B M Sharma Solutions for Chapter: Nuclear Physics, Exercise 2: DPP

The binding energy per nucleon is maximum in the case of,

The masses of neutrons and protons are $1.0087 \mathrm{amu}$and $1.0073 \mathrm{amu}$, respectively. If the neutrons and protons combine to form a Helium nucleus ($\text{α}$-particles) of mass $4.0015 \mathrm{amu}$, then, the binding energy of the Helium nucleus will be ($1 \mathrm{amu}=931 \mathrm{MeV}$),

The mass defect for the nucleus of helium is $0.0303 \mathrm{amu}$. What is the binding energy per nucleon for helium in $\mathrm{MeV}$?

$M_p$ denotes the mass of a proton and $M_n$ that of a neutron. A given nucleus, of binding energy $B$, contains $Z$ protons and $N$ neutrons. The mass $M\left(N, Z\right)$of the nucleus is given by ($c$ is the velocity of light)

The binding energy of deuteron ${}_1{}^2\mathrm{H}$ is $1.112 \mathrm{MeV}$ per nucleon and an $\text{α}$-particle ${}_2{}^4\mathrm{He}$ has a binding energy of $7.047 \mathrm{MeV}$ per nucleon. Then in the fusion reaction ${}_1{}^2\mathrm{H}{+}_1^2\mathrm{H}{\to }_2^4\mathrm{He}+Q,$ the energy $Q$ released is,

If the binding energy per nucleon in ${\mathrm{Li}}^7$and ${\mathrm{He}}^4$ nuclei are, respectively, $5.60 \mathrm{MeV}$ and $7.06 \mathrm{MeV}$ then energy of reaction ${\mathrm{Li}}^7+\mathrm{p}\to 2{\mathrm{He}}^4$ is,

The binding energy per nucleon of deuterium and helium atom is $1.1 \mathrm{MeV}$ and $7.0 \mathrm{MeV}$. If two deuterium nuclei fuse to form helium atom, the energy released is,

A nucleus of $\begin{array}{l}210\\ 82\end{array}\mathrm{Po}$ originally at rest emits $\text{α}$-particle with speed $\nu .$ What will be the recoil speed of the daughter nucleus?