Verify, Product of two numbers = LCM ( a , b ) × HCF ( a , b ) by finding the HCF and LCM of the numbers given below, 4 , 9

Given numbers 4 , 9 To verify Product of two numbers = LCM ( a , b ) × HCF ( a , b ) Using prime factorization method, 4 = 2 × 2 9 = 3 × 3 LCM ( a , b ) = 2 × 2 × 3 × 3 = 36 HCF ( a , b ) = 1 Product of two numbers = 4 × 9 = 36 LCM ( a , b ) × HCF ( a , b ) = 36 × 1 = 36 Thus, Product of two numbers = LCM ( a , b ) × HCF ( a , b ) is verified.

Verify, Product of two numbers = LCM ( a , b ) × HCF ( a , b ) by finding the HCF and LCM of the numbers given below, 30 , 36

Given numbers 30 , 36 To verify Product of two numbers = LCM ( a , b ) × HCF ( a , b ) Using prime factorization method, 30 = 2 × 5 × 3 36 = 3 × 3 × 2 × 2 LCM ( a , b ) = 2 × 2 × 3 × 3 × 5 = 180 HCF ( a , b ) = 3 × 2 = 6 Product of two numbers = 30 × 36 = 1080 LCM ( a , b ) × HCF ( a , b ) = 180 × 6 = 1080 Thus, Product of two numbers = LCM ( a , b ) × HCF ( a , b ) is verified.

Verify, Product of two numbers = LCM ( a , b ) × HCF ( a , b ) by finding the HCF and LCM of the numbers given below, 42 , 48

Given numbers 42 , 48 To verify Product of two numbers = LCM ( a , b ) × HCF ( a , b ) Using prime factorization method, 42 = 2 × 3 × 7 48 = 2 × 2 × 2 × 2 × 3 LCM ( a , b ) = 2 × 3 × 2 × 2 × 2 × 7 = 336 HCF ( a , b ) = 2 × 3 = 6 Product of two numbers = 42 × 48 = 2016 LCM ( a , b ) × HCF ( a , b ) = 336 × 6 = 2016 Thus, Product of two numbers = LCM ( a , b ) × HCF ( a , b ) is verified.

Verify, Product of two numbers = LCM ( a , b ) × HCF ( a , b ) by finding the HCF and LCM of the numbers given below, 108 , 18

Given numbers 108 , 18 To verify Product of two numbers = LCM ( a , b ) × HCF ( a , b ) Using prime factorization method, 108 = 2 × 2 × 3 × 3 × 3 18 = 3 × 3 × 2 LCM ( a , b ) = 2 × 2 × 3 × 3 × 3 = 108 HCF ( a , b ) = 18 Product of two numbers = 108 × 18 = 1944 LCM ( a , b ) × HCF ( a , b ) = 108 × 18 = 1944 Thus, Product of two numbers = LCM ( a , b ) × HCF ( a , b ) is verified.

Verify, Product of two numbers = LCM ( a , b ) × HCF ( a , b ) by finding the HCF and LCM of the numbers given below, 21 , 105

Given numbers 21 , 105 To verify Product of two numbers = LCM ( a , b ) × HCF ( a , b ) Using prime factorization method, 21 = 7 × 3 105 = 5 × 3 × 7 LCM ( a , b ) = 7 × 5 × 3 = 105 HCF ( a , b ) = 7 × 3 = 21 Product of two numbers = 21 × 105 = 2205 LCM ( a , b ) × HCF ( a , b ) = 105 × 21 = 2205 Thus, Product of two numbers = LCM ( a , b ) × HCF ( a , b ) is verified.

E M B I B E

MATHEMATICS CLASS - 6>Chapter 6 - Factors and Multiples>ACTIVITY 6

Chhattisgarh Board Solutions for Chapter: Factors and Multiples, Exercise 12: ACTIVITY 6

Author:Chhattisgarh Board

Chhattisgarh Board Mathematics Solutions for Exercise - Chhattisgarh Board Solutions for Chapter: Factors and Multiples, Exercise 12: ACTIVITY 6

Attempt the free practice questions on Chapter 6: Factors and Multiples, Exercise 12: ACTIVITY 6 with hints and solutions to strengthen your understanding. MATHEMATICS CLASS - 6 solutions are prepared by Experienced Embibe Experts.