Embibe Experts Solutions for Chapter: Electromagnetic Induction, Exercise 2: Exercise-2

The radius of the circular conducting loop shown in the figure is $R$. The magnetic field is decreasing at a constant rate $\alpha$. Resistance per unit length of the loop is $\rho$. Then current in the wire $AB$ is ($AB$ is one of the diameters)

In an $LR$ circuit current at $t=0$ is $20 \mathrm{A}.$ After $2 \mathrm{s}$ it reduces to $18 \mathrm{A}$. The time constant of the circuit is (in second);

In the circuit shown in the figure, switch $S$ is closed at $t=0$. Then:

The battery shown in the figure is ideal: The values are $\epsilon =10 \mathrm{V},R=5\mathrm{\Omega },L=2\mathrm{H}.$Initially the current in the inductor is zero. The current through the battery at $t=2s$ is

When two co-axial coils having same current in same direction are brought to each other, then the value of current in both coils :

A coil of inductance $300 \mathrm{mH}$ and resistance $2 \mathrm{\Omega }$ is connected to a source of voltage $2 \mathrm{V}$. The current reaches half of its steady state value in

If a bar magnet is dropping through the copper ring, then its velocity (gravity-free space):

The unit of mutual inductance of a coil can be expressed as :