Chhattisgarh Board Solutions for Exercise 8: Exercise – 4
Chhattisgarh Board Mathematics Solutions for Exercise - Chhattisgarh Board Solutions for Exercise 8: Exercise – 4
Attempt the practice questions from Exercise 8: Exercise – 4 with hints and solutions to strengthen your understanding. Mathematics Class - 10 solutions are prepared by Experienced Embibe Experts.
Questions from Chhattisgarh Board Solutions for Exercise 8: Exercise – 4 with Hints & Solutions
By melting down a sphere of radius somes mall cones are made, each of height and radius . Find the number of such cones.

After filling the air in a spherical balloon of radius it becomes . Calculate the ratio of the surface area of the balloon in both conditions.

Calculate the volume of a sphere having surface area equal to . (Use )

Ratio of the volume of spheres is . Calculate the ratio of their surface areas.

Radius of a solid sphere is . How many spheres of radius can be made by melting this sphere.

If the volume and surface area of a sphere are equal then calculate its radius.

A child converts a cone of height and base radius into a sphere. Calculate the radius of the sphere in .

By melting down spherical balls of radius and one big solid sphere is made. Calculate the radius (in ) of the new solid sphere.
