Odisha Board Solutions for Chapter: Wave Optics and Interference, Exercise 2: MODEL QUESTIONS

In Young's experiment, the width of fringes obtained with light of wavelength $6000 \stackrel{°}{\mathrm{A}}$ is $2.0 \mathrm{mm}$. What will be the fringe width (in $\mathrm{mm}$) if the entire apparatus is immersed in a liquid of refractive index $1.33$ ?

In Young's double slit experiment, using light of wavelength $400 \mathrm{nm}$, interference fringes of width '$X$' are obtained. The wavelength of light is increased to $600 \mathrm{nm}$ and the separation between the slits is halved. If one wants the observed fringe width on the screen to be same in the two cases, find the ratio of the distance between the screen and the plane of interfering sources with the two arrangements.

Find the ratio of intensities at two points on a screen in Young's double slit experiment when waves from the two slits have a path difference of (i) 0 and (ii) $\frac{\lambda }{4}$

Correct the following sentences:

Wave theory of light explains photoelectric effect but not interference.

Correct the following sentences:

In young's double slit experiment the fringe width depends on the order of fringe.

Correct the following sentence.

In Young's double slit experiment the fringe width decreases if the distance between the source and screen increases.

Correct the following sentence.

Correct the following sentence.

Fringe width for dark fringe differs from fringe width for bright fringe, in Young's double slit experiment.