Find the value of k in 3 x 2 - 2 8 x + k = 0 given that the roots of the quadratic equation are real and equal.

On comparing the quadratic equation 3 x 2 - 2 8 x + k = 0 with the standard from ax 2 + bx + c = 0 , we find that a = 3 , b = - 2 8 , c = k Substituting the above values in D = b 2 - 4 ac D = b 2 - 4 ac D = - 2 8 2 - 4 ( 3 ) ( k ) D = 4 × 8 - 12 k D = 32 - 12 k When the roots are real and equal, D = 0 0 = 32 - 12 k 12 k = 32 k = 32 12 k = 8 3 Hence, the value of k = 8 3 .

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Mathematics Class - 10>Algebra>Chapter 3 - Quadratic Equation in One Variable>Try These

Chhattisgarh Board Solutions for Exercise 12: Try These

Author:Chhattisgarh Board

Chhattisgarh Board Mathematics Solutions for Exercise - Chhattisgarh Board Solutions for Exercise 12: Try These

Attempt the practice questions from Exercise 12: Try These with hints and solutions to strengthen your understanding. Mathematics Class - 10 solutions are prepared by Experienced Embibe Experts.