to represent this:

Thus, Saroj is the mother of Priyanka.

- (a)Daughter
- (b)Sister
- (c)Maternal grand mother
- (d)Aunt
- (e)None of these

**Hint**

The child's maternal uncle is the only son of Narendra's maternal grandfather.

**Solution:**

According to the question, the brother of the child's mother is the only son of Narendra's mother's father. i.e. the child's maternal uncle is the only son of Narendra's maternal grandfather. We can use the following diagram to represent this:

The child's maternal uncle is also the maternal's uncle of Narendra. Now, we cannot determine whether they are siblings or cousins because we do not know how many daughters their maternal grandfather has. Since 'cousin' is not one of the options, we can say that the child is Narendra's sister.

- (a)Sister
- (b)Maternal aunt
- (c)Niece
- (d)Cousin
- (e)None of these

**Hint**

The only son of Kaushal's grandfather will be Kaushal's father.

**Solution:**

According to the given information, the lady in the photograph is the daughter of the daughter of the only son of Kaushal's grandfather.

So, the only son of Kaushal's grandfather is Kaushal's father. The daughter of Kaushal's father is Kaushal's sister. The daughter of Kaushal's sister is Kaushal's niece.

So, the following family tree can be drawn:

Therefore, the lady in the photograph is Kaushal's niece.

Hence, the correct answer is Niece.

- (a)Mother
- (b)Sister
- (c)Aunt
- (d)Sister-in-law
- (e)None of these

**Hint**

Manju is the daughter-in-law of Gaurav's grandfather.

**Solution:**

According to the question, Manju is the wife of the only son of Gaurav's father's father.

The only son of Gaurav's father's father is Gaurav's father and therefore, Manju is the mother of Gaurav.

- (a)Husband
- (b) Son
- (c)Father
- (d)Maternal uncle
- (e)None of these

**Hint**

Maternal uncle's son is cousin.

**Solution:**

According to question

The only son of the maternal grandfather of the lady is the maternal uncle of the lady and this maternal uncle is the father of the brother of the man in photograph. Hence the man in the photograph is the maternal cousin of the lady.

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- (a)$\frac{1}{1760}$
- (b)$76$
- (c)$176$
- (d)$186$
- (e)None of these

**Hint**

Convert the artificial signs into actual signs and then simplify according to the rule BODMAS.

**Solution:**

As given equation is

$\Rightarrow $$13-12\xf7400+20\times 100$

After putting the actual signs for artificial signs

$\Rightarrow $$13$ $\times $ $12$$+$ $400$ $\xf7$ $20$$-$$100$

$\Rightarrow $ $156$ $+$ $20$$-$$100$

$\Rightarrow $$176$$-$$100$

$\Rightarrow $ $76$

- (a)$51$
- (b)$45$
- (c)$34$
- (d)$64$
- (e)None of these

**Hint**

If $-$ means $\xf7$, then $12-4$ will be $12\xf74$. So the result is $3$.

**Solution:**

The given equation is,

$12-4\times 7+8\xf75$

After putting the actual signs for artificial signs,

$\Rightarrow 12\xf74+7\times 8-5$

$\Rightarrow 3+56-5$

$\Rightarrow 54$

- (a)$31$
- (b)$\frac{29}{2}$
- (c)$\frac{43}{2}$
- (d)$15$
- (e)None of these

**Hint**

$\times $ means $+$, so the value$16\times 2$ will be $16+2=18$.

**Solution:**

According to the given information:

$+$ means $\times $,

$\times $ means $+$,

$-$ means $\xf7$, and

$\xf7$ means $-$, thenThe given expression is- $16\times 2\xf74+7-8$

After replacing the coded signs with the actual ones, we get,

$16+2-4\times 7\xf78=?$

$\Rightarrow 18-4\times \frac{7}{8}=?$

$\Rightarrow 18-\frac{7}{2}=?$

$\Rightarrow ?=\frac{36-7}{2}$

$\Rightarrow ?=\frac{29}{2}$

Hence, the correct answer is $\frac{29}{2}.$

- (a)$34$
- (b)$16$
- (c)$-14$
- (d)$24$
- (e)None of these

**Hint**

$-$ means $\times $, so $6-4$ will be $6\times 4=24$.

**Solution:**

The given expression is- $64+8\xf76-4\times 2$

Replacing the coded signs with the actual signs, we get,

$64\xf78-6\times 4+2=?$

$\Rightarrow 8-24+2=?$

$\Rightarrow ?=-14$

- (a)$3$
- (b)$-5$
- (c)$35$
- (d)$16$
- (e)None of these

**Hint**

If $\times $ means $\xf7$, then $48\times 4$ will be written as $48\xf74$.

