Embibe Experts Solutions for Chapter: Electrostatics, Exercise 1: BITSAT 2017

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Electrostatics, Exercise 1: BITSAT 2017

Attempt the free practice questions on Chapter 12: Electrostatics, Exercise 1: BITSAT 2017 with hints and solutions to strengthen your understanding. EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Electrostatics, Exercise 1: BITSAT 2017 with Hints & Solutions

EASY
BITSAT
IMPORTANT

Two electrons are moving with equal speed of 5×105 m s-1 parallel to each other. The ratio of the electrostatic to the magnetic force between them is

MEDIUM
BITSAT
IMPORTANT

In the following figures, which figure represents the variation of the electric field with distance from the centre of a uniformly charged non-conducting spheres of radius R ?

EASY
BITSAT
IMPORTANT

A parallel plate capacitor C with plates of unit area and separation d is filled with a liquid of dielectric constant K=2, the level of liquid isd3,initially. Question Image
Suppose, the liquid level decreases at a constant speed v, the time constant as a function of time is

EASY
BITSAT
IMPORTANT

Two metal plates having a potential difference of 800 V are 2 cm apart. It is found that a particle of mass 1.96×10-15 kg remains suspended in the region between the plates. The charge on the particle must be (e= elementary charge)

MEDIUM
BITSAT
IMPORTANT

Three charges are placed at the three vertices of an equilateral triangle of side a as shown in the figure. The force experienced by the charge placed at the vertex A in a direction normal to BC is

Question Image

EASY
BITSAT
IMPORTANT

In the given circuit diagram,

E=5 V, r=1 Ω, R2=4 Ω, R1=R3=1 Ω and C=3 μF

Question Image

Then, what will be the numerical value of charge on each plates of the capacitor.

HARD
BITSAT
IMPORTANT

A parallel plate capacitor with air between the plates has a capacitance of 9 pF. The separation between the plates is d. The space between the plates is now filled with two dielectrics constant K1=3 and thickness d3 while the other one has dielectric constant K2=6 and thickness 2d3. Capacitance of the capacitor is now