Amit M Agarwal Solutions for Chapter: dy/dx as a Rate Measurer & Tangents, Normals, Exercise 3: Proficiency in 'dy/dx as a Rate Measurer & Tangents, Normals' Exercise 1

Author:Amit M Agarwal

Amit M Agarwal Mathematics Solutions for Exercise - Amit M Agarwal Solutions for Chapter: dy/dx as a Rate Measurer & Tangents, Normals, Exercise 3: Proficiency in 'dy/dx as a Rate Measurer & Tangents, Normals' Exercise 1

Attempt the practice questions on Chapter 7: dy/dx as a Rate Measurer & Tangents, Normals, Exercise 3: Proficiency in 'dy/dx as a Rate Measurer & Tangents, Normals' Exercise 1 with hints and solutions to strengthen your understanding. Skills in Mathematics Differential Calculus for JEE Main & Advanced solutions are prepared by Experienced Embibe Experts.

Questions from Amit M Agarwal Solutions for Chapter: dy/dx as a Rate Measurer & Tangents, Normals, Exercise 3: Proficiency in 'dy/dx as a Rate Measurer & Tangents, Normals' Exercise 1 with Hints & Solutions

HARD
JEE Main
IMPORTANT

The parabola y=x2+px+q intercepts the straight line y=2x-3 at a point with abscissa 1. If the distance between the vertex of the parabola and the x-axis is least, then:

HARD
JEE Main
IMPORTANT

The abscissa of the point on the curve xy=a+x, the tangent at which cuts off equal intercepts from the coordinate axes is a>0:

EASY
JEE Main
IMPORTANT

If the side of a triangle vary slightly da, db, dc in such a way that its circumradius remains constant, then dacosA+dbcosB+dccosC is equal to

HARD
JEE Main
IMPORTANT

For the following questions, choose the correct answer from the options (a), (b), (c) and (d) defined as follows:
Statement I: f(x)=12-x,x<1212-x2,x12. Mean value theorem is applicable in the interval 0, 1
Statement II: For the application of mean value theorem, fx must be continuous
in 0, 1 and differentiable in 0, 1.

HARD
JEE Main
IMPORTANT

For the following questions, choose the correct answer from the options (a), (b), (c) and (d) defined as follows:
Let fx=ln2+x-2x+2x+3
Statement I: The function fx=0 has a unique solution in the domain of fx.
Statement II: If fx is continuous in a, b and is strictly monotonic in a, b,
then f has a unique root in a, b.

HARD
JEE Main
IMPORTANT

For the following questions, choose the correct answer from the options (a), (b), (c) and (d) defined as follows:
Consider the polynomial function
fx=x77-x66+x55-x44+x33-x22+x
Statement I: The equation fx=0 cannot have two or more roots.
Statement II: Rolle's theorem is not applicable for y=fx on any interval
a, b, where a, bR.