Chhattisgarh Board Solutions for Exercise 8: Exercise – 4

Author:Chhattisgarh Board

Chhattisgarh Board Mathematics Solutions for Exercise - Chhattisgarh Board Solutions for Exercise 8: Exercise – 4

Attempt the practice questions from Exercise 8: Exercise – 4 with hints and solutions to strengthen your understanding. Mathematics Class - 10 solutions are prepared by Experienced Embibe Experts.

Questions from Chhattisgarh Board Solutions for Exercise 8: Exercise – 4 with Hints & Solutions

MEDIUM
10th Chhattisgarh Board
IMPORTANT

By melting down a sphere of radius 10.5 cm somes mall cones are made, each of height 3 cm and radius 3.5 cm. Find the number of such cones.

MEDIUM
10th Chhattisgarh Board
IMPORTANT

After filling the air in a spherical balloon of radius 7 cm it becomes 14 cm. Calculate the ratio of the surface area of the balloon in both conditions.

MEDIUM
10th Chhattisgarh Board
IMPORTANT

Calculate the volume of a sphere having surface area equal to 154 cm2. (Use π=227)

MEDIUM
10th Chhattisgarh Board
IMPORTANT

Ratio of the volume of 2 spheres is 64:27. Calculate the ratio of their surface areas.

MEDIUM
10th Chhattisgarh Board
IMPORTANT

Radius of a solid sphere is 12 cm. How many spheres of radius 6 cm can be made by melting this sphere.

MEDIUM
10th Chhattisgarh Board
IMPORTANT

If the volume and surface area of a sphere are equal then calculate its radius.

MEDIUM
10th Chhattisgarh Board
IMPORTANT

A child converts a cone of height 24 cm and base radius 6 cm into a sphere. Calculate the radius of the sphere in cm.

MEDIUM
10th Chhattisgarh Board
IMPORTANT

By melting down 3 spherical balls of radius 6 cm, 8 cm and 10 cm one big solid sphere is made. Calculate the radius (in cm) of the new solid sphere.