Odisha Board Solutions for Chapter: Redox Reaction, Exercise 1: QUESTIONS

Author:Odisha Board

Odisha Board Chemistry Solutions for Exercise - Odisha Board Solutions for Chapter: Redox Reaction, Exercise 1: QUESTIONS

Attempt the practice questions on Chapter 10: Redox Reaction, Exercise 1: QUESTIONS with hints and solutions to strengthen your understanding. Bureau's Higher Secondary Chemistry Volume-1 solutions are prepared by Experienced Embibe Experts.

Questions from Odisha Board Solutions for Chapter: Redox Reaction, Exercise 1: QUESTIONS with Hints & Solutions

MEDIUM
11th Odisha Board
IMPORTANT

In the following reaction,  

MnO4-+H++X Mn2++4H2O,     X is

MEDIUM
11th Odisha Board
IMPORTANT

In the following equation : 

Cr2O72-+H++X  2Cr3++7H2O,   X is

HARD
11th Odisha Board
IMPORTANT

Balance the following equations by oxidation number method.

K2MnO4+HCl  KMnO4+MnO2+KCl+H2O

MEDIUM
11th Odisha Board
IMPORTANT

Balance the following equation by oxidation number method

MnO4-+SO2  Mn2++H2SO4

HARD
11th Odisha Board
IMPORTANT

Consider the reactions : 

2S2O3(aq)2-+I2(s)  S4O6(aq)2-+2I(aq)-S2O3(aq)2-+2Br2(l)+5H2O(l)  2SO4(aq)2-+4Br(aq)-+10H(aq)+

Why does the same reductant, thiosulphate reacts differently with iodine and bromine?

HARD
11th Odisha Board
IMPORTANT

Sulphur dioxide and hydrogen peroxide can act as oxidising as well as reducing agents in their reactions. Why?

HARD
11th Odisha Board
IMPORTANT

Determine the volume of M8KMnO4 solution required to react completely with 20 Cm3 of M4FeSO4 solution in acidic medium.

HARD
11th Odisha Board
IMPORTANT

Which of the following species, do not show disproportionation reaction and why?

ClO-, ClO2-, ClO3- and ClO4-

Also write reaction for each of the species that disproportionates.