EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 25 - Limits>BITSAT 2017

Embibe Experts Solutions for Chapter: Limits, Exercise 1: BITSAT 2017

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Embibe Experts Mathematics Solutions for Exercise - Embibe Experts Solutions for Chapter: Limits, Exercise 1: BITSAT 2017

Attempt the free practice questions on Chapter 25: Limits, Exercise 1: BITSAT 2017 with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Limits, Exercise 1: BITSAT 2017 with Hints & Solutions

MEDIUM

BITSAT

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 25 - Limits>BITSAT 2019>Q 1

The value of $\lim_{x \to \frac{3 π}{4}} \frac{4 \sin^{2} x \cos x - \cos x + \sin x}{\sin x + \cos x}$ is

EASY

BITSAT

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 25 - Limits>BITSAT 2018>Q 2

The value of $a$ , so that $\lim_{x \to 0} \frac{1}{x^{2}} (e^{a x} - e^{x} - x) = \frac{3}{2}$ , is

MEDIUM

BITSAT

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 25 - Limits>BITSAT 2017>Q 3

$\lim_{n \to \infty} \sin [π \sqrt{n^{2} + 1}]$ is equal to

MEDIUM

BITSAT

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR MATHEMATICS>Chapter 25 - Limits>BITSAT 2017>Q 4

If $\lim_{n \to \infty} (a n - \frac{1 + n^{2}}{1 + n}) = b$ , where $a$ is finite number, then