Lawrie Ryan and Roger Norris Solutions for Chapter: Electrochemistry, Exercise 12: Questions

What is the ${\mathrm{E}}^{⊝}$ value for the half-cell on the left-hand side of Figure.

Why is platinum used in preference to other metals, in half-cells where the reaction does not involve a metallic element?

Show, with the aid of a diagram, how you would measure the ${\mathrm{E}}^{⊝}$value for the half-cell shown by the equation:
${\mathrm{VO}}^{2+}+ 2{\mathrm{H}}^{+}+{\mathrm{e}}^{-}\rightleftharpoons {\mathrm{V}}^{3+}+{\mathrm{H}}_2\mathrm{O}$