Important Compounds of Group 13 Elements

Given below are two statements :
Statement I : Upon heating a borax bead dipped in cupric sulphate in a luminous flame, the colour of the bead becomes green.
Statement II : The green colour observed is due to the formation of copper(I) metaborate In the light of the above statements, choose the most appropriate answer from the options given below:

Boric acid in solid, whereas ${\mathrm{BF}}_3$ is gas at room temperature because of

During the borax bead test with ${\mathrm{CuSO}}_4$, a blue green colour of the bead was observed in oxidising flame due to the formation of

When borax is heated with $\mathrm{CoO}$ on a platinum loop, blue coloured bead formed is largely due to

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason $\mathrm{R}$.

Assertion $\mathrm{A}$ : Boric acid is a weak acid

Reason $\mathrm{R}$ : Boric acid is not able to release ${\mathrm{H}}^{+}$ ion on its own. It receives ${\mathrm{OH}}^{-}$ ion from water and releases ${\mathrm{H}}^{+}$ ion.

In the light of the above statements, choose the most appropriate answer from the options given below.

Borazine, also known as inorganic benzene, can be prepared by the reaction of $3$-equivalents of "$\mathrm{X}$" with $6$-equivalents of "$\mathrm{Y}$". "$\mathrm{X}$" and "$\mathrm{Y}$", respectively are

The geometry around boron in the product '$\mathrm{B}$' formed from the following reaction is

${\mathrm{BF}}_3+\mathrm{NaH}\stackrel{450 \mathrm{K}}{⟶}\mathrm{A}+\mathrm{NaF}$

$\mathrm{A}+{\mathrm{NMe}}_3\to \mathrm{B}$

Aqueous solution of which of the following boron compounds will be strongly basic in nature?

Identify the correct statement for ${\mathrm{B}}_2{\mathrm{H}}_6$ from those given below.

(A) In ${\mathrm{B}}_2{\mathrm{H}}_6$, all $\mathrm{B}-\mathrm{H}$ bonds are equivalent.

(B) In ${\mathrm{B}}_2{\mathrm{H}}_6$, there are four $3$-centre- $2$-electron bonds.

(C) ${\mathrm{B}}_2{\mathrm{H}}_6$ is a Lewis acid.

(D) ${\mathrm{B}}_2{\mathrm{H}}_6$ can be synthesized from both ${\mathrm{BF}}_3$ and ${\mathrm{NaBH}}_4$.

(E) ${\mathrm{B}}_2{\mathrm{H}}_6$ is a planar molecule.

Choose the most appropriate answer from the options given below :

In which one of the following molecules strongest back donation of an electron pair from halide to boron is expected?

Given below are the statements about diborane
(a) Diborane is prepared by the oxidation of ${\mathrm{NaBH}}_4$ with ${\mathrm{I}}_2$
(b) Each boron atom is in ${\mathrm{sp}}^2$ hybridized state
(c) Diborane has one bridged $3$ centre-$2$-electron bond
(d) Diborane is a planar molecule

The option with correct statement(s) is 

The set in which compounds have different nature is:

The incorrect statement about ${\mathrm{B}}_2{\mathrm{H}}_6$ is :

Given below are two statements:
Statement $\mathrm{I}:$ Colourless cupric metaborate is reduced to cuprous metaborate in a luminous flame.

Statement $\mathrm{II}:$ Cuprous metaborate is obtained by heating boric anhydride and copper sulphate in a non-luminous flame.

In the light of the above statements, choose the most appropriate answer from the options given below.

The reaction of ${\mathrm{H}}_3{\mathrm{N}}_3{\mathrm{B}}_3\mathrm{C}{\mathrm{l}}_3\left(\mathrm{A}\right)$ with $\mathrm{L}\mathrm{i}\mathrm{B}{\mathrm{H}}_4$ in tetrahydrofuran gives inorganic benzene $\left(\mathrm{B}\right)$ . Further, the reaction of $\left(\mathrm{A}\right)$ with $\left(\mathrm{C}\right)$ leads to ${\mathrm{H}}_3{\mathrm{N}}_3{\mathrm{B}}_3{\left(\mathrm{M}\mathrm{e}\right)}_3$ . Compounds $\left(\mathrm{B}\right)$ and $\left(\mathrm{C}\right)$ respectively, are:

Diborane $\left({\mathrm{B}}_2{\mathrm{H}}_6\right)$ reacts independently with ${\mathrm{O}}_2$ and ${\mathrm{H}}_2\mathrm{O}$ to produce, respectively:

The number of $2$-centre-$2$-electron and $3$-centre-$2$-electron bonds in ${\mathrm{B}}_2{\mathrm{H}}_6$, respectively, are:

Identify the reaction which does not liberate hydrogen