**Solution:**

The given equation is,

$\Rightarrow 48\times 4\xf77+8-2$

After putting the actual signs for artificial signs,

$\Rightarrow 48\xf74+7-8\times 2$

$\Rightarrow 12+7-16$

$\Rightarrow 3$

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- (a)A
- (b)B
- (c)C
- (d)D
- (e)E

**Hint**

To obey any official notice is mandatory.

**Solution:**

After brainstorming with given data, we find that there will be a talk on some particular fact. So, all the officers will assemble in the conference hall to attend the notice.

So only assumption I is implicit.

- (a)A
- (b)B
- (c)C
- (d)D
- (e)E

**Hint**

Collateral security must equal or more value than 1,80,000 rupees to have a loan.

**Solution:**

After brainstorming with the given data, we find that the bank can allow a person a loan of 1 lakh and above on collateral security for a certain period. So, Saroj may be granted a loan by the bank by mortgaging his house.

So, all three assumptions are implicit.

- (a)
None is implicit

- (b)
All are implicit

- (c)
Only III is implicit

- (d)
Either I or II is implicit

- (e)Both I and III are implicit

**Hint**

Training increases the efficiency of the work.

**Solution:**

Given Statement: Training must be given to all the employees for increasing productivity and profitability.

After brainstorming with the given data, we can find that trained employees only can pay due attention to the policy of productivity and profitability. It is hard to expect profitability unless the employees pay attention to productivity. So these are supplementary to each other.So. all three assumptions are implicit.

Hence, the correct answer is All are implicit.

- (a)A
- (b)B
- (c)C
- (d)D
- (e)E

**Hint**

To complete the work within the given time, we need to work longer hours some time.

**Solution:**

After brainstorming with the given data, we can find that:

(1) The proposal for extending working hours would have been made with the consultation of all the members.

(2) It became necessary to extend the working hours due to heavy load of work

On comparing these with the two given assumptions, it seems that only assumption II is implicit.

- (a)Only I is implicit
- (b)Only II is implicit
- (c)Either I or II is implicit
- (d)Neither I nor II is implicit
- (e)Both are implicit

**Hint**

Payscale is a prime factor for job satisfaction of the workers.

**Solution:**

The fact that A wishes to conduct such a study the degree of effect of pay revision on job satisfaction of employees means the following:

The relation between pay scale revision and job satisfaction can be measured or estimated. A wouldn't be interested in conducting the study otherwise.

A has the capacity to study such a topic since he wouldn't have told B if he felt he is incapable of carrying out the work.Therefore, both assumptions I and II are implicit.

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- (a)27
- (b)28
- (c)25
- (d)Cannot be determined
- (e)None of these

**Hint**

Total no. of boys = {(Raman’s place from the right) + (Raman’s place from the left)} — 1

**Solution:**

According to the given information in the question, Raman is 14th from the right and 13th from the left. This means that there are 13 boys to the right of Raman and 12 boys to the left of Raman.

Total no. of boys = {(Raman’s place from the right) + (Raman’s place from the left)} — 1

Total no. of boys = 14 + 13 – 1 = 26

- (a)21
^{st} - (b)22
^{nd} - (c)23
^{rd} - (d) 24
^{th} - (e)None of these

**Hint**

Total no. of students = {(Raman’s place from upwards) + (Raman’s place from downwards)} — 1

**Solution:**

According to the given information in the question, Raman is 9th from downwards in a class. So, there are 8 students below Raman.

Total no. of students = {(Raman’s place from the top) + (Raman’s place from the bottom)} — 1

31 = Raman’s place from the top + 9 – 1

Raman’s place from the top = 31 – 9 + 1 = 23Therefore, Raman’s is 23rd from upwards.

- (a)44th
- (b)45th
- (c)46th
- (d)Data inadequate
- (e)None of these

**Hint**

Total no. of students = {(Mohan’s place from downwards) + (Mohan's place from upwards)} — 1

**Solution:**

According to the given information in the question, Mohan is 21st from upwards in a class.

Total no. of students = {(Mohan's place from downwards) + (Mohan's place from upwards)} — 1

65 = (Mohan's place from downwards) + 21 – 1

Mohan's place from downwards = 65 – 21 + 1 = 45Therefore, Mohan's place from downwards is 45th.

- (a)48
- (b)49
- (c)50
- (d)Cannot be determined
- (e)None of these

**Hint**

Total no. of boys who passed = {(Rohan’s place from downwards) + (Rohan's place from upwards)} — 1

**Solution:**

According to the given information in the question, Rohan is 11th from upwards and 27th from downwards among the boys who passed in a class. Also, it is given that 12 boys failed in the class.

Total no. of boys who passed = {(Rohan's place from downwards) + (Rohan's place from upwards)} — 1

Total no. of boys who passed = 27 + 11 – 1 = 37Total no. of boys = Number of boys who passed + Number of boys who failed = 37 + 12 = 49

- (a)30
- (b) 29
- (c)32
- (d)31
- (e)None of these

**Hint**

Total no. of boys = {(Ganesh’s first position) +( Rajan's second position)}-1

**Solution:**

According to the given information in the question, we have to find out the total no. of boys in a line.

It is given that, Ganesh is 12th from the left and Rajan is 15th from the right. After interchanging their positions, Rajan is 20th from the right.

So, we know that Total no. of boys = {(Ganesh's first position) + (Rajan's second position)} - 1

Hence, Total no. of boys in a class = 12 + 20 - 1 = 31

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- (a)None
- (b)Two
- (c)One
- (d)Three

**Hint**

When the digits are arranged in descending order, the number becomes 8765431.

**Solution:**

When the digits are arranged in descending order, the number becomes 8765431.

After comparing 6315784 and 8765431, we can see that there are three pairs (7,8), (1,3) and (3,5), that has as many digits between them in the number as when the digits are rearranged in descending order.

Hence, the correct answer is three.

- (a)0
- (b)3
- (c)4
- (d)6

**Hint**

While reversing series, Positions of number changes from left to right or vice versa.

**Solution:**

Given series,

7, 3, 9, 7, 0, 3, 8, 4, 6, 2, 1, 0, 5, 11, 13

When written in the reverse order :

13, 11, 5, 0, 1, 2, 6, 4, 8, 3, 0, 7, 9, 3, 7

Then 7th number from the left is 6 and 4th number to the right of 6 is 0.

- (a)None
- (b)One
- (c)Two
- (d)Three

**Hint**

Immediately preceded means just before and immediately followed means just after.

**Solution:**

According to given question

2 6 3 7 5 6 4 2 9 6 1 3 4 1 [6] 3 9 1 5 [6] 9 2 3 1 6 5 4 3 2 1 9 6 7 1 [6] 3

Hence only three 6s (in brackets) are there which are immediately preceded by 1 or 5 and immediately followed by 3 or 9.

- (a)One
- (b)Two
- (c)Four
- (d)Six

**Hint**

Immediately preceded means just before.

**Solution:**

According to given question

7 4 2 7 6 4 3 6 [7] 5 3 5 7 8 4 3 7 6 [7] 2 4 0 6 7 4 3

Hence only two 7s (in brackets) are there which are immediately preceded by 6 but not immediately followed by 4.

- (a)1
- (b)3
- (c)6
- (d)None of these

**Hint**

After rearranging the given number according to the directions in the question, the new number formed is 49138657.

**Solution:**

After rearranging 94316875 according to the directions in the question, the new number formed is 49138657.

The seventh digit from the left end of this new number is 5, and the third digit to the left of 5 is 3.

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### Importance of Mental Ability Tests

Practice Now#### Question-wise Difficulty Level Summary

Additionally, we tag all questions of any book to difficulty, ranging from 1 to 10. This tagging helps create personalised learning paths based on the performance of the student.

The table given below shows the difficulty tagged to the questions of this textbook -

Difficulty | No. of Questions |
---|---|

Easy | 219 |

Medium | 116 |

Hard | 0 |

## Why is the Mental Ability Tests Important?

Exam Name |
---|

SBI Clerk Mains |

IBPS Clerk Prelims |

UPSC CAPF AC Paper I |

IRDAI Assistant Manager |

IDBI Bank Executive |

SBI Clerk Prelims |

Goa Police SI |

Delhi Police MTS |

IBPS RRB Officer Scale-I Prelims |

NICL AO Prelims |

South Indian Bank PO |

Bihar Cooperative Bank Assistant Manager Prelims |

ESIC SSO Mains |

IBPS PO Mains |

SBI PO Mains |

NIACL AO Prelims |

IBPS PO Prelims |

IBPS RRB Office Assistant Mains |

IBPS Clerk Mains |

UIIC Assistant Prelims |

ESIC UDC Preliminary Exam |

IBPS RRB Office Assistant Prelims |

SBI PO Prelims |

Bihar Cooperative Bank Assistant Prelims |

IDBI Assistant Manager |

UP Police Constable |

OICL AO Prelims |

SBI Apprentice |

RBI Grade B Phase I |

NABARD Development Assistant Prelims |

Andhra Pradesh State Cooperative Bank PO |

IBPS RRB Officer Scale-I Mains |