Chhattisgarh Board Solutions for Chapter: Work and Energy, Exercise 8: Exercise

Author:Chhattisgarh Board

Chhattisgarh Board Science Solutions for Exercise - Chhattisgarh Board Solutions for Chapter: Work and Energy, Exercise 8: Exercise

Attempt the practice questions on Chapter 12: Work and Energy, Exercise 8: Exercise with hints and solutions to strengthen your understanding. Science (Theory & Practical) Class-9 solutions are prepared by Experienced Embibe Experts.

Questions from Chhattisgarh Board Solutions for Chapter: Work and Energy, Exercise 8: Exercise with Hints & Solutions

EASY
9th Chhattisgarh Board
IMPORTANT

On applying brakes of a car which is moving at a speed v, it stops after covering a distance d. Calculate, what will be the distance covered by the car after applying brakes if it was moving at a speed of 2v.

EASY
9th Chhattisgarh Board
IMPORTANT

A man holds a sack of rice on his head for 30 minutes and gets tired. Has he done any work? Explain your answer with reasons.

EASY
9th Chhattisgarh Board
IMPORTANT

On applying a force of 8 Newton on a body, it moves in the direction of motion and displaces for 4 meters. Calculate the work done.

EASY
9th Chhattisgarh Board
IMPORTANT

A body of 10 kg mass is raised against gravitational force of earth to a height of 10 m. How much work is done (in joules) in this case? (g=10 ms2)

EASY
9th Chhattisgarh Board
IMPORTANT

Two bodies of masses 10 kg and 15 kg are raised to a height of 5 m and 2 m respectively above the surface of earth. Calculate the change in their potential energy in joules.

EASY
9th Chhattisgarh Board
IMPORTANT

By using the information given in the figure, calculate the velocity of the ball at the position D. (use the law of conservation of mechanical energy).
Question Image 

EASY
9th Chhattisgarh Board
IMPORTANT

On applying a force of 15 N for 6 sec a man displaces a box by 8 m. Calculate his power.

EASY
9th Chhattisgarh Board
IMPORTANT

To change the energy of a body of 0.5 kg by 1 J, we will have to raise it to what height? (g = 10 ms2).