Embibe Experts Solutions for Chapter: Dual Nature of Matter and Radiation, Exercise 2: Exercise - 2

The work function of a certain metal is $\frac{hc}{{\lambda }_0}$. When a monochromatic light of wavelength $\lambda <{\lambda }_0$ is incident such that the plate gains a total power $P$. If the efficiency of photoelectric emission is $\mathrm{\eta }\%$ and all the emitted photoelectrons are captured by a hollow conducting sphere of radius $R$ already charged to potential $V$, then neglecting any interaction between plate and the sphere, expression of potential of the sphere at time $t$ is,

$(\mathrm{e}=1.6\times {10}^{–19}\mathrm{C})$

Radiation pressure on any surface (for a given intensity): 

The radiation force experienced by body exposed to radiation of intensity $I$, assuming surface of body to be perfectly absorbing is :

Which one of the following statements is NOT true for de Broglie waves?

The photoelectric threshold wavelength of tungsten is $230\mathrm{nm}$. The energy of electrons ejected from its surface by ultraviolet light of wavelength $180\mathrm{nm}$ is

Radiation from a hydrogen discharge tube (energy of photons $\le 13.6 \mathrm{eV}$) goes through a filter which transmits only waves of wavelength greater than $4400 \stackrel{\circ }{\mathrm{A}}$ and is incident on a metal of work function $2.0 \mathrm{eV}$. If stopping potential is $n\times {10}^{–2} \mathrm{volts}$. Find the value of $‘n’$

Photoelectric effect supports particle nature of light because

Select the correct alternative(s):
When photons of energy $4.25 \mathrm{eV}$ strike the surface of a metal $\mathrm{A}$, the ejected photo electrons have maximum kinetic energy $T_{\mathrm{A}} \mathrm{eV}$ and de Broglie wave length ${\mathrm{\lambda }}_{\mathrm{A}}$. The maximum kinetic energy of photo electrons liberated from another metal $\mathrm{B}$ by photons of energy $4.70 \mathrm{eV}$ is $T_{\mathrm{B}} = (T_{\mathrm{A}} - 1.50) \mathrm{eV}$. If the de-Broglie wave length of these photo electrons is ${\mathrm{\lambda }}_{\mathrm{B}} = 2{\mathrm{\lambda }}_{\mathrm{A}}$, then: