No Author Solutions for Exercise 5: EXAM GALLERY

The statement $~(p\wedge q)\vee q$

If $x^n=a_0+a_1\left(1+x\right)+a_2{\left(1+x\right)}^2+\dots +a_n{\left(1+x\right)}^n=b_0+b_1\left(1-x\right)+b_2{\left(1-x\right)}^2+\dots +b_n{\left(1-x\right)}^n$, then for $n=101, \left(a_{50},b_{50}\right)$ equals to

A particle is constrained to move along the curve $y=\sqrt{x}$ starting at the origin at time $t=0.$ The point on the curve where abscissa and the ordinate are changing at the same rate is

The sum of the numbers between $200$ and $400$ that are divisible by $7$, is

If $\overrightarrow{b}=\hat{i}-\hat{j}+3\hat{k}, \overrightarrow{c}=\hat{j}+2\hat{k}$ and $\overrightarrow{a}$ is a unit vector, then the maximum value of the scalar triple product $\left[\overrightarrow{a} \overrightarrow{b} \overrightarrow{c}\right]$ is

The mid-point of the chord intercepted by the circle $x^2+y^2=16$ on the line through the points $\left(1,-2\right)$ and $\left(0,-1\right)$ is

The domain of the function $f\left(x\right)=\frac{1}{3-{\log }_3(x-3)}$ is

$ABC$ is an equilateral triangle such that the vertices $B$ and $C$ lie on two parallel lines at a distance $6$. If $A$ lies between the parallel lines at a distance $4$  from one of them, then the length of a side of the equilateral triangle is