Force Between Two Parallel Current - Carrying Conductors

Author:Embibe Experts
JEE Main
IMPORTANT

Important Questions on Force Between Two Parallel Current - Carrying Conductors

EASY
IMPORTANT

A current carrying rectangular loop PQRS is made of uniform wire. The length PR=QS=5 cm and PQ=RS=100 cm. If ammeter current reading changes from I to 2I, the ratio of magnetic forces per unit length on the wire PQ due to wire RS in the two cases respectively fPQI:fPQ2I is:

Question Image

EASY
IMPORTANT

Two long straight wires P and Q carrying equal current 10 A each were kept parallel to each other at 5 cm distance. Magnitude of magnetic force experienced by 10 cm length of wire P is F1. If distance between wires is halved and currents on them are doubled, force F2 on 10 cm length of wire P will be:

MEDIUM
IMPORTANT

A wire X of length 50 cm carrying a current of 2 A is placed parallel to a long wire Y of length 5 m. The wire Y carries a current of 3 A. The distance between two wires is 5 cm and currents flow in the same direction. The force acting on the wire Y is :

Question Image​​​​​​​

EASY
IMPORTANT

Two parallel, long wires are kept 0.20 m apart in vacuum, each carrying current of x A in the same direction. If the force of attraction per meter of each wire is 2×10-6 N, then the value of x is approximately

MEDIUM
IMPORTANT

Two 10 cm long, straight wires, each carrying a current of 5 A are kept parallel to each other. If each wire experienced a force of 10-5 N, then separation between the wires is _____ cm.

EASY
IMPORTANT

A galvanometer is used in laboratory for detecting the null point in electrical experiments. If, on passing a current of 6mA it produces a deflection of 2°, its figure of merit is close to :

EASY
IMPORTANT

An electrical power line, having a total resistance of 2Ω, delivers 1 kW at 220 V. The efficiency of the transmission line is approximately :

MEDIUM
IMPORTANT

A galvanometer of resistance G is converted into a voltameter of range 0-1 V by connecting a resistance R in series with it. The additional resistance that should be connected in series with R1 to increase the range of the voltmeter to 0-2V will be :

MEDIUM
IMPORTANT

Two wires A &  B are carrying currents I1 and I2 as shown in the figure. The separation between them is  d . A third wire C carrying a current I is to be kept parallel to them at a distance x from A such that the net force acting on it is zero. The possible values of x are:
Question Image

MEDIUM
IMPORTANT

A rigid square loop of side a and carrying current I2 is lying on a horizontal surface near a long current I1 carrying wire in the same plane as shown in figure. The net force on the loop due to the wire will be:
Question Image

MEDIUM
IMPORTANT

Two long straight parallel wires, carrying (adjustable) currents I1 and I2 , are kept at a distance d apart. If the force F between the two wires is taken as 'positive' when the wires repel each other and 'negative' when the wires attract each other, the graph showing the dependence of F, on the product I1I2 , would be:

HARD
IMPORTANT

Question Image

Two long currents carrying thin wires, both with current I, are held by insulating threads of length L and are in equilibrium as shown in the figure, with threads making an angle ' θ ' with the vertical. If wires have a mass λ per unit length then the value of I is:
(g= gravitational acceleration)