Rational Numbers Factors of numerators Factors of denominator HCF Numerator ÷ HCF Denominator ÷ HCF Simplest form 57 76

Given, 57 76 To find the simplest form of any rational number we need to check whether the rational number is in the lowest form or not. If the HCF of the numerator and the denominator is 1 , then we can say the rational number is in the simplest form. Now, the factors of 57 = 3 , 19 , 1 , 57 and 76 = 1 , 2 , 4 , 19 , 76 Thus, the HCF ( 57 , 76 ) = 19 To find the simplest form of a rational number we need to divide the numerator and the denominator by the HCF of the numerator and the denominator. Therefore, 57 76 = 57 ÷ 19 76 ÷ 19 = 3 4 Rational Numbers Factors of numerators Factors of denominator HCF Numerator ÷ HCF Denominator ÷ HCF Simplest form 57 76 3 , 19 , 1 , 57 1 , 2 , 4 , 19 , 76 19 57 ÷ 19 76 ÷ 19 3 4

Rational Numbers Factors of numerators Factors of denominator HCF Numerator ÷ HCF Denominator ÷ HCF Simplest form 18 36

Given, 18 36 To find the simplest form of any rational number we need to check whether the rational number is in the lowest form or not. If the HCF of the numerator and the denominator is 1 , then we can say the rational number is in the simplest form. Now, the factors of 18 = 1 , 2 , 3 , 6 , 9 , 18 and 36 = 1 , 2 , 3 , 4 , 6 , 9 , 12 , 18 , 36 . Thus, the HCF ( 18 , 36 ) = 18 To find the simplest form of a rational number we need to divide the numerator and the denominator by the HCF of the numerator and the denominator. Therefore, 18 36 = 18 ÷ 18 36 ÷ 18 = 1 2 Rational Numbers Factors of numerators Factors of denominator HCF Numerator ÷ HCF Denominator ÷ HCF Simplest form 18 36 1 , 2 , 3 , 6 , 9 , 18 1 , 2 , 3 , 4 , 6 , 9 , 12 , 18 , 36 18 18 ÷ 18 36 ÷ 18 1 2

Rational Numbers Factors of numerators Factors of denominator HCF Numerator ÷ HCF Denominator ÷ HCF Simplest form 27 81

Given, 27 81 To find the simplest form of any rational number we need to check whether the rational number is in the lowest form or not. If the HCF of the numerator and the denominator is 1 , then we can say the rational number is in the simplest form. Now, the factors of 27 = 1 , 3 , 9 , 27 and 81 = 1 , 3 , 9 , 27 , 81 . Thus, the HCF ( 27 , 81 ) = 27 To find the simplest form of a rational number we need to divide the numerator and the denominator by the HCF of the numerator and the denominator. Therefore, 27 81 = 27 ÷ 27 81 ÷ 27 = 1 3 Rational Numbers Factors of numerators Factors of denominator HCF Numerator ÷ HCF Denominator ÷ HCF Simplest form 27 81 1 , 3 , 9 , 27 1 , 3 , 9 , 27 , 81 27 27 ÷ 27 81 ÷ 27 = 1 3 1 3

Rational Numbers Factors of numerators Factors of denominator HCF Numerator ÷ HCF Denominator ÷ HCF Simplest form - 63 85

Given, - 63 85 To find the simplest form of any rational number we need to check whether the rational number is in the lowest form or not. If the HCF of the numerator and the denominator is 1 , then we can say the rational number is in the simplest form. Now, the factors of 63 = 1 , 3 , 7 , 9 , 21 , 63 and 85 = 1 , 5 , 17 , 85 . Thus, the HCF ( 63 , 85 ) = 1 Therefore, the simplest form is the given rational number itself. Rational Numbers Factors of numerators Factors of denominator HCF Numerator ÷ HCF Denominator ÷ HCF Simplest form - 63 85 1 , 3 , 7 , 9 , 21 , 63 1 , 5 , 17 , 85 1 - 63 ÷ 1 85 ÷ 1 - 63 85

E M B I B E

Mathematics Class - VII>Chapter 2 - Rational Numbers>Activity

Chhattisgarh Board Solutions for Chapter: Rational Numbers, Exercise 2: Exercise 2

Author:Chhattisgarh Board

Chhattisgarh Board Mathematics Solutions for Exercise - Chhattisgarh Board Solutions for Chapter: Rational Numbers, Exercise 2: Exercise 2

Attempt the practice questions on Chapter 2: Rational Numbers, Exercise 2: Exercise 2 with hints and solutions to strengthen your understanding. Mathematics Class - VII solutions are prepared by Experienced Embibe Experts.