Poisson Distribution

If $m$ is the parameter of the Poisson distribution then the variance of the distribution is

A random variable $X$ has Poisson distribution with mean $2.$ Then $P\left(X\ge 2\right)$ equals

If $x$ is Poisson variate and $P\left(x=0\right)=P\left(x=1\right),$ then $P\left(x=2\right)=$

$3\%$ of the electric bulbs manufactured by a company are defective. Using Poisson distribution (approximation), the probability that a sample of 100 bulbs will contain exactly one defective is

(Given antilog $\left(0·1742\right)=1·5$)

Suppose that $X$ has a Poisson distribution. If $P\left(X=1\right)=0·3,$ and $P\left(x=2\right)=0·2$ then $P\left(X=0\right)=$