Inverse of a Matrix

If $A=\left[\begin{array}{ccc}0& -1& 2\\ 2& -2& 0\end{array}\right], B=\left[\begin{array}{cc}0& 1\\ 1& 0\\ 1& 1\end{array}\right]$ and $M=AB,$ then $M^{-1}$ is equal to

If $M\left(\alpha \right)=\left[\begin{array}{ccc}\cos \alpha & -\sin \alpha & 0\\ \sin \alpha & \cos \alpha & 0\\ 0& 0& 1\end{array}\right],$ $M\left(\beta \right)=\left[\begin{array}{ccc}\cos \beta & 0& \sin \beta \\ 0& 1& 0\\ -\sin \beta & 0& \cos \beta \end{array}\right]$, then ${\left[M\left(\alpha \right)M\left(\beta \right)\right]}^{-1}$ is equal to

If $A=\left[\begin{array}{ll}1& 0\\ 1& 1\end{array}\right]$, then $A^{-n}$ is equal to

If $A$ and $B$ are square matrices of order $3$ then

If $A$ and $B$ are matrices and $B=AB{A}^{-1}$, then the value of $\left(A+B\right)\left(A-B\right)$ is

Inverse matrix of $\left[\begin{array}{cc}2& -3\\ -4& 2\end{array}\right]$