Sue Pemberton Solutions for Chapter: Functions, Exercise 5: EXERCISE 2D

Author:Sue Pemberton

Sue Pemberton Mathematics Solutions for Exercise - Sue Pemberton Solutions for Chapter: Functions, Exercise 5: EXERCISE 2D

Attempt the practice questions on Chapter 2: Functions, Exercise 5: EXERCISE 2D with hints and solutions to strengthen your understanding. Cambridge International AS & A Level Mathematics : Pure Mathematics 1 Course Book solutions are prepared by Experienced Embibe Experts.

Questions from Sue Pemberton Solutions for Chapter: Functions, Exercise 5: EXERCISE 2D with Hints & Solutions

MEDIUM
AS and A Level
IMPORTANT

The diagram shows the graph of y=fx, where f(x)=4x+2 for x,x0.

(c) State the domain and range of f-1.

HARD
AS and A Level
IMPORTANT

The diagram shows the graph of y=fx, where f(x)=4x+2 for x,x0.

(d) On a copy of the diagram, sketch the graph of y=f-1(x), making clear the relationship between the graphs.

MEDIUM
AS and A Level
IMPORTANT

For each of the following functions, find an expression for f-1(x) and, hence, decide if the graph of y=f(x) is symmetrical about the line y=x.

(a) f(x)=x+52x-1 for x,x12.

MEDIUM
AS and A Level
IMPORTANT

For each of the following functions, find an expression for f-1(x) and, hence, decide if the graph of y=f(x) is symmetrical about the line y=x.

(b) f(x)=2x-3x-5 for x,x5.

MEDIUM
AS and A Level
IMPORTANT

For each of the following functions, find an expression for f-1(x) and, hence, decide if the graph of y=f(x) is symmetrical about the line y=x.

(c) f(x)=3x-12x-3 for x,x32.

MEDIUM
AS and A Level
IMPORTANT

For each of the following functions, find an expression for f-1(x) and, hence, decide if the graph of y=f(x) is symmetrical about the line y=x.

(d) f(x)=4x+53x-4 for x,x43.

MEDIUM
AS and A Level
IMPORTANT

(a) f(x)=x+abx-1 for x,x1b, where a &b are constants. Prove that this function is self-inverse.

MEDIUM
AS and A Level
IMPORTANT

(b) g(x)=ax+bcx+d for x,x-dc, where a,b,c and d are constants. Find the condition for this function to be self-inverse.