A first order reaction has a rate constant 1 . 15 × 10 - 3 s - 1 . How long will 5 g of this reactant take to reduce to 3 g ?

Given: Initial amount R 0 = 5 g Final concentration [ R ] = 3 g Rate constant ( k ) = 1.15 × 10 - 3 s - 1 Formula: t = 2.303 k l o g R 0 R Put the values of R 0 , R and Rate constant in above formula, t = 2.303 1.15 × 10 - 3 l o g 5 3 = 2.303 1.15 × 10 - 3 × 0.2219 seconds = 444. 378 seconds = 444 seconds.

E M B I B E

Chemistry Part I Textbook for Class XII>Chapter 3 - Chemical Kinetics>Intext Questions

NCERT Solutions for Chapter: Chemical Kinetics, Exercise 2: Intext Questions

Author:NCERT

NCERT Chemistry Solutions for Exercise - NCERT Solutions for Chapter: Chemical Kinetics, Exercise 2: Intext Questions

Attempt the free practice questions on Chapter 3: Chemical Kinetics, Exercise 2: Intext Questions with hints and solutions to strengthen your understanding. Chemistry Part I Textbook for Class XII solutions are prepared by Experienced Embibe Experts.

Questions from NCERT Solutions for Chapter: Chemical Kinetics, Exercise 2: Intext Questions with Hints & Solutions

EASY

12th Uttar Pradesh Board

IMPORTANT

Chemistry Part I Textbook for Class XII>Chapter 3 - Chemical Kinetics>Intext Questions>Q 4.5

A first order reaction has a rate constant $1.15 \times 10^{- 3} s^{- 1} .$ How long will $5 g$ of this reactant take to reduce to $3 g ?$

EASY

12th Uttar Pradesh Board

IMPORTANT

Chemistry Part I Textbook for Class XII>Chapter 3 - Chemical Kinetics>Intext Questions>Q 4.6

Time required to decompose $S O_{2} C l_{2}$ to half of its initial amount is $60$ minutes. If the decomposition is a first order reaction, calculate the rate constant of the reaction.

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