Dr. Dayal Sandhu Solutions for Chapter: Mathematical Reasoning and Aptitude, Exercise 7: Exercise

When $0.232323$ ………. is converted into a fraction, then the result is :

The expression $\left(11.98\times 11.98+11.98\times x+0.02\times 0.02\right)$ will be a perfect square for $X$ equal to :

$\frac{\left(0.1667\right)\left(0.8833\right)\left(0.3333\right)}{\left(0.2222\right)\left(0.6667\right)\left(0.1250\right)}$ is approximately equal to _____.

Find the value that can replace the question mark.

$3889+12.952-?=3854.002$

$0.04\times 0.0162$ is equal to _____.

$\frac{4.2\mathrm{ }\times \mathrm{ }4.2\mathrm{ }-1.9\mathrm{ }\times \mathrm{ }1.9\mathrm{ }}{2.3\mathrm{ }\times \mathrm{ }6.1\mathrm{ }}$ is equal to :

If $\frac{144}{0.144}=\frac{14.4}{x}$ , then the value of $x$ is

The price of commodity $X$ increases by $40$ paise every year, while the price of commodity $Y$ increases by $15$ paise every year. If in $2001$, the price of commodity $X$ was $₹4.20$ and that of $Y$ was $₹6.30$, in which year commodity $X$ will cost $40$ paise more than the commodity $Y$?