BM Sharma Solutions for Chapter: Motion in One Dimension, Exercise 3: DPP

A particle travels $10\mathrm{ }\mathrm{m}$ in the first $5\mathrm{ }\sec$ and $10\mathrm{ }\mathrm{m}$ in the next $3\mathrm{ }\sec$. Assuming constant acceleration, what is the distance traveled in the next $2\mathrm{ }\sec$?

A particle starts from rest, accelerates at $2\mathrm{ }\mathrm{m} {\mathrm{s}}^{-2}$ for $10\mathrm{ }\mathrm{s}$ and then goes at a constant speed for $30 \mathrm{s}$ and then decelerates at $4\mathrm{ }\mathrm{m} {\mathrm{s}}^{-2}$ till it stops. What is the distance traveled by it?

A car starts from rest and moves with uniform acceleration $a$ on a straight road from time$t=0$to $t=T$. After that, a constant deceleration brings it to rest. In this process, the average speed of the car is

A body moving with uniform acceleration describes $40\mathrm{ }\mathrm{m}$ in the first $5\mathrm{ }\sec$ and $65\mathrm{ }\mathrm{m}$ in next $5\mathrm{ }\sec$. Its initial velocity will be

A car starting from rest, accelerates at a rate of $f$ through a distance $S$, then continues at a constant speed for time $t$ and then decelerates at a rate $\frac{f}{2}$ to come to rest. If the total distance traversed is $15S$, then

A man is $45\mathrm{ }\mathrm{m}$ behind the bus when the bus starts accelerating from rest with acceleration $2.5\mathrm{ }\mathrm{m} {\mathrm{s}}^{-2}$. With what minimum velocity should the man start running to catch the bus?

A car $A$ is travelling on a straight level road with a uniform speed of $60\mathrm{ }\mathrm{km} {\mathrm{h}}^{-1}$. It is followed by another car $B$ which is moving with a speed of $70\mathrm{ }\mathrm{km} {\mathrm{h}}^{-1}$. When the distance between them is $2.5\mathrm{ }\mathrm{km}$, the car $B$ is given a deceleration of $20 \mathrm{km} {\mathrm{h}}^{-2}$. After how much time will $B$ catch up with $A$?

The speed of a body moving with uniform acceleration is $u$. This speed is doubled while covering a distance $s$. When it covers an additional distance $s$, its speed would become