Upkar's UGC NET/SET/JRF Teaching & Research Aptitude (General Paper-I)>Chapter 13 - Mathematical Aptitude>Exercise

Dr. K. Kautilya Solutions for Chapter: Mathematical Aptitude, Exercise 2: Exercise

Author:Dr. K. Kautilya

Dr. K. Kautilya Teaching and Research Aptitude Solutions for Exercise - Dr. K. Kautilya Solutions for Chapter: Mathematical Aptitude, Exercise 2: Exercise

Attempt the free practice questions on Chapter 13: Mathematical Aptitude, Exercise 2: Exercise with hints and solutions to strengthen your understanding. Upkar's UGC NET/SET/JRF Teaching & Research Aptitude (General Paper-I) solutions are prepared by Experienced Embibe Experts.

Questions from Dr. K. Kautilya Solutions for Chapter: Mathematical Aptitude, Exercise 2: Exercise with Hints & Solutions

EASY

UGC NET Paper 1

IMPORTANT

Upkar's UGC NET/SET/JRF Teaching & Research Aptitude (General Paper-I)>Chapter 13 - Mathematical Aptitude>Exercise>Q 6

Find the value of $x$ : $(\frac{36}{29 - \frac{4}{0 \cdot 2}} = x)$ .

EASY

UGC NET Paper 1

IMPORTANT

Upkar's UGC NET/SET/JRF Teaching & Research Aptitude (General Paper-I)>Chapter 13 - Mathematical Aptitude>Exercise>Q 7

What decimal fraction of $0.3$ meters is $6$ centimetres?

EASY

UGC NET Paper 1

IMPORTANT

Upkar's UGC NET/SET/JRF Teaching & Research Aptitude (General Paper-I)>Chapter 13 - Mathematical Aptitude>Exercise>Q 8

What is the value of $\frac{170}{272}$ in decimals?

EASY

UGC NET Paper 1

IMPORTANT

Upkar's UGC NET/SET/JRF Teaching & Research Aptitude (General Paper-I)>Chapter 13 - Mathematical Aptitude>Exercise>Q 9

Simplify: $(0.319 \div 2.9 = ?)$

EASY

UGC NET Paper 1

IMPORTANT

Upkar's UGC NET/SET/JRF Teaching & Research Aptitude (General Paper-I)>Chapter 13 - Mathematical Aptitude>Exercise>Q 10

Simplify: $(41 \cdot 01 + 9 \cdot 9 + 18 \cdot 77 = ?)$

EASY

UGC NET Paper 1

IMPORTANT

Upkar's UGC NET/SET/JRF Teaching & Research Aptitude (General Paper-I)>Chapter 13 - Mathematical Aptitude>Exercise>Q 11

Simplify: $(0 . 5 - 0.0036 = ?)$ .

EASY

UGC NET Paper 1

IMPORTANT

Upkar's UGC NET/SET/JRF Teaching & Research Aptitude (General Paper-I)>Chapter 13 - Mathematical Aptitude>Exercise>Q 12

Simplify: $(0 \cdot 135 \div 2 \cdot 7 = ?)$ .

EASY

UGC NET Paper 1

IMPORTANT

Upkar's UGC NET/SET/JRF Teaching & Research Aptitude (General Paper-I)>Chapter 13 - Mathematical Aptitude>Exercise>Q 13

Simplify: $(4 \cdot 2 - 1 \cdot 4 \div 0 \cdot 7 = ?)$ .