NCERT Solutions for Chapter: Coordination Compounds, Exercise 3: Intext Questions

Explain on the basis of valence bond theory that ${\left[\mathrm{N}\mathrm{i}{\left(\mathrm{C}\mathrm{N}\right)}_4\right]}^{2-}$ ion with square planar structure is diamagnetic and the ${\left[\mathrm{N}\mathrm{i}\mathrm{C}{\mathrm{l}}_4\right]}^{2-}$ ion with tetrahedral geometry is paramagnetic.

${\left[\mathrm{N}\mathrm{i}\mathrm{C}{\mathrm{l}}_4\right]}^{2-}$ is paramagnetic while $\left[\mathrm{N}\mathrm{i}{\left(\mathrm{C}\mathrm{O}\right)}_4\right]$ is diamagnetic though both are tetrahedral. Why?

${\left[\mathrm{F}\mathrm{e}{\left({\mathrm{H}}_2\mathrm{O}\right)}_6\right]}^{3+}$ is strongly paramagnetic whereas, ${\left[\mathrm{F}\mathrm{e}{\left(\mathrm{C}\mathrm{N}\right)}_6\right]}^{3-}$ is weakly paramagnetic. Explain.

Explain ${\left[\mathrm{C}\mathrm{o}{\left(\mathrm{N}{\mathrm{H}}_3\right)}_6\right]}^{3+}$ is an inner orbital complex whereas ${\left[\mathrm{N}\mathrm{i}{\left(\mathrm{N}{\mathrm{H}}_3\right)}_6\right]}^{2+}$ is an outer orbital complex.

Predict the number of unpaired electrons in the square planar ${\left[\mathrm{P}\mathrm{t}{\left(\mathrm{C}\mathrm{N}\right)}_4\right]}^{2-}$ ion.

The hexaquamanganese (II) ion contains five unpaired electrons, while the hexacyano ion contains only one unpaired electron. Explain using Crystal Field Theory.