Faraday's Law of Electrolysis

Author:Embibe Experts
JEE Main/Advance
IMPORTANT

Important Questions on Faraday's Law of Electrolysis

HARD
IMPORTANT

Find out the volume of gases evolved by passing 0.965 A current for 1hr through an aqueous solution of CH3COONa  at 25°C and 1 atm.

EASY
IMPORTANT

A current of 9.65 ampere is passed through the aqueous solution NaCl using suitable electrodes for 1000 s. The amount of NaOH formed during electrolysis is:

MEDIUM
IMPORTANT

A current of 2 A was passed for 1 h through a solution of CuSO4. 0.237 g of Cu2+ ions were discharged at cathode. The current efficiency is:

MEDIUM
IMPORTANT

Three faradays of electricity was passed through an aqueous solution of iron II bromide. The mass of iron metal (at. mass 56) deposited at the cathode is -

EASY
IMPORTANT

Electrolysis of a solution of HSO4- ions produces S2O8-- Assuming 75% current efficiency, what current should be employed to achieve a production rate of 1 mole of S2O8-- per hour ?

MEDIUM
IMPORTANT

A current of 2.68 A is passed for one hour through an aqueous solution of CuSO, using copper electrodes. Select the correct statement(s) from the following:

HARD
IMPORTANT

How long (approximate) should water be electrolysed by passing through 100 amperes current so that the oxygen released can completely burn 27.66 g of diborane? (Atomic weight of B=10.8 u)

HARD
IMPORTANT

A current of 5.0 A flows for 4.0 h through an electrolytic cell containing a molten salt of metal M. This results in deposition of 0.25 mol of the metal M at the cathode. The oxidation state of M in the molten salt is (1 Faraday =96485 C mol-1)

EASY
IMPORTANT

The salts of A (atomic mass 15 ), B (atomic mass 27 ) and C (atomic mass 48 ) were electrolysed using same amount of charge. It was found that when 4.5 g of A was deposited, the mass of B and C deposited were 2.7 g and 9.6 g.The valencies of A, B and C, respectively.

MEDIUM
IMPORTANT

How many faradays are required to reduce one mol of MnO4- to Mn2+

EASY
IMPORTANT

The amount of copper (At. wt. 63.54 ) deposited by passing 0.2 faraday of electricity through copper sulphate is

MEDIUM
IMPORTANT

An electric current is passed through a silver voltameter connected to a water voltameter. 0.324 g of silver was deposited on the cathode of the silver voltameter. The volume of oxygen evolved at NTP is :

HARD
IMPORTANT

One of the methods of preparation of per disulphuric acid, H2S2O8, involve electrolytic oxidation of H2SO4 at anode 2H2SO4H2S2O8+2H++2e- with oxygen and hydrogen as by-products. In such an electrolysis, 9.722 L H2 of and 2.35 L O2 were generated at STP . What is the weight of H2S2O8 formed'?

MEDIUM
IMPORTANT

The quantity of electricity which deposits 1.08 g of silver from AgNO3 solution is:

HARD
IMPORTANT

Three moles of electrons are passed through three solutions in succession containing AgNO3, CuSO4 and AuCl3, respectively. The molar ratio of amounts of cations reduced at cathode will be:

EASY
IMPORTANT

Four moles of electrons were transferred from anode to cathode in an experiment on electrolysis of water. The total volume of the two gases (dry and at STP) produced will be approximately (in litres).

EASY
IMPORTANT

During the preparation of H2S2O8 (per disulphuric acid) O2 gas also releases at anode as byproduct. When 9.72 L of H2 releases at cathode and 2.35 L O2 at anode at STP, the weight of H2S2O8 produced in gram is:

MEDIUM
IMPORTANT

Electrolysis of a solution of MnSO4 in aqueous sulphuric acid is a method for the preparation of MnO2. Passing a current of 27 A for 24 hours gives 1 kg of MnO2. The current efficiency in this process is:

MEDIUM
IMPORTANT

One g equivalent of Na metal is formed from electrolysis of fused NaCl. No. of moles of Al from the fused Na3 AlF6 with the same current passed is:

HARD
IMPORTANT

A current of 0.5 ampere, when passed through AgNO3 solution for 193 seconds, deposited 0.108 g of Ag. The equivalent weight of Ag is: