Embibe Experts Solutions for Chapter: Wave Optics, Exercise 2: Exercise 2

In Young's slit experiment, carried out with lights of wavelength $\lambda =5000 \stackrel{\circ }{\mathrm{A}}$, the distance between the slit is $0.2 \mathrm{mm}$ and the screen is at $200 \mathrm{cm}$ from the slits. The central maximum is at $x=0$. The third maximum will be at $x$ equal to.

Two slits separated by a distance of $1 \mathrm{mm}$ are illuminated with red light of wavelength $6.5\times {10}^{-7}\mathrm{m}$. The interference fringes are observed on a screen placed $1 \mathrm{m}$ from the slits. The distance between third dark fringe & the fifth bright fringe is equal to:

In an experiment, the two slits are $0.5 \text{m}\text{m}$ apart and the fringes are observed at $100 \text{c}\text{m}$ from the plane of the slits. The distance of the $11\text{th}$ bright fringe from the $1\text{st}$ bright fringe is $9.72 \text{m}\text{m}$. Calculate the wavelength.

When a plastic thin film of refractive index $1.45$ is placed in the path of one of the interfering waves then the central fringe is displaced through the width of five fringes. The thickness of the film, if the wavelength of light is $5890 \stackrel{\circ }{\mathrm{A}}$, will be

The path difference between two interfering waves at a point on the screen is $\frac{\lambda }{6}$. The ratio of intensity at this point and that at the central bright fringe will be (Assume that intensity due to each slit in same)

The path difference between two interfering waves at a point on screen is $171.5$ times the wavelength. If the path difference is $0.01029 \mathrm{cm}$. Find the wavelength.

Find the minimum thickness of a film which will strongly reflect the light of wavelength $589 \mathrm{nm}$. The refractive index of the material of the film is $1.25$.

Two light rays having the same wavelength in vacuum are in phase initially. Then, the first ray travels a path ${\mathrm{L}}_{\mathrm{l}}$ through a medium of refractive index ${\mathrm{\mu }}_1$ while the second ray travels a path ${\mathrm{L}}_2$ through a medium of refractive index ${\mathrm{\mu }}_2$. The two waves are then combined to observe interference. The phase difference between the two waves is