B M Sharma Solutions for Chapter: Sources of Magnetic Field, Exercise 3: DPP

A cell is connected between the points $A$ and $C$ of a circular conductor $A B C D$ of Centre $O$ with angle $AOC=60°$. If $B_1$ and $B_2$ are the magnitudes of the magnetic fields at $O$ due to the currents in $A B C$ and $A D C$ respectively, the ratio $\frac{B_1}{B_2}$ is

In the given figure, net magnetic field at $O$ will be,

The unit vectors $\hat{i}$, $\hat{j}$ and $\hat{k}$ are as shown below. What will be the magnetic field at $O$ in the following figure?

(Current flowing through wire $=i$)

A straight wire of length $\left({\pi }^2\right)$  meter is carrying a current of $2 \mathrm{A}$ and the magnetic field due to it is measured at a point distant $1 \mathrm{cm}$ from it. If the wire is to be bent into a circle and is to carry the same current as before, the ratio of the magnetic field at its Centre to that obtained in the first case would be

For the current-carrying wire, show that the magnetic field at $P$ is,

$L$ is the circular ring made of a uniform wire. Current enters and leaves the ring through straight conductors which, if produced, would have passed through the centre $C$ of the ring. The magnetic field at $C$ is

Two circular coils $A$ and $B$ with their centres lying on the same axis have the same number of turns and carry equal currents in the same sense. They are separated by a distance, have different diameters but subtend the same angle at a point $P$ lying on their common axis. The coil $B$ lies exactly midway between coil $A$ and the point $P$. The magnetic field at point $P$ due to coils $A$ and $B$ is $B_1$ and $B_2$ respectively.

Figure shows a long wire bent at the middle to form a right angle.