Establish Einstein's relation 1 2 mu 2 = hv - hv 0 with respect to photoelectric emission.

The phenomenon of emission of electrons from a metal surface, when electromagnetic radiations of sufficiently high frequency are incident on it, is called the photoelectric effect. Einstein explained the photoelectric effect based on Planck's quantum theory according to which light radiation travels in the form of discrete photons. The energy of each photon is hv , where h is Planck's constant and v is the frequency of light. The main points of Einstein’s theory of the photoelectric effect are: The interaction between two particles results in photoelectric emission– one a photon of incident radiation and the other an electron of photosensitive metal. The free electrons are bound within the metal due to restraining forces on the surface. The minimum energy required to liberate an electron from the metal surface is called the work function W 0 of the metal. Each photon interacts with one electron. The energy hv of the incident photon is used up in two parts: A part of the energy of the photon is used in liberating the electron from the metal surface, which is equal to the work function W 0 of the metal, and The remaining energy of the photon is used in impairing kinetic energy to the ejected electron. Very few < 1 0 0 photons, whose energies are greater than W 0 , capable of ejecting the photons. By law of the conservation of energy, Energy of the incident photon = Maximum K . E . of photon + Work function hv = 1 2 mv 2 max + W 0 ∴ K max = 1 2 mv 2 max = hv - W 0 . . . . . . . ( 1 ) If the incident photon is threshold frequency v 0 , then its energy hv 0 is just sufficient to free the electron from the metal surface and does not give it any kinetic energy. So hv 0 = W 0 . Hence K max = 1 2 mv 2 max = hv - hv 0 = h v - v 0 . . . . . . ( 2 ) Equations (1) and (2) are called Einstein’s photoelectric equations.A

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 11 - Dual Nature of Radiation and Matter>Madhya Pradesh Board-2019

Embibe Experts Solutions for Chapter: Dual Nature of Radiation and Matter, Exercise 1: Madhya Pradesh Board-2018

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Dual Nature of Radiation and Matter, Exercise 1: Madhya Pradesh Board-2018

Attempt the free practice questions on Chapter 11: Dual Nature of Radiation and Matter, Exercise 1: Madhya Pradesh Board-2018 with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Dual Nature of Radiation and Matter, Exercise 1: Madhya Pradesh Board-2018 with Hints & Solutions

EASY

12th Madhya Pradesh Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 11 - Dual Nature of Radiation and Matter>Madhya Pradesh Board-2018>Q 1

The concept of photon was first given by _____.

MEDIUM

12th Madhya Pradesh Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 11 - Dual Nature of Radiation and Matter>Madhya Pradesh Board-2018>Q 2

Establish Einstein's relation $\frac{1}{2} {mu}^{2} = hv - {hv}_{0}$ with respect to photoelectric emission.

EASY

12th Madhya Pradesh Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 11 - Dual Nature of Radiation and Matter>Madhya Pradesh Board-2018>Q 3

The work function of a metal is $0.1 eV$ . Calculate the threshold frequency for photoelectric emission.

EASY

12th Madhya Pradesh Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 11 - Dual Nature of Radiation and Matter>Madhya Pradesh Board-2019>Q 4

What is thermionic emission?

EASY

12th Madhya Pradesh Board

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 11 - Dual Nature of Radiation and Matter>Madhya Pradesh Board-2019>Q 5

Monochromatic light of frequency $6.0 \times 10^{14}$ Hertz is produced by a laser. What is the energy of a photon in the light beam? $(h = 6.63 \times 10^{- 34} JS)$