Bidyut Guha Thakurta and Amitava Mitra Solutions for Exercise 1: EXERCISE 5
Bidyut Guha Thakurta Mathematics Solutions for Exercise - Bidyut Guha Thakurta and Amitava Mitra Solutions for Exercise 1: EXERCISE 5
Attempt the practice questions from Exercise 1: EXERCISE 5 with hints and solutions to strengthen your understanding. SCHOOL MATHEMATICS Class 10 solutions are prepared by Experienced Embibe Experts.
Questions from Bidyut Guha Thakurta and Amitava Mitra Solutions for Exercise 1: EXERCISE 5 with Hints & Solutions
The heights of a sphere and a right circular cylinder are the same. If their volumes are equal, the ratio of square of the radii of the sphere and the cylinder is _____.

By melting a solid right circular cylinder, a solid right circular cone of same height as the cylinder is made. The ratio of the radii of the cylinder and the cone is _____

The length of a cylinder is and the radius of its cross-section is . If the volume be equal to that of the sphere of the same radius, then the relation between and is _____.

The number of spherical solids each in radius that can be cast from a solid iron cylinder of radius and height , is .

The two radii and the volumes of a sphere and a right circular cylinder are the same. The ratio of the height and the radius of the cylinder is .

A rectangular paper sheet is of length . It is folded to form a hollow right circular cylinder such that the breadth of the paper becomes the height of the cylinder. The radius of the greatest cylinder is .

The percentage increase in the volume of a solid hemisphere if its radius is doubled, is .

A sphere of the greatest size is kept inside a cubical box. If the internal dimension of the box be x unit, then the volume of sphere is cu. units.
