Embibe Experts Solutions for Chapter: Mechanics of Solids and Fluids, Exercise 1: Exercise 1

In Poiseuilli's method of determination of coefficient of viscosity, the physical quantity that requires greater accuracy in measurement is

According to Newton, viscous force is given by

$F=-\eta A\frac{dv}{dx}$

where $\eta =$ coefficient of viscosity, so dimensions of $\eta$ will be :

The work done in blowing a soap bubble of $10 \mathrm{cm}$ radius is $($surface tension of the soap solution is $\frac{3}{\mathrm{100}} \mathrm{N} {\mathrm{m}}^{-1}$​$)$

The radii of two soap bubbles are $r_1$ and $r_2$. In isothermal conditions, two meet together in a vacuum. Then the radius of the resultant bubble is given by:

If work done to make a bubble of volume $V$ with soap solution is $W$, then using same solution work done to make a bubble of volume $2V$ is :

The force required to drag a circular ring flat plate of radius $5 \mathrm{cm}$ on the surface of water is (ST of water is $75$ dyne/cm):

The work done in increasing the size of a rectangular soap film with dimensions $8 \mathrm{cm}\times 3.75 \mathrm{cm}$ to $10 \mathrm{cm}\times 6 \mathrm{cm}$ is $3\times {10}^{-4} \mathrm{J}.$ The surface tension of film is :

A thin liquid film formed between a U-shaped wire and a light slider supports a weight of $2.0\times {10}^{-2} \mathrm{N}$ (see figure). The length of the slider is $10 \mathrm{cm}$ and its weight negligible. The surface tension of the liquid film is :