Embibe Experts Solutions for Chapter: Some Basic Concepts of Chemistry, Exercise 4: Exercise 4

If $0.5 \mathrm{moles}$ of ${\mathrm{BaCl}}_2$ are mixed with $0.2 \mathrm{moles}$ of ${\mathrm{Na}}_3{\mathrm{PO}}_4$, the maximum number of moles of ${\mathrm{Ba}}_3({\mathrm{PO}}_4{)}_2$ that can be formed, is

In a hydrocarbon, mass ratio of hydrogen and carbon is $1:3$  the empirical formula of hydrocarbon is 

The mole fraction of the solute in one molal aqueous solution is

The amount of sugar $\left({\mathrm{C}}_{12}{\mathrm{H}}_{22}{\mathrm{O}}_{11}\right)$ required to prepare $2 \mathrm{L}$of its $0.1 \mathrm{M}$ aqueous solutions is: 

A mixture of $100 \mathrm{m}$ mol of $\mathrm{Ca}(\mathrm{OH}{)}_2$and $2 \mathrm{g}$of sodium sulphate was dissolved in water and the volume was made up to $100 \mathrm{mL}$. The mass of calcium sulphate formed and the concentration of ${\mathrm{OH}}^{-}$ in resulting solution are: Molar mass of $\mathrm{Ca}(\mathrm{OH}{)}_2, {\mathrm{Na}}_2{\mathrm{SO}}_4$ and ${\mathrm{CaSO}}_4$are $74,143$ and $136 \mathrm{g}$ ${\mathrm{mol}}^{-1}$ and ${\mathrm{K}}_{\mathrm{sp}}$ of $\mathrm{Ca}(\mathrm{OH}{)}_2$ is $5.5\times {10}^{-6}$ respectively.

An organic compound is estimated through Dumas method and was found to evolve $6 \mathrm{moles}$ of ${\mathrm{CO}}_2, 4 \mathrm{moles}$ of ${\mathrm{H}}_2\mathrm{O}$ and $1 \mathrm{mole}$ of nitrogen gas. The formula of the compound is:  

A $10 \text{mg}$ effervescent tablet containing sodium bicarbonate and oxalic acid releases $0.25 \mathrm{ml}$of ${\mathrm{CO}}_2$when $\mathrm{T}= 298.15 \mathrm{K}$ and $\mathrm{P}=1 \mathrm{bar}$. If molar volume of ${\mathrm{CO}}_2$is $25.0 \mathrm{L}$ under such condition, what will be the percentage of sodium bicarbonate in each tablet?
[Molar mass of ${\mathrm{NaHCO}}_3=84 \mathrm{g} {\mathrm{mol}}^{-1 }$] 

$8 \mathrm{g}$of $\mathrm{NaOH}$is dissolved in $18 \mathrm{g}$of ${\mathrm{H}}_2\mathrm{O}$. Mole fraction of $\mathrm{NaOH}$in solution and molality ($\mathrm{mol} {\mathrm{kg}}^{-1}$) of the solution respectively are: