Supply the missing digits: + 8 * 7 * 3 2 * 4 * * 2 3 0

Given number is + 8 * 7 * 3 2 * 4 * * 2 3 0 From the sum of the numbers, If we add single digit number 6 to number 4 , we get 10 . So, we get 0 as unit place value. _____ + 4 = 10 = 6 + 4 = 10 Now, we add the carry digit to the next number and get, 7 + _____ = 3 ⇒ 7 + 5 + 1 = 13 Now, we add the carry digit to the next number and get, _____ + 2 = 2 ⇒ 9 + 2 + 1 = 12 Now, we add the carry digit to the next number and get, 8 + 3 + 1 = 12 Thus, the complete table is + 8 9 7 6 3 2 5 4 1 2 2 3 0

Supply the missing digits: - 8 9 4 5 * * 3 2 6 3 * *

Given numbers is - 8 9 4 5 * * 3 2 6 3 * * By applying subtraction operation, 5 - 2 = * ; 5 - 2 = 3 4 - 3 = * ; 4 - 3 = 1 9 - * = 3 ; 9 - 3 = 6 8 - * = 6 ; 8 - 6 = 2 Therefore, arranging the missing digits - 8 9 4 5 2 6 3 2 6 3 1 3

Supply the missing digits: 2 3 5 × * * * 1 0

Given number is 2 3 5 × * * * 1 0 If we consider the missing multiplier as 2 , we will get 0 at the unit place and we need to add the carry to the next product which would be 3 × 2 + 1 = 7 , does not give the given digit. So, let us consider the multiplier as 6 , we get 5 × 6 = 30 Now, carry 3 will be added to the next product. So, we get ( 3 × 6 ) + 3 = 18 + 3 = 21 Now, carry 2 will be added with the next product. So, we get ( 2 × 6 ) + 2 = 14 By arranging the digits, 2 3 5 × 6 1 4 1 0

E M B I B E

Essential ICSE Mathematics for Class 6>Numbers>Chapter 3 - Whole Numbers>EXERCISE 3A

Asit Das Gupta and Alok Kumar Solutions for Exercise 1: EXERCISE 3A

Author:Asit Das Gupta & Alok Kumar

Asit Das Gupta Mathematics Solutions for Exercise - Asit Das Gupta and Alok Kumar Solutions for Exercise 1: EXERCISE 3A

Attempt the free practice questions from Exercise 1: EXERCISE 3A with hints and solutions to strengthen your understanding. Essential ICSE Mathematics for Class 6 solutions are prepared by Experienced Embibe Experts.