D. C. Pandey Solutions for Chapter: Laws of Thermodynamics, Exercise 5: Exercises

Author:D. C. Pandey

D. C. Pandey Physics Solutions for Exercise - D. C. Pandey Solutions for Chapter: Laws of Thermodynamics, Exercise 5: Exercises

Attempt the practice questions on Chapter 5: Laws of Thermodynamics, Exercise 5: Exercises with hints and solutions to strengthen your understanding. Understanding Physics JEE Main & Advanced WAVES AND THERMODYNAMICS solutions are prepared by Experienced Embibe Experts.

Questions from D. C. Pandey Solutions for Chapter: Laws of Thermodynamics, Exercise 5: Exercises with Hints & Solutions

MEDIUM
JEE Advanced
IMPORTANT

The temperature of a monatomic gas is increased from T0 to 2T0 in three different processes such as isochoric, isobaric and adiabatic. Heat given to the gas in these three processes are Q1Q2 and Q3, respectively. Then, choose the correct option.

MEDIUM
JEE Advanced
IMPORTANT

A cyclic process 1-2-3-4-1 is depicted on V-T diagram. The p-T and p-V diagrams for this cyclic process are given below. Select the correct choices (more than one options is/are correct)

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EASY
JEE Advanced
IMPORTANT

One mole of a monatomic ideal gas is taken along the cycle ABCA as shown in the diagram.

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The ratio of specific heat in the process CA to the specific heat in the process BC is

MEDIUM
JEE Advanced
IMPORTANT

One mole of a monoatomic ideal gas is taken through the cycle ABCDA as shown in the figure.

TA=1000 K and 2pA=3pB=6pC

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The temperature at B is

Assume 230.4=0.85 and R=253J K-1 mol-1

MEDIUM
JEE Advanced
IMPORTANT

One mole of a monoatomic ideal gas is taken through the cycle ABCDA as shown in the figure.

TA=1000 K and 2pA=3pB=6pC

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Work done by gas in the process AB is

Assume 230.4=0.85 and R=253J K-1 mol-1

MEDIUM
JEE Advanced
IMPORTANT

One mole of a monoatomic ideal gas is taken through the cycle ABCDA as shown in the figure.

TA=1000 K and 2pA=3pB=6pC

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Heat lost by the gas in the process BC is

Assume 230.4=0.85 and R=253J K-1 mol-1

HARD
JEE Advanced
IMPORTANT

The pressure versus temperature (p-T) graph of n moles of an ideal gas is shown in the figure. Plot the corresponding,
(a) density versus volume (ρ-V) graph
(b) pressure versus volume (p-V) graph and
(c) density versus pressure (ρ-p) graph.

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HARD
JEE Advanced
IMPORTANT

Three moles of an ideal gas being initially at a temperature Ti=273 K were isothermally expanded 5 times its initial volume and then isochorically heated so that the pressure in the final state becomes equal to that in the initial state. The total heat supplied in the process is 80 kJ. Find γ =CpCV of the gas.