Embibe Experts Solutions for Chapter: Classification of Elements and Periodicity in Properties, Exercise 5: Exercise 5

The elements which exhibit both vertical and horizontal similarities are:

A large difference between the third and fourth ionization energies indicates the presence of:

Arrange $\mathrm{F},\mathrm{C},\mathrm{N},\mathrm{O}$ in the decreasing order of electronegativity:

Among $\mathrm{O}, \mathrm{C}, \mathrm{F}, \mathrm{Cl}, \mathrm{Br}$ the correct order of increasing atomic radii is:

The values of $\mathrm{IE}\left(\mathrm{I}\right), \mathrm{IE}\left(\mathrm{II}\right), \mathrm{IE}\left(\mathrm{III}\right)$, and $\mathrm{IE}\left(\mathrm{IV}\right)$, of an atom are respectively, $7.5\mathrm{eV},25.6\mathrm{eV},48.6\mathrm{eV}$ and $170.6\mathrm{eV}$. The electronic configuration of the atom will be:

The first $\left({\mathrm{IE}}_1\right)$ and second $\left({\mathrm{IE}}_2\right)$ ionization energies ($\mathrm{kJ}/\mathrm{mol}$) of a few elements designated by Roman numerals are given below. Which of these would be an alkali metal?

In the formation of a chloride ion, from an isolated gaseous chlorine atom, $3.8\mathrm{eV}$ energy is released, which would be equal to:

lonisation potential of $\mathrm{Na}$ would be numerically the same as: