Measures of Central Tendency

The weighted mean of first $n$ natural numbers whose weights are equal, is:

If the mean of $n$ observations $1^2,2^2,3^2,......n^2$ is $\frac{46n}{11}$, then $n$ is equal to

Median of observations $x_{\mathit{i}}$ such that $\left(x_i^2-7x_i+12\right) \left(x_i^3-x_i^2-4x_i+4\right)=0$ will be :-

The median of $19$ observations of a group is $30$. If two observations with values $8$ and $32$ are further included, then the median of the new group of $21$ observation will be

If ${\overline{X}}_1$ and ${\overline{X}}_2$ are the means of two series such that ${\overline{X}}_1<{\overline{X}}_2$ and $\overline{X}$ is the mean of the combined series, then-

The mode of the following frequency distribution is:

Mode of the following frequency distribution

A series which have numbers three $4$'s, four $5$'s, five $6$'s, eight $7$'s, seven $8$'s and $9$'s, then the mode of numbers is

Median is independent of change of

Median of ${}^{2n}C_0,{}^{2n}C_1,{}^{2n}C_2, \dots ,{}^{2n}C_n$ (when $n$ is even) is-

Median of $5$ observations i.e. $3^{{\log }_{9}4},5^{{\log }_{\frac{1}{2}}8},e^{2\ln 3},\ln \left(\frac{1}{e}2\right)+3, e^{2\ln 3+\frac{1}{{\log }_{4}e}}:-$

The average age of a teacher and three students is $20$ years. If all students are of equal age and the difference between the age of the teacher and that of a student is $20$ years, then the age of the teacher is-

The median of $21$ observation is $40$. If each observations greater than the median are increased by $6$, then the median of the observations will be-

Median of the following frequency distribution is

A man spends equal amount on purchasing three kinds of pens at the rate $5$ Rs/pen, $10$ Rs/pen, $20$ Rs/pen, then average cost of one pen is :-

If mean $=(3$ median $-$ mode$)$ $x$, then the value of $x$ is-

The mean of the series $x_1,x_2,\dots \dots ,x_{\mathit{n}}$ is $\overline{X}$. If $x_2$ is replaced by $\lambda$, then the new mean is-

The mean of $n$ values of a distribution is $\overline{x}$. If its first value is increased by $1$, second by $2,\dots$ then the mean of new values will be-

For $15$ observations of $x$, mean and median were found to be $12$ and $20$ respectively. Later an observation which was $25$ found to be wrong then replaced by its correct value $55$, then new mean and median will be :-

The mean of values $0,1,2,\dots \dots ,n$ when their weights are $1,{}^{\mathit{n}}C_1,{}^{\mathit{n}}C_2,\dots .,{}^{\mathit{n}}C_{\mathit{n}}$, resp., is