Embibe Experts Solutions for Chapter: Coordination Compounds, Exercise 2: Level 2

${\mathrm{sp}}^3{\mathrm{d}}^2$ hybridization explains the bonding in:

A divalent transition metal ion with valence electron configuration $3{\mathrm{d}}^8$ forms a complex with cyanide ion. The correct identity of the metal ion, the complex and its geometry, respectively, are

The hybridization of $\mathrm{Ni}$ centre in $\mathrm{Ni}\left[{\left({\mathrm{PPh}}_3\right)}_2{\mathrm{Cl}}_2\right]$ and ${\left[{\mathrm{NiCl}}_4\right]}^{2-}$ respectively are

The hybridisations of $\mathrm{Ni}{\left(\mathrm{CO}\right)}_4$ and $\mathrm{Cr}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6^{3+}$, respectively.

Among the following, the species that is both tetrahedral and diamagnetic is

The octahedral complex ${\mathrm{CoSO}}_4\mathrm{Cl}.5{\mathrm{NH}}_3$ exists in two isomeric forms, $\mathrm{X}$ and $\mathrm{Y}.$ Isomer X reacts with ${\mathrm{AgNO}}_3$ to give a white precipitate, but does not react with ${\mathrm{BaCl}}_2.$ Isomer $\mathrm{Y}$ gives a white precipitate with ${\mathrm{BaCl}}_2$, but does not react with ${\mathrm{AgNO}}_3.$ X and Y are:

The complex that can exhibit linkage isomerism is:

The complex having the highest spin-only magnetic moment is: