Embibe Experts Solutions for Chapter: Kinetic Theory of Gases, Exercise 1: Exercise - 1

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Embibe Experts Physics Solutions for Exercise - Embibe Experts Solutions for Chapter: Kinetic Theory of Gases, Exercise 1: Exercise - 1

Attempt the free practice questions on Chapter 18: Kinetic Theory of Gases, Exercise 1: Exercise - 1 with hints and solutions to strengthen your understanding. Alpha Question Bank for Engineering: Physics solutions are prepared by Experienced Embibe Experts.

Questions from Embibe Experts Solutions for Chapter: Kinetic Theory of Gases, Exercise 1: Exercise - 1 with Hints & Solutions

EASY
JEE Main/Advance
IMPORTANT

The mean speed of the molecules of a hydrogen sample equals the mean speed of the molecules of a helium sample. Calculate the ratio of the temperature of the hydrogen sample to the temperature of the helium sample.

MEDIUM
JEE Main/Advance
IMPORTANT

0.04 g of He is kept in a closed container, initially at 100.0°C. The container is now heated. Neglecting the expansion of the container, calculate the temperature at which the internal energy is increased by 12 J.

HARD
JEE Main/Advance
IMPORTANT

For a gas sample with N0 number of molecules, the function NV is given by, NV=dNdV=3N0V03V2 for 0<V<V0 and NV=0 for V>V0. Where dN is a number of molecules in speed range V to V+dV. The rms speed of the molecules is

MEDIUM
JEE Main/Advance
IMPORTANT

A, B and C Are three closed vessels, at the same temperature T And contain gases which obey the Maxwellian distribution of velocities. Vessel A Contains only undefined and C A mixture of equal quantities of O2 And undefined. If the average speed of O2 Molecules in vessel A is v1, that of the undefined molecules in vessel B is v2, the average speed of the O2 Molecules in vessel C is

EASY
JEE Main/Advance
IMPORTANT

A certain gas is taken to the five states represented by dots in the graph. The plotted lines are isotherms. The order of the most probable speed vp of the molecules at these five states is,

Question Image

EASY
JEE Main/Advance
IMPORTANT

The pressure of an ideal gas is written as, E=3PV2. Here, E stands for,

EASY
JEE Main/Advance
IMPORTANT

The quantities which remain same for all ideal gases at the same temperature is/are,

HARD
JEE Main/Advance
IMPORTANT

One mole of an ideal gas undergoes a process in which, T=T0+aV3, where T0 and a are positive constants and V is volume. The minimum pressure attainable is,