Name: Equally Likely Outcomes of an Experiment
Uploaded: 2019-07-19
Duration: 1 min 59 s
Description: In this video, we will understand the concept of equally likely outcomes in probability with the help of some examples. Hit on the play button to know more.

Question

The following data represents the different type of animals and their numbers in a zoo. Prepare a pie chart for the given data.

Animals	Number of animals
Deer	$42$
Elephants	$15$
Giraffe	$26$
Reptiles	$24$
Tiger	$13$

Accepted Answer

Given data represents the different types of animals and their numbers in a zoo.

For preparing a pie chart for the given data, use the following steps.

Step $1$ : Obtain the data and find the sum of various component values.

Step $2$ : Divide each component value by the sum obtained in step $1$ and multiply by $360 °$ to obtain the sector angles (central angles) of the sectors represented by them.

Central angle of a component $= {(\frac{Value of the component}{Sum of the all component values} \times 360)}^{°}$

Animals Number of animals Central angles

Deer $42$ ${(\frac{42}{120} \times 360)}^{°} = 126 °$

Elephants $15$ ${(\frac{15}{120} \times 360)}^{°} = 45 °$

Giraffe $26$ ${(\frac{26}{120} \times 360)}^{°} = 78 °$

Reptiles $24$ ${(\frac{24}{120} \times 360)}^{°} = 72 °$

Tiger $13$ ${(\frac{13}{120} \times 360)}^{°} = 39 °$

Total $120$ $360 °$

Step $3$ : Draw a circle of appropriate size with a compass and mark its radius.

Step $4$ : Let's take the first central angle i.e., $126 °$ and construct $126 °$ using a protractor on the marked radius in Step $3$ .

Step $5$ : Construct other sectors representing other components in the similar manner.

Step $6$ : Add explanatory or descriptive label inside each sector, so that they can be easily identified. If it is not possible to place the labels inside the sectors due to lack of space, then labels can be placed in continuous positions outside the circle, usually with an arrow pointing to the appropriate sector.

Thus, we have the pie chart as follows:

Item head	Road	Electricity	Drinking Water	Sewerage
Amount (in crore Rs)	$43.2$	$16.2$	$27.0$	$21.6$

Items	Wheat	Rice	Tea
Production(in metric tonnes)	$1840$	$3260$	$900$

Students	Professionals	Government servants	Businessman	Housewife
$45 %$	$30 %$	$13 %$	$10 %$	$2 %$

Abhishek Chauhan and Vivek Singhal Solutions for Chapter: Data Handling, Exercise 2: Topic Exercise 5.2

Abhishek Chauhan Mathematics Solutions for Exercise - Abhishek Chauhan and Vivek Singhal Solutions for Chapter: Data Handling, Exercise 2: Topic Exercise 5.2

Questions from Abhishek Chauhan and Vivek Singhal Solutions for Chapter: Data Handling, Exercise 2: Topic Exercise 5.2 with Hints & Solutions

Learn and Prepare for any exam you want !