Chhattisgarh Board Solutions for Exercise 9: Exercise – 5

Author:Chhattisgarh Board

Chhattisgarh Board Mathematics Solutions for Exercise - Chhattisgarh Board Solutions for Exercise 9: Exercise – 5

Attempt the free practice questions from Exercise 9: Exercise – 5 with hints and solutions to strengthen your understanding. Mathematics Class - 10 solutions are prepared by Experienced Embibe Experts.

Questions from Chhattisgarh Board Solutions for Exercise 9: Exercise – 5 with Hints & Solutions

HARD
10th Chhattisgarh Board
IMPORTANT

In figure the object is made of two solids - a cube and a hemisphere. The base of the figure is a cube with edges of 5 cm and the hemisphere fixed on the top has a diameter of 4.2 cm. Find the total surface area (in cm2) of the object. (Take π=227

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HARD
10th Chhattisgarh Board
IMPORTANT

A toy has two parts. One part is cone-shaped and has radius of 5 cm. And it is placed on the top of a hemisphere having similar radius. Total height of toy is 17 cm. Find the total surface area of the toy?

MEDIUM
10th Chhattisgarh Board
IMPORTANT

A solid is in the shape of a cone standing on a hemisphere with both their radii being equal to 1 cm. The height of the cone is equal to its radius. Find the volume of the solid in terms of π.

HARD
10th Chhattisgarh Board
IMPORTANT

A spherical glass vessel has a cylindrical neck which is 4 cm long and 2 cm in diameter. The diameter of the spherical part is 6 cm. Find the amount of water it can hold in terms of π?

HARD
10th Chhattisgarh Board
IMPORTANT

The upper portion of the greenhouse shown in figure is semicircular. This greenhouse is made up of cloth. It has a wooden door of size 1.2 m×0.5 m. Find the area of the cloth required to cover the greenhouse completely.

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