In the table below, which of the operations - addition, subtraction, multiplication or division will be carried out on both sides of the equation so that the value of x is obtained. Fill in the table. Equation Which operation would remove the constant from the variable's side Equation after the operation Value of x after the equation is solved 5 + x = 9

Given, Equation Which operation would remove the constant from the variable's side Equation after the operation Value of x after the equation is solved 5 + x = 9 Here, the equation is 5 + x = 9 Now, to remove the constant from the variable's side we need to subtract 5 from both the sides of the equation. Thus, we get 5 + x - 5 = 9 - 5 ⇒ x = 4 Thus, the complete table is, Equation Which operation would remove the constant from the variable's side Equation after the operation Value of x after the equation is solved 5 + x = 9 We need to subtract 5 from both the sides 5 + x - 5 = 9 - 5 x = 4

In the table below, which of the operations - addition, subtraction, multiplication or division will be carried out on both sides of the equation so that the value of x is obtained. Fill in the table. Equation Which operation would remove the constant from the variable's side Equation after the operation Value of x after the equation is solved 4 + x = 2

Given, Equation Which operation would remove the constant from the variable's side Equation after the operation Value of x after the equation is solved 4 + x = 2 Here, the equation is 4 + x = 2 Now, to remove the constant from the variable's side we need to subtract 4 from both the sides of the equation. Thus, we get 4 + x - 4 = 2 - 4 ⇒ x = - 2 Thus, the complete table is, Equation Which operation would remove the constant from the variable's side Equation after the operation Value of x after the equation is solved 4 + x = 2 We need to subtract 4 from both the sides 4 + x - 4 = 2 - 4 x = - 2

In the table below, which of the operations - addition, subtraction, multiplication or division will be carried out on both sides of the equation so that the value of y is obtained. Fill in the table. Equation Which operation would remove the constant from the variable's side Equation after the operation Value of y after the equation is solved - 7 = 3 + y

Given, Equation Which operation would remove the constant from the variable's side Equation after the operation Value of y after the equation is solved - 7 = 3 + y Here, the equation is - 7 = 3 + y Now, to remove the constant from the variable's side we need to subtract 3 from both the sides of the equation. Thus, we get - 7 - 3 = 3 + y - 3 ⇒ y = - 10 Thus, the complete table is, Equation Which operation would remove the constant from the variable's side Equation after the operation Value of y after the equation is solved - 7 = 3 + y We need to subtract 3 from both the sides - 7 - 3 = 3 + y - 3 y = - 10

In the table below, which of the operations - addition, subtraction, multiplication or division will be carried out on both sides of the equation so that the value of y is obtained. Fill in the table. Equation Which operation would remove the constant from the variable's side Equation after the operation Value of y after the equation is solved 4 = 8 y

Given, Equation Which operation would remove the constant from the variable's side Equation after the operation Value of y after the equation is solved 4 = 8 y Here, the equation is 4 = 8 y Now, to remove the constant from the variable's side we need to divide 8 from both the sides of the equation. Thus, we get 4 8 = 8 y 8 ⇒ y = 1 2 Thus, the complete table is, Equation Which operation would remove the constant from the variable's side Equation after the operation Value of y after the equation is solved 4 = 8 y We need to divide 8 from both the sides 4 8 = 8 y 8 y = 1 2

Chhattisgarh Board Solutions for Chapter: Equations, Exercise 5: ACTIVITY 4

Author:Chhattisgarh Board

Chhattisgarh Board Mathematics Solutions for Exercise - Chhattisgarh Board Solutions for Chapter: Equations, Exercise 5: ACTIVITY 4

Attempt the practice questions on Chapter 14: Equations, Exercise 5: ACTIVITY 4 with hints and solutions to strengthen your understanding. MATHEMATICS CLASS - 6 solutions are prepared by Experienced Embibe Experts.

Questions from Chhattisgarh Board Solutions for Chapter: Equations, Exercise 5: ACTIVITY 4 with Hints & Solutions

MEDIUM

6th Chhattisgarh Board

IMPORTANT

MATHEMATICS CLASS - 6>Chapter 14 - Equations>ACTIVITY 4>Q 7

In the table below, which of the operations - addition, subtraction, multiplication or division will be carried out on both sides of the equation so that the value of $x$ is obtained. Fill in the table.

Equation	Which operation would remove the constant from the variable's side	Equation after the operation	Value of $x$ after the equation is solved

$5 + x = 9$

MEDIUM

6th Chhattisgarh Board

IMPORTANT

MATHEMATICS CLASS - 6>Chapter 14 - Equations>ACTIVITY 4>Q 8

Equation	Which operation would remove the constant from the variable's side	Equation after the operation	Value of $x$ after the equation is solved

$4 + x = 2$

MEDIUM

6th Chhattisgarh Board

IMPORTANT

MATHEMATICS CLASS - 6>Chapter 14 - Equations>ACTIVITY 4>Q 9

In the table below, which of the operations - addition, subtraction, multiplication or division will be carried out on both sides of the equation so that the value of $y$ is obtained. Fill in the table.

Equation	Which operation would remove the constant from the variable's side	Equation after the operation	Value of $y$ after the equation is solved

$- 7 = 3 + y$

MEDIUM

6th Chhattisgarh Board

IMPORTANT

MATHEMATICS CLASS - 6>Chapter 14 - Equations>ACTIVITY 4>Q 10

Equation	Which operation would remove the constant from the variable's side	Equation after the operation	Value of $y$ after the equation is solved

$4 = 8 y$

EASY

6th Chhattisgarh Board

IMPORTANT

MATHEMATICS CLASS - 6>Chapter 14 - Equations>ACTIVITY 4>Q (i)

Solve the given equation:

$x + 3 = 10$

EASY

6th Chhattisgarh Board

IMPORTANT

MATHEMATICS CLASS - 6>Chapter 14 - Equations>ACTIVITY 4>Q (ii)

Solve the given equation:

$6 = y + 4$

EASY

6th Chhattisgarh Board

IMPORTANT

MATHEMATICS CLASS - 6>Chapter 14 - Equations>ACTIVITY 4>Q (iii)

Solve the given equation:

$S + 6 = 15$

EASY

6th Chhattisgarh Board

IMPORTANT

MATHEMATICS CLASS - 6>Chapter 14 - Equations>ACTIVITY 4>Q (iv)

Solve the given equation:

$7 + t = 25$

Chhattisgarh Board Solutions for Chapter: Equations, Exercise 5: ACTIVITY 4

Chhattisgarh Board Mathematics Solutions for Exercise - Chhattisgarh Board Solutions for Chapter: Equations, Exercise 5: ACTIVITY 4

Questions from Chhattisgarh Board Solutions for Chapter: Equations, Exercise 5: ACTIVITY 4 with Hints & Solutions

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