Embibe Experts Solutions for Chapter: Electrostatics, Exercise 1: KCET (UG) 2018

The force of repulsion between two identical positive charges when kept, with a separation '$r$' in the air is ' $F$ '. Half the gap between the two charges is filled by a dielectric slab of dielectric constant $=4$. Then, the new force of repulsion between those two charges becomes

The magnitude of point charge due to which the electric field $30 \mathrm{cm}$ away has the magnitude $2 {\mathrm{NC}}^{-1}$ will be

A copper rod $AB$ of length $l$ is rotated about end $A$ with a constant angular velocity $\omega .$ The electric field at a distance $x$ from the axis of rotation is

Electric field due to infinite, straight uniformly charged wire varies with distance $r$ as

A $2$ gram object, located in a region of uniform electric field $\overrightarrow{E}=\left(300 \mathrm{N} {\mathrm{C}}^{-1}\right)\hat{\mathrm{i}}$ carries a charge $Q.$ The object released from rest at $x=0,$ has a kinetic energy of $0.12 \mathrm{J}$ at $x=0.5$ $\mathrm{m}$. Then $Q$ is

A mass of $1 \mathrm{kg}$ carrying a charge of  $2 \mathrm{C}$ is accelerated through a potential of $1 \mathrm{V}$. The velocity acquired by it is:

Which graph in the following diagram correctly represents the potential energy of a pair of nucleons as a function of their separation?

The work done to move a charge on an equipotential surface is