Given matrix $\mathrm{B}=\left[\begin{array}{ll}1& 1\\ 8& 3\end{array}\right].$ Find the matrix $\mathrm{X}$  if, $\mathrm{X}={\mathrm{B}}^2-4\mathrm{B}.$ Hence, solve for $\mathrm{a}$ and $\mathrm{b}$ given. $\mathrm{X}\left[\begin{array}{l}\mathrm{a}\\ \mathrm{b}\end{array}\right]=\left[\begin{array}{c}5\\ 50\end{array}\right].$

If $\mathrm{A}$ and $\mathrm{B}$ are two matrices of orders $3\times 2$ and $2\times 3$ respectively; then their sum$\mathrm{A}+\mathrm{B}$is possible.

The matrices ${\mathrm{A}}_{2\times 3}$ and ${\mathrm{B}}_{2\times 3}$ are conformable for subtraction.

Transpose of a$2\times 1$ matrix is a$2\times 1$ matrix.

Transpose of a square matrix is a square matrix.

A column matrix has many columns and only one row.

Solve for $\mathrm{a}, \mathrm{b}$ and$\mathrm{c}$; if :

$\left[\begin{array}{cc}-4& \mathrm{a}+5\\ 3& 2\end{array}\right]=\left[\begin{array}{cc}\mathrm{h}+4& 2\\ 3& \mathrm{c}-1\end{array}\right]$

Solve for $\mathrm{a}, \mathrm{b}$ and$\mathrm{c}$; if :

$\left[\begin{array}{cc}\mathrm{a}& \mathrm{a}-\mathrm{b}\\ \mathrm{b}+\mathrm{c}& 0\end{array}\right]=\left[\begin{array}{cc}3& -1\\ 2& 0\end{array}\right]